Integrand size = 55, antiderivative size = 31 \[ \int \frac {-4-6 x+7 x^2-x^3-x^4+2 x^5-x^6}{x^3+2 x^4-x^5-2 x^6+x^7} \, dx=\frac {2}{\left (1+\frac {2-x}{\frac {2}{x}-x}\right ) x^2}-\log (x) \]
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Time = 0.08 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.073, Rules used = {2099, 652, 632, 212} \[ \int \frac {-4-6 x+7 x^2-x^3-x^4+2 x^5-x^6}{x^3+2 x^4-x^5-2 x^6+x^7} \, dx=\frac {3-2 x}{-x^2+x+1}+\frac {2}{x^2}-\frac {2}{x}-\log (x) \]
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Rule 212
Rule 632
Rule 652
Rule 2099
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {4}{x^3}+\frac {2}{x^2}-\frac {1}{x}+\frac {-7+4 x}{\left (-1-x+x^2\right )^2}-\frac {2}{-1-x+x^2}\right ) \, dx \\ & = \frac {2}{x^2}-\frac {2}{x}-\log (x)-2 \int \frac {1}{-1-x+x^2} \, dx+\int \frac {-7+4 x}{\left (-1-x+x^2\right )^2} \, dx \\ & = \frac {2}{x^2}-\frac {2}{x}+\frac {3-2 x}{1+x-x^2}-\log (x)+2 \int \frac {1}{-1-x+x^2} \, dx+4 \text {Subst}\left (\int \frac {1}{5-x^2} \, dx,x,-1+2 x\right ) \\ & = \frac {2}{x^2}-\frac {2}{x}+\frac {3-2 x}{1+x-x^2}-\frac {4 \text {arctanh}\left (\frac {1-2 x}{\sqrt {5}}\right )}{\sqrt {5}}-\log (x)-4 \text {Subst}\left (\int \frac {1}{5-x^2} \, dx,x,-1+2 x\right ) \\ & = \frac {2}{x^2}-\frac {2}{x}+\frac {3-2 x}{1+x-x^2}-\log (x) \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.87 \[ \int \frac {-4-6 x+7 x^2-x^3-x^4+2 x^5-x^6}{x^3+2 x^4-x^5-2 x^6+x^7} \, dx=-\frac {2-x^2}{x^2 \left (-1-x+x^2\right )}-\log (x) \]
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Time = 0.09 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.81
method | result | size |
norman | \(\frac {x^{2}-2}{x^{2} \left (x^{2}-x -1\right )}-\ln \left (x \right )\) | \(25\) |
risch | \(\frac {x^{2}-2}{x^{2} \left (x^{2}-x -1\right )}-\ln \left (x \right )\) | \(25\) |
default | \(\frac {2}{x^{2}}-\frac {2}{x}-\ln \left (x \right )-\frac {3-2 x}{x^{2}-x -1}\) | \(33\) |
parallelrisch | \(-\frac {x^{4} \ln \left (x \right )+2-x^{3} \ln \left (x \right )-x^{2} \ln \left (x \right )-x^{2}}{x^{2} \left (x^{2}-x -1\right )}\) | \(43\) |
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Time = 0.24 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.29 \[ \int \frac {-4-6 x+7 x^2-x^3-x^4+2 x^5-x^6}{x^3+2 x^4-x^5-2 x^6+x^7} \, dx=\frac {x^{2} - {\left (x^{4} - x^{3} - x^{2}\right )} \log \left (x\right ) - 2}{x^{4} - x^{3} - x^{2}} \]
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Time = 0.07 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.61 \[ \int \frac {-4-6 x+7 x^2-x^3-x^4+2 x^5-x^6}{x^3+2 x^4-x^5-2 x^6+x^7} \, dx=- \frac {2 - x^{2}}{x^{4} - x^{3} - x^{2}} - \log {\left (x \right )} \]
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Time = 0.21 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.87 \[ \int \frac {-4-6 x+7 x^2-x^3-x^4+2 x^5-x^6}{x^3+2 x^4-x^5-2 x^6+x^7} \, dx=\frac {x^{2} - 2}{x^{4} - x^{3} - x^{2}} - \log \left (x\right ) \]
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Time = 0.26 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.81 \[ \int \frac {-4-6 x+7 x^2-x^3-x^4+2 x^5-x^6}{x^3+2 x^4-x^5-2 x^6+x^7} \, dx=\frac {x^{2} - 2}{{\left (x^{2} - x - 1\right )} x^{2}} - \log \left ({\left | x \right |}\right ) \]
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Time = 0.07 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.81 \[ \int \frac {-4-6 x+7 x^2-x^3-x^4+2 x^5-x^6}{x^3+2 x^4-x^5-2 x^6+x^7} \, dx=-\ln \left (x\right )-\frac {x^2-2}{x^2\,\left (-x^2+x+1\right )} \]
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