Integrand size = 100, antiderivative size = 25 \[ \int \frac {-6 x+9 x^2+e^{x^2} \left (3-3 x+9 x^2-12 x^3-6 x^4\right )+\left (-3 x^2+6 e^{x^2} x^3\right ) \log (x)}{1-4 x+2 x^2+4 x^3+x^4+\left (2 x-4 x^2-2 x^3\right ) \log (x)+x^2 \log ^2(x)} \, dx=\frac {3 \left (-e^{x^2}+x\right )}{2-\frac {1}{x}+x-\log (x)} \]
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\[ \int \frac {-6 x+9 x^2+e^{x^2} \left (3-3 x+9 x^2-12 x^3-6 x^4\right )+\left (-3 x^2+6 e^{x^2} x^3\right ) \log (x)}{1-4 x+2 x^2+4 x^3+x^4+\left (2 x-4 x^2-2 x^3\right ) \log (x)+x^2 \log ^2(x)} \, dx=\int \frac {-6 x+9 x^2+e^{x^2} \left (3-3 x+9 x^2-12 x^3-6 x^4\right )+\left (-3 x^2+6 e^{x^2} x^3\right ) \log (x)}{1-4 x+2 x^2+4 x^3+x^4+\left (2 x-4 x^2-2 x^3\right ) \log (x)+x^2 \log ^2(x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {3 \left (-((2-3 x) x)-e^{x^2} \left (-1+x-3 x^2+4 x^3+2 x^4\right )-\left (x^2-2 e^{x^2} x^3\right ) \log (x)\right )}{\left (1-2 x-x^2+x \log (x)\right )^2} \, dx \\ & = 3 \int \frac {-((2-3 x) x)-e^{x^2} \left (-1+x-3 x^2+4 x^3+2 x^4\right )-\left (x^2-2 e^{x^2} x^3\right ) \log (x)}{\left (1-2 x-x^2+x \log (x)\right )^2} \, dx \\ & = 3 \int \left (-\frac {x (2-3 x+x \log (x))}{\left (-1+2 x+x^2-x \log (x)\right )^2}-\frac {e^{x^2} \left (-1+x-3 x^2+4 x^3+2 x^4-2 x^3 \log (x)\right )}{\left (-1+2 x+x^2-x \log (x)\right )^2}\right ) \, dx \\ & = -\left (3 \int \frac {x (2-3 x+x \log (x))}{\left (-1+2 x+x^2-x \log (x)\right )^2} \, dx\right )-3 \int \frac {e^{x^2} \left (-1+x-3 x^2+4 x^3+2 x^4-2 x^3 \log (x)\right )}{\left (-1+2 x+x^2-x \log (x)\right )^2} \, dx \\ & = -\left (3 \int \left (\frac {x \left (1-x+x^2\right )}{\left (-1+2 x+x^2-x \log (x)\right )^2}-\frac {x}{-1+2 x+x^2-x \log (x)}\right ) \, dx\right )-3 \int \left (\frac {e^{x^2} \left (-1+x-x^2\right )}{\left (-1+2 x+x^2-x \log (x)\right )^2}+\frac {2 e^{x^2} x^2}{-1+2 x+x^2-x \log (x)}\right ) \, dx \\ & = -\left (3 \int \frac {e^{x^2} \left (-1+x-x^2\right )}{\left (-1+2 x+x^2-x \log (x)\right )^2} \, dx\right )-3 \int \frac {x \left (1-x+x^2\right )}{\left (-1+2 x+x^2-x \log (x)\right )^2} \, dx+3 \int \frac {x}{-1+2 x+x^2-x \log (x)} \, dx-6 \int \frac {e^{x^2} x^2}{-1+2 x+x^2-x \log (x)} \, dx \\ & = 3 \int \frac {x}{-1+2 x+x^2-x \log (x)} \, dx-3 \int \left (-\frac {e^{x^2}}{\left (-1+2 x+x^2-x \log (x)\right )^2}+\frac {e^{x^2} x}{\left (-1+2 x+x^2-x \log (x)\right )^2}-\frac {e^{x^2} x^2}{\left (-1+2 x+x^2-x \log (x)\right )^2}\right ) \, dx-3 \int \left (\frac {x}{\left (-1+2 x+x^2-x \log (x)\right )^2}-\frac {x^2}{\left (-1+2 x+x^2-x \log (x)\right )^2}+\frac {x^3}{\left (-1+2 x+x^2-x \log (x)\right )^2}\right ) \, dx-6 \int \frac {e^{x^2} x^2}{-1+2 x+x^2-x \log (x)} \, dx \\ & = 3 \int \frac {e^{x^2}}{\left (-1+2 x+x^2-x \log (x)\right )^2} \, dx-3 \int \frac {x}{\left (-1+2 x+x^2-x \log (x)\right )^2} \, dx-3 \int \frac {e^{x^2} x}{\left (-1+2 x+x^2-x \log (x)\right )^2} \, dx+3 \int \frac {x^2}{\left (-1+2 x+x^2-x \log (x)\right )^2} \, dx+3 \int \frac {e^{x^2} x^2}{\left (-1+2 x+x^2-x \log (x)\right )^2} \, dx-3 \int \frac {x^3}{\left (-1+2 x+x^2-x \log (x)\right )^2} \, dx+3 \int \frac {x}{-1+2 x+x^2-x \log (x)} \, dx-6 \int \frac {e^{x^2} x^2}{-1+2 x+x^2-x \log (x)} \, dx \\ \end{align*}
Time = 0.38 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {-6 x+9 x^2+e^{x^2} \left (3-3 x+9 x^2-12 x^3-6 x^4\right )+\left (-3 x^2+6 e^{x^2} x^3\right ) \log (x)}{1-4 x+2 x^2+4 x^3+x^4+\left (2 x-4 x^2-2 x^3\right ) \log (x)+x^2 \log ^2(x)} \, dx=\frac {3 \left (e^{x^2}-x\right ) x}{1-2 x-x^2+x \log (x)} \]
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Time = 11.26 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.08
method | result | size |
risch | \(\frac {3 \left (-{\mathrm e}^{x^{2}}+x \right ) x}{x^{2}-x \ln \left (x \right )+2 x -1}\) | \(27\) |
parallelrisch | \(\frac {3 x^{2}-3 \,{\mathrm e}^{x^{2}} x}{x^{2}-x \ln \left (x \right )+2 x -1}\) | \(30\) |
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Time = 0.25 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {-6 x+9 x^2+e^{x^2} \left (3-3 x+9 x^2-12 x^3-6 x^4\right )+\left (-3 x^2+6 e^{x^2} x^3\right ) \log (x)}{1-4 x+2 x^2+4 x^3+x^4+\left (2 x-4 x^2-2 x^3\right ) \log (x)+x^2 \log ^2(x)} \, dx=\frac {3 \, {\left (x^{2} - x e^{\left (x^{2}\right )}\right )}}{x^{2} - x \log \left (x\right ) + 2 \, x - 1} \]
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Time = 0.13 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.64 \[ \int \frac {-6 x+9 x^2+e^{x^2} \left (3-3 x+9 x^2-12 x^3-6 x^4\right )+\left (-3 x^2+6 e^{x^2} x^3\right ) \log (x)}{1-4 x+2 x^2+4 x^3+x^4+\left (2 x-4 x^2-2 x^3\right ) \log (x)+x^2 \log ^2(x)} \, dx=- \frac {3 x^{2}}{- x^{2} + x \log {\left (x \right )} - 2 x + 1} - \frac {3 x e^{x^{2}}}{x^{2} - x \log {\left (x \right )} + 2 x - 1} \]
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Time = 0.25 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {-6 x+9 x^2+e^{x^2} \left (3-3 x+9 x^2-12 x^3-6 x^4\right )+\left (-3 x^2+6 e^{x^2} x^3\right ) \log (x)}{1-4 x+2 x^2+4 x^3+x^4+\left (2 x-4 x^2-2 x^3\right ) \log (x)+x^2 \log ^2(x)} \, dx=\frac {3 \, {\left (x^{2} - x e^{\left (x^{2}\right )}\right )}}{x^{2} - x \log \left (x\right ) + 2 \, x - 1} \]
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Time = 0.29 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {-6 x+9 x^2+e^{x^2} \left (3-3 x+9 x^2-12 x^3-6 x^4\right )+\left (-3 x^2+6 e^{x^2} x^3\right ) \log (x)}{1-4 x+2 x^2+4 x^3+x^4+\left (2 x-4 x^2-2 x^3\right ) \log (x)+x^2 \log ^2(x)} \, dx=\frac {3 \, {\left (x^{2} - x e^{\left (x^{2}\right )}\right )}}{x^{2} - x \log \left (x\right ) + 2 \, x - 1} \]
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Time = 12.48 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.04 \[ \int \frac {-6 x+9 x^2+e^{x^2} \left (3-3 x+9 x^2-12 x^3-6 x^4\right )+\left (-3 x^2+6 e^{x^2} x^3\right ) \log (x)}{1-4 x+2 x^2+4 x^3+x^4+\left (2 x-4 x^2-2 x^3\right ) \log (x)+x^2 \log ^2(x)} \, dx=\frac {3\,x\,\left (x-{\mathrm {e}}^{x^2}\right )}{2\,x-x\,\ln \left (x\right )+x^2-1} \]
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