Integrand size = 13, antiderivative size = 17 \[ \int \frac {-768-30 x-12 \log (4)}{x^3} \, dx=2+\frac {6 \left (5+\frac {64+\log (4)}{x}\right )}{x} \]
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Time = 0.00 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.47, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {37} \[ \int \frac {-768-30 x-12 \log (4)}{x^3} \, dx=\frac {3 (5 x+2 (64+\log (4)))^2}{2 x^2 (64+\log (4))} \]
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Rule 37
Rubi steps \begin{align*} \text {integral}& = \frac {3 (5 x+2 (64+\log (4)))^2}{2 x^2 (64+\log (4))} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.71 \[ \int \frac {-768-30 x-12 \log (4)}{x^3} \, dx=\frac {3 (128+10 x+\log (16))}{x^2} \]
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Time = 0.11 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.82
method | result | size |
norman | \(\frac {30 x +12 \ln \left (2\right )+384}{x^{2}}\) | \(14\) |
risch | \(\frac {30 x +12 \ln \left (2\right )+384}{x^{2}}\) | \(14\) |
parallelrisch | \(\frac {30 x +12 \ln \left (2\right )+384}{x^{2}}\) | \(14\) |
gosper | \(\frac {30 x +12 \ln \left (2\right )+384}{x^{2}}\) | \(15\) |
default | \(\frac {30}{x}-\frac {3 \left (-4 \ln \left (2\right )-128\right )}{x^{2}}\) | \(18\) |
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none
Time = 0.27 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.82 \[ \int \frac {-768-30 x-12 \log (4)}{x^3} \, dx=\frac {6 \, {\left (5 \, x + 2 \, \log \left (2\right ) + 64\right )}}{x^{2}} \]
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Time = 0.07 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int \frac {-768-30 x-12 \log (4)}{x^3} \, dx=- \frac {- 30 x - 384 - 12 \log {\left (2 \right )}}{x^{2}} \]
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none
Time = 0.20 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.82 \[ \int \frac {-768-30 x-12 \log (4)}{x^3} \, dx=\frac {6 \, {\left (5 \, x + 2 \, \log \left (2\right ) + 64\right )}}{x^{2}} \]
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none
Time = 0.26 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.82 \[ \int \frac {-768-30 x-12 \log (4)}{x^3} \, dx=\frac {6 \, {\left (5 \, x + 2 \, \log \left (2\right ) + 64\right )}}{x^{2}} \]
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Time = 0.04 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.76 \[ \int \frac {-768-30 x-12 \log (4)}{x^3} \, dx=\frac {30\,x+12\,\ln \left (2\right )+384}{x^2} \]
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