Integrand size = 14, antiderivative size = 13 \[ \int \frac {3+3 x+2 x^2}{x} \, dx=x^2+3 (-2+x+\log (2 x)) \]
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Time = 0.00 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.85, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {14} \[ \int \frac {3+3 x+2 x^2}{x} \, dx=x^2+3 x+3 \log (x) \]
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Rule 14
Rubi steps \begin{align*} \text {integral}& = \int \left (3+\frac {3}{x}+2 x\right ) \, dx \\ & = 3 x+x^2+3 \log (x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.85 \[ \int \frac {3+3 x+2 x^2}{x} \, dx=3 x+x^2+3 \log (x) \]
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Time = 0.11 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.92
method | result | size |
default | \(3 x +x^{2}+3 \ln \left (x \right )\) | \(12\) |
norman | \(3 x +x^{2}+3 \ln \left (x \right )\) | \(12\) |
risch | \(3 x +x^{2}+3 \ln \left (x \right )\) | \(12\) |
parallelrisch | \(3 x +x^{2}+3 \ln \left (x \right )\) | \(12\) |
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none
Time = 0.23 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.85 \[ \int \frac {3+3 x+2 x^2}{x} \, dx=x^{2} + 3 \, x + 3 \, \log \left (x\right ) \]
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Time = 0.03 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.77 \[ \int \frac {3+3 x+2 x^2}{x} \, dx=x^{2} + 3 x + 3 \log {\left (x \right )} \]
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none
Time = 0.21 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.85 \[ \int \frac {3+3 x+2 x^2}{x} \, dx=x^{2} + 3 \, x + 3 \, \log \left (x\right ) \]
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none
Time = 0.26 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.92 \[ \int \frac {3+3 x+2 x^2}{x} \, dx=x^{2} + 3 \, x + 3 \, \log \left ({\left | x \right |}\right ) \]
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Time = 13.96 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.85 \[ \int \frac {3+3 x+2 x^2}{x} \, dx=3\,x+3\,\ln \left (x\right )+x^2 \]
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