Integrand size = 43, antiderivative size = 17 \[ \int e^{-1+e^{4 x} x^2} x^4 \left (8 x^3+e^{4 x} x^2 \left (2 x^3+4 x^4\right )\right ) \, dx=e^{-1+e^{4 x} x^2} x^8 \]
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Leaf count is larger than twice the leaf count of optimal. \(49\) vs. \(2(17)=34\).
Time = 0.05 (sec) , antiderivative size = 49, normalized size of antiderivative = 2.88, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.023, Rules used = {2326} \[ \int e^{-1+e^{4 x} x^2} x^4 \left (8 x^3+e^{4 x} x^2 \left (2 x^3+4 x^4\right )\right ) \, dx=\frac {e^{e^{4 x} x^2+4 x-1} x^6 \left (2 x^4+x^3\right )}{2 e^{4 x} x^2+e^{4 x} x} \]
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Rule 2326
Rubi steps \begin{align*} \text {integral}& = \frac {e^{-1+4 x+e^{4 x} x^2} x^6 \left (x^3+2 x^4\right )}{e^{4 x} x+2 e^{4 x} x^2} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00 \[ \int e^{-1+e^{4 x} x^2} x^4 \left (8 x^3+e^{4 x} x^2 \left (2 x^3+4 x^4\right )\right ) \, dx=e^{-1+e^{4 x} x^2} x^8 \]
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Time = 30.65 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.65
method | result | size |
parallelrisch | \(x^{8} {\mathrm e}^{x^{2} {\mathrm e}^{4 x}-1}\) | \(28\) |
risch | \(x^{8} {\mathrm e}^{x^{2} {\mathrm e}^{4 x} {\mathrm e}^{-\frac {i \pi \operatorname {csgn}\left (i {\mathrm e}^{2 x}\right )^{3}}{2}} {\mathrm e}^{-\frac {i \pi \,\operatorname {csgn}\left (i {\mathrm e}^{2 x}\right ) \operatorname {csgn}\left (i {\mathrm e}^{x}\right )^{2}}{2}} {\mathrm e}^{-\frac {i \pi \operatorname {csgn}\left (i x^{2}\right )^{3}}{2}} {\mathrm e}^{-\frac {i \pi \operatorname {csgn}\left (i x \right )^{2} \operatorname {csgn}\left (i x^{2}\right )}{2}} {\mathrm e}^{-\frac {i \pi \,\operatorname {csgn}\left (i {\mathrm e}^{2 x}\right ) \operatorname {csgn}\left (i x^{2}\right ) \operatorname {csgn}\left (i x^{2} {\mathrm e}^{2 x}\right )}{2}} {\mathrm e}^{\frac {i \pi \,\operatorname {csgn}\left (i {\mathrm e}^{2 x}\right ) \operatorname {csgn}\left (i x^{2} {\mathrm e}^{2 x}\right )^{2}}{2}} {\mathrm e}^{\frac {i \pi \,\operatorname {csgn}\left (i x^{2}\right ) \operatorname {csgn}\left (i x^{2} {\mathrm e}^{2 x}\right )^{2}}{2}} {\mathrm e}^{-\frac {i \pi \operatorname {csgn}\left (i x^{2} {\mathrm e}^{2 x}\right )^{3}}{2}}-1}\) | \(185\) |
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none
Time = 0.26 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.18 \[ \int e^{-1+e^{4 x} x^2} x^4 \left (8 x^3+e^{4 x} x^2 \left (2 x^3+4 x^4\right )\right ) \, dx=x^{4} e^{\left (e^{\left (4 \, x + 2 \, \log \left (x\right )\right )} + 4 \, \log \left (x\right ) - 1\right )} \]
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Time = 0.14 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.82 \[ \int e^{-1+e^{4 x} x^2} x^4 \left (8 x^3+e^{4 x} x^2 \left (2 x^3+4 x^4\right )\right ) \, dx=x^{8} e^{x^{2} e^{4 x} - 1} \]
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none
Time = 0.27 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int e^{-1+e^{4 x} x^2} x^4 \left (8 x^3+e^{4 x} x^2 \left (2 x^3+4 x^4\right )\right ) \, dx=x^{8} e^{\left (x^{2} e^{\left (4 \, x\right )} - 1\right )} \]
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\[ \int e^{-1+e^{4 x} x^2} x^4 \left (8 x^3+e^{4 x} x^2 \left (2 x^3+4 x^4\right )\right ) \, dx=\int { 2 \, {\left (4 \, x^{3} + {\left (2 \, x^{4} + x^{3}\right )} e^{\left (2 \, x + \log \left (x^{2} e^{\left (2 \, x\right )}\right )\right )}\right )} e^{\left (e^{\left (2 \, x + \log \left (x^{2} e^{\left (2 \, x\right )}\right )\right )} + 4 \, \log \left (x\right ) - 1\right )} \,d x } \]
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Time = 14.46 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.88 \[ \int e^{-1+e^{4 x} x^2} x^4 \left (8 x^3+e^{4 x} x^2 \left (2 x^3+4 x^4\right )\right ) \, dx=x^8\,{\mathrm {e}}^{-1}\,{\mathrm {e}}^{x^2\,{\mathrm {e}}^{4\,x}} \]
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