Integrand size = 69, antiderivative size = 23 \[ \int \frac {3208 x^2-11212 x^3+12006 x^4-5201 x^5+800 x^6+e^x \left (-2406+6015 x-6003 x^2+1200 x^3\right )}{-3200 x^2+4800 x^3-2400 x^4+400 x^5} \, dx=\left (-\frac {401}{400}+x\right ) \left (\frac {3 e^x}{(2-x)^2 x}+x\right ) \]
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Leaf count is larger than twice the leaf count of optimal. \(47\) vs. \(2(23)=46\).
Time = 0.28 (sec) , antiderivative size = 47, normalized size of antiderivative = 2.04, number of steps used = 14, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.072, Rules used = {6820, 12, 6874, 2208, 2209} \[ \int \frac {3208 x^2-11212 x^3+12006 x^4-5201 x^5+800 x^6+e^x \left (-2406+6015 x-6003 x^2+1200 x^3\right )}{-3200 x^2+4800 x^3-2400 x^4+400 x^5} \, dx=x^2-\frac {401 x}{400}-\frac {1203 e^x}{1600 (2-x)}+\frac {1197 e^x}{800 (2-x)^2}-\frac {1203 e^x}{1600 x} \]
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Rule 12
Rule 2208
Rule 2209
Rule 6820
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{400} \left (-401+800 x+\frac {3 e^x \left (-802+2005 x-2001 x^2+400 x^3\right )}{(-2+x)^3 x^2}\right ) \, dx \\ & = \frac {1}{400} \int \left (-401+800 x+\frac {3 e^x \left (-802+2005 x-2001 x^2+400 x^3\right )}{(-2+x)^3 x^2}\right ) \, dx \\ & = -\frac {401 x}{400}+x^2+\frac {3}{400} \int \frac {e^x \left (-802+2005 x-2001 x^2+400 x^3\right )}{(-2+x)^3 x^2} \, dx \\ & = -\frac {401 x}{400}+x^2+\frac {3}{400} \int \left (-\frac {399 e^x}{(-2+x)^3}+\frac {397 e^x}{4 (-2+x)^2}+\frac {401 e^x}{4 (-2+x)}+\frac {401 e^x}{4 x^2}-\frac {401 e^x}{4 x}\right ) \, dx \\ & = -\frac {401 x}{400}+x^2+\frac {1191 \int \frac {e^x}{(-2+x)^2} \, dx}{1600}+\frac {1203 \int \frac {e^x}{-2+x} \, dx}{1600}+\frac {1203 \int \frac {e^x}{x^2} \, dx}{1600}-\frac {1203 \int \frac {e^x}{x} \, dx}{1600}-\frac {1197}{400} \int \frac {e^x}{(-2+x)^3} \, dx \\ & = \frac {1197 e^x}{800 (2-x)^2}+\frac {1191 e^x}{1600 (2-x)}-\frac {1203 e^x}{1600 x}-\frac {401 x}{400}+x^2+\frac {1203 e^2 \operatorname {ExpIntegralEi}(-2+x)}{1600}-\frac {1203 \operatorname {ExpIntegralEi}(x)}{1600}+\frac {1191 \int \frac {e^x}{-2+x} \, dx}{1600}+\frac {1203 \int \frac {e^x}{x} \, dx}{1600}-\frac {1197}{800} \int \frac {e^x}{(-2+x)^2} \, dx \\ & = \frac {1197 e^x}{800 (2-x)^2}-\frac {1203 e^x}{1600 (2-x)}-\frac {1203 e^x}{1600 x}-\frac {401 x}{400}+x^2+\frac {1197}{800} e^2 \operatorname {ExpIntegralEi}(-2+x)-\frac {1197}{800} \int \frac {e^x}{-2+x} \, dx \\ & = \frac {1197 e^x}{800 (2-x)^2}-\frac {1203 e^x}{1600 (2-x)}-\frac {1203 e^x}{1600 x}-\frac {401 x}{400}+x^2 \\ \end{align*}
Time = 0.36 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.91 \[ \int \frac {3208 x^2-11212 x^3+12006 x^4-5201 x^5+800 x^6+e^x \left (-2406+6015 x-6003 x^2+1200 x^3\right )}{-3200 x^2+4800 x^3-2400 x^4+400 x^5} \, dx=\frac {1}{400} \left (3 e^x \left (\frac {399}{2 (-2+x)^2}+\frac {401}{4 (-2+x)}-\frac {401}{4 x}\right )-401 x+400 x^2\right ) \]
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Time = 0.10 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.09
method | result | size |
risch | \(x^{2}-\frac {401 x}{400}+\frac {3 \left (400 x -401\right ) {\mathrm e}^{x}}{400 x \left (-2+x \right )^{2}}\) | \(25\) |
default | \(x^{2}-\frac {401 x}{400}+\frac {1203 \,{\mathrm e}^{x}}{1600 \left (-2+x \right )}+\frac {1197 \,{\mathrm e}^{x}}{800 \left (-2+x \right )^{2}}-\frac {1203 \,{\mathrm e}^{x}}{1600 x}\) | \(33\) |
parts | \(x^{2}-\frac {401 x}{400}+\frac {1203 \,{\mathrm e}^{x}}{1600 \left (-2+x \right )}+\frac {1197 \,{\mathrm e}^{x}}{800 \left (-2+x \right )^{2}}-\frac {1203 \,{\mathrm e}^{x}}{1600 x}\) | \(33\) |
norman | \(\frac {x^{5}-\frac {801 x}{25}+\frac {2803 x^{2}}{100}-\frac {2001 x^{4}}{400}+3 \,{\mathrm e}^{x} x -\frac {1203 \,{\mathrm e}^{x}}{400}}{x \left (-2+x \right )^{2}}\) | \(36\) |
parallelrisch | \(\frac {400 x^{5}-2001 x^{4}+11212 x^{2}+1200 \,{\mathrm e}^{x} x -12816 x -1203 \,{\mathrm e}^{x}}{400 x \left (x^{2}-4 x +4\right )}\) | \(44\) |
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Leaf count of result is larger than twice the leaf count of optimal. 46 vs. \(2 (21) = 42\).
Time = 0.26 (sec) , antiderivative size = 46, normalized size of antiderivative = 2.00 \[ \int \frac {3208 x^2-11212 x^3+12006 x^4-5201 x^5+800 x^6+e^x \left (-2406+6015 x-6003 x^2+1200 x^3\right )}{-3200 x^2+4800 x^3-2400 x^4+400 x^5} \, dx=\frac {400 \, x^{5} - 2001 \, x^{4} + 3204 \, x^{3} - 1604 \, x^{2} + 3 \, {\left (400 \, x - 401\right )} e^{x}}{400 \, {\left (x^{3} - 4 \, x^{2} + 4 \, x\right )}} \]
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Time = 0.10 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.26 \[ \int \frac {3208 x^2-11212 x^3+12006 x^4-5201 x^5+800 x^6+e^x \left (-2406+6015 x-6003 x^2+1200 x^3\right )}{-3200 x^2+4800 x^3-2400 x^4+400 x^5} \, dx=x^{2} - \frac {401 x}{400} + \frac {\left (1200 x - 1203\right ) e^{x}}{400 x^{3} - 1600 x^{2} + 1600 x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 108 vs. \(2 (21) = 42\).
Time = 0.26 (sec) , antiderivative size = 108, normalized size of antiderivative = 4.70 \[ \int \frac {3208 x^2-11212 x^3+12006 x^4-5201 x^5+800 x^6+e^x \left (-2406+6015 x-6003 x^2+1200 x^3\right )}{-3200 x^2+4800 x^3-2400 x^4+400 x^5} \, dx=x^{2} - \frac {401}{400} \, x + \frac {3 \, {\left (400 \, x - 401\right )} e^{x}}{400 \, {\left (x^{3} - 4 \, x^{2} + 4 \, x\right )}} - \frac {16 \, {\left (4 \, x - 7\right )}}{x^{2} - 4 \, x + 4} + \frac {5201 \, {\left (3 \, x - 5\right )}}{100 \, {\left (x^{2} - 4 \, x + 4\right )}} - \frac {6003 \, {\left (2 \, x - 3\right )}}{100 \, {\left (x^{2} - 4 \, x + 4\right )}} + \frac {2803 \, {\left (x - 1\right )}}{100 \, {\left (x^{2} - 4 \, x + 4\right )}} - \frac {401}{100 \, {\left (x^{2} - 4 \, x + 4\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 46 vs. \(2 (21) = 42\).
Time = 0.27 (sec) , antiderivative size = 46, normalized size of antiderivative = 2.00 \[ \int \frac {3208 x^2-11212 x^3+12006 x^4-5201 x^5+800 x^6+e^x \left (-2406+6015 x-6003 x^2+1200 x^3\right )}{-3200 x^2+4800 x^3-2400 x^4+400 x^5} \, dx=\frac {400 \, x^{5} - 2001 \, x^{4} + 3204 \, x^{3} - 1604 \, x^{2} + 1200 \, x e^{x} - 1203 \, e^{x}}{400 \, {\left (x^{3} - 4 \, x^{2} + 4 \, x\right )}} \]
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Time = 0.21 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.43 \[ \int \frac {3208 x^2-11212 x^3+12006 x^4-5201 x^5+800 x^6+e^x \left (-2406+6015 x-6003 x^2+1200 x^3\right )}{-3200 x^2+4800 x^3-2400 x^4+400 x^5} \, dx=\frac {\left (400\,x-401\right )\,\left (3\,{\mathrm {e}}^x+4\,x^2-4\,x^3+x^4\right )}{400\,x\,{\left (x-2\right )}^2} \]
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