Integrand size = 15, antiderivative size = 17 \[ \int \left (-3-10 x-6 x^2-4 x^3\right ) \, dx=-e^{17}+x-\left (2+x+x^2\right )^2 \]
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Time = 0.00 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.12, number of steps used = 1, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \left (-3-10 x-6 x^2-4 x^3\right ) \, dx=-x^4-2 x^3-5 x^2-3 x \]
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Rubi steps \begin{align*} \text {integral}& = -3 x-5 x^2-2 x^3-x^4 \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.12 \[ \int \left (-3-10 x-6 x^2-4 x^3\right ) \, dx=-3 x-5 x^2-2 x^3-x^4 \]
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Time = 0.09 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00
method | result | size |
gosper | \(-x \left (x^{3}+2 x^{2}+5 x +3\right )\) | \(17\) |
default | \(-x^{4}-2 x^{3}-5 x^{2}-3 x\) | \(20\) |
norman | \(-x^{4}-2 x^{3}-5 x^{2}-3 x\) | \(20\) |
risch | \(-x^{4}-2 x^{3}-5 x^{2}-3 x\) | \(20\) |
parallelrisch | \(-x^{4}-2 x^{3}-5 x^{2}-3 x\) | \(20\) |
parts | \(-x^{4}-2 x^{3}-5 x^{2}-3 x\) | \(20\) |
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none
Time = 0.24 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.12 \[ \int \left (-3-10 x-6 x^2-4 x^3\right ) \, dx=-x^{4} - 2 \, x^{3} - 5 \, x^{2} - 3 \, x \]
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Time = 0.04 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00 \[ \int \left (-3-10 x-6 x^2-4 x^3\right ) \, dx=- x^{4} - 2 x^{3} - 5 x^{2} - 3 x \]
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none
Time = 0.22 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.12 \[ \int \left (-3-10 x-6 x^2-4 x^3\right ) \, dx=-x^{4} - 2 \, x^{3} - 5 \, x^{2} - 3 \, x \]
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none
Time = 0.26 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.12 \[ \int \left (-3-10 x-6 x^2-4 x^3\right ) \, dx=-x^{4} - 2 \, x^{3} - 5 \, x^{2} - 3 \, x \]
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Time = 0.03 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.12 \[ \int \left (-3-10 x-6 x^2-4 x^3\right ) \, dx=-x^4-2\,x^3-5\,x^2-3\,x \]
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