\(\int \frac {e^{-e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \log (x)+(2-x) \log (x)} (-128+e^{3 x} (2-x)-32 x+24 x^2+10 x^3+x^4+e^{2 x} (-24+6 x+3 x^2)+e^x (96-18 x^2-3 x^3)+(64 x-e^{3 x} x+48 x^2+12 x^3+x^4+e^{2 x} (12 x+3 x^2)+e^x (-48 x-24 x^2-3 x^3)) \log (x)+e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} (64-e^{3 x}+48 x+12 x^2+x^3+e^{2 x} (12+3 x)+e^x (-48-24 x-3 x^2)+(-2 x+2 e^x x) \log (x)))}{-64 x+e^{3 x} x-48 x^2-12 x^3-x^4+e^{2 x} (-12 x-3 x^2)+e^x (48 x+24 x^2+3 x^3)} \, dx\) [859]

Optimal result

Integrand size = 310, antiderivative size = 21 \[ \int \frac {e^{-e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \log (x)+(2-x) \log (x)} \left (-128+e^{3 x} (2-x)-32 x+24 x^2+10 x^3+x^4+e^{2 x} \left (-24+6 x+3 x^2\right )+e^x \left (96-18 x^2-3 x^3\right )+\left (64 x-e^{3 x} x+48 x^2+12 x^3+x^4+e^{2 x} \left (12 x+3 x^2\right )+e^x \left (-48 x-24 x^2-3 x^3\right )\right ) \log (x)+e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \left (64-e^{3 x}+48 x+12 x^2+x^3+e^{2 x} (12+3 x)+e^x \left (-48-24 x-3 x^2\right )+\left (-2 x+2 e^x x\right ) \log (x)\right )\right )}{-64 x+e^{3 x} x-48 x^2-12 x^3-x^4+e^{2 x} \left (-12 x-3 x^2\right )+e^x \left (48 x+24 x^2+3 x^3\right )} \, dx=x^{2-e^{\frac {1}{\left (-4+e^x-x\right )^2}}-x} \]

[Out]

exp((2-exp(1/(exp(x)-4-x)^2)-x)*ln(x))

Rubi [F(-1)]

Timed out. \[ \int \frac {e^{-e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \log (x)+(2-x) \log (x)} \left (-128+e^{3 x} (2-x)-32 x+24 x^2+10 x^3+x^4+e^{2 x} \left (-24+6 x+3 x^2\right )+e^x \left (96-18 x^2-3 x^3\right )+\left (64 x-e^{3 x} x+48 x^2+12 x^3+x^4+e^{2 x} \left (12 x+3 x^2\right )+e^x \left (-48 x-24 x^2-3 x^3\right )\right ) \log (x)+e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \left (64-e^{3 x}+48 x+12 x^2+x^3+e^{2 x} (12+3 x)+e^x \left (-48-24 x-3 x^2\right )+\left (-2 x+2 e^x x\right ) \log (x)\right )\right )}{-64 x+e^{3 x} x-48 x^2-12 x^3-x^4+e^{2 x} \left (-12 x-3 x^2\right )+e^x \left (48 x+24 x^2+3 x^3\right )} \, dx=\text {\$Aborted} \]

[In]

Int[(E^(-(E^(16 + E^(2*x) + E^x*(-8 - 2*x) + 8*x + x^2)^(-1)*Log[x]) + (2 - x)*Log[x])*(-128 + E^(3*x)*(2 - x)
- 32*x + 24*x^2 + 10*x^3 + x^4 + E^(2*x)*(-24 + 6*x + 3*x^2) + E^x*(96 - 18*x^2 - 3*x^3) + (64*x - E^(3*x)*x
+ 48*x^2 + 12*x^3 + x^4 + E^(2*x)*(12*x + 3*x^2) + E^x*(-48*x - 24*x^2 - 3*x^3))*Log[x] + E^(16 + E^(2*x) + E^
x*(-8 - 2*x) + 8*x + x^2)^(-1)*(64 - E^(3*x) + 48*x + 12*x^2 + x^3 + E^(2*x)*(12 + 3*x) + E^x*(-48 - 24*x - 3*
x^2) + (-2*x + 2*E^x*x)*Log[x])))/(-64*x + E^(3*x)*x - 48*x^2 - 12*x^3 - x^4 + E^(2*x)*(-12*x - 3*x^2) + E^x*(
48*x + 24*x^2 + 3*x^3)),x]

[Out]

$Aborted

Rubi steps Aborted

Mathematica [A] (verified)

Time = 1.28 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.00 \[ \int \frac {e^{-e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \log (x)+(2-x) \log (x)} \left (-128+e^{3 x} (2-x)-32 x+24 x^2+10 x^3+x^4+e^{2 x} \left (-24+6 x+3 x^2\right )+e^x \left (96-18 x^2-3 x^3\right )+\left (64 x-e^{3 x} x+48 x^2+12 x^3+x^4+e^{2 x} \left (12 x+3 x^2\right )+e^x \left (-48 x-24 x^2-3 x^3\right )\right ) \log (x)+e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \left (64-e^{3 x}+48 x+12 x^2+x^3+e^{2 x} (12+3 x)+e^x \left (-48-24 x-3 x^2\right )+\left (-2 x+2 e^x x\right ) \log (x)\right )\right )}{-64 x+e^{3 x} x-48 x^2-12 x^3-x^4+e^{2 x} \left (-12 x-3 x^2\right )+e^x \left (48 x+24 x^2+3 x^3\right )} \, dx=x^{2-e^{\frac {1}{\left (-4+e^x-x\right )^2}}-x} \]

[In]

Integrate[(E^(-(E^(16 + E^(2*x) + E^x*(-8 - 2*x) + 8*x + x^2)^(-1)*Log[x]) + (2 - x)*Log[x])*(-128 + E^(3*x)*(
2 - x) - 32*x + 24*x^2 + 10*x^3 + x^4 + E^(2*x)*(-24 + 6*x + 3*x^2) + E^x*(96 - 18*x^2 - 3*x^3) + (64*x - E^(3
*x)*x + 48*x^2 + 12*x^3 + x^4 + E^(2*x)*(12*x + 3*x^2) + E^x*(-48*x - 24*x^2 - 3*x^3))*Log[x] + E^(16 + E^(2*x
) + E^x*(-8 - 2*x) + 8*x + x^2)^(-1)*(64 - E^(3*x) + 48*x + 12*x^2 + x^3 + E^(2*x)*(12 + 3*x) + E^x*(-48 - 24*
x - 3*x^2) + (-2*x + 2*E^x*x)*Log[x])))/(-64*x + E^(3*x)*x - 48*x^2 - 12*x^3 - x^4 + E^(2*x)*(-12*x - 3*x^2) +
E^x*(48*x + 24*x^2 + 3*x^3)),x]

[Out]

x^(2 - E^(-4 + E^x - x)^(-2) - x)

Maple [A] (verified)

Time = 285.92 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.57

method	result	size
parallelrisch	\({\mathrm e}^{-\ln \left (x \right ) \left ({\mathrm e}^{\frac {1}{-2 \,{\mathrm e}^{x} x +x^{2}-8 \,{\mathrm e}^{x}+{\mathrm e}^{2 x}+8 x +16}}+x -2\right )}\)	\(33\)
risch	\(x^{-{\mathrm e}^{-\frac {1}{2 \,{\mathrm e}^{x} x -x^{2}+8 \,{\mathrm e}^{x}-{\mathrm e}^{2 x}-8 x -16}}} x^{2-x}\)	\(43\)

[In]

int((((2*exp(x)*x-2*x)*ln(x)-exp(x)^3+(3*x+12)*exp(x)^2+(-3*x^2-24*x-48)*exp(x)+x^3+12*x^2+48*x+64)*exp(1/(exp
(x)^2+(-2*x-8)*exp(x)+x^2+8*x+16))+(-x*exp(x)^3+(3*x^2+12*x)*exp(x)^2+(-3*x^3-24*x^2-48*x)*exp(x)+x^4+12*x^3+4
8*x^2+64*x)*ln(x)+(2-x)*exp(x)^3+(3*x^2+6*x-24)*exp(x)^2+(-3*x^3-18*x^2+96)*exp(x)+x^4+10*x^3+24*x^2-32*x-128)
*exp(-ln(x)*exp(1/(exp(x)^2+(-2*x-8)*exp(x)+x^2+8*x+16))+(2-x)*ln(x))/(x*exp(x)^3+(-3*x^2-12*x)*exp(x)^2+(3*x^
3+24*x^2+48*x)*exp(x)-x^4-12*x^3-48*x^2-64*x),x,method=_RETURNVERBOSE)

[Out]

exp(-ln(x)*(exp(1/(exp(x)^2-2*exp(x)*x+x^2-8*exp(x)+8*x+16))+x-2))

Fricas [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.67 \[ \int \frac {e^{-e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \log (x)+(2-x) \log (x)} \left (-128+e^{3 x} (2-x)-32 x+24 x^2+10 x^3+x^4+e^{2 x} \left (-24+6 x+3 x^2\right )+e^x \left (96-18 x^2-3 x^3\right )+\left (64 x-e^{3 x} x+48 x^2+12 x^3+x^4+e^{2 x} \left (12 x+3 x^2\right )+e^x \left (-48 x-24 x^2-3 x^3\right )\right ) \log (x)+e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \left (64-e^{3 x}+48 x+12 x^2+x^3+e^{2 x} (12+3 x)+e^x \left (-48-24 x-3 x^2\right )+\left (-2 x+2 e^x x\right ) \log (x)\right )\right )}{-64 x+e^{3 x} x-48 x^2-12 x^3-x^4+e^{2 x} \left (-12 x-3 x^2\right )+e^x \left (48 x+24 x^2+3 x^3\right )} \, dx=e^{\left (-{\left (x - 2\right )} \log \left (x\right ) - e^{\left (\frac {1}{x^{2} - 2 \, {\left (x + 4\right )} e^{x} + 8 \, x + e^{\left (2 \, x\right )} + 16}\right )} \log \left (x\right )\right )} \]

[In]

integrate((((2*exp(x)*x-2*x)*log(x)-exp(x)^3+(3*x+12)*exp(x)^2+(-3*x^2-24*x-48)*exp(x)+x^3+12*x^2+48*x+64)*exp
(1/(exp(x)^2+(-2*x-8)*exp(x)+x^2+8*x+16))+(-x*exp(x)^3+(3*x^2+12*x)*exp(x)^2+(-3*x^3-24*x^2-48*x)*exp(x)+x^4+1
2*x^3+48*x^2+64*x)*log(x)+(2-x)*exp(x)^3+(3*x^2+6*x-24)*exp(x)^2+(-3*x^3-18*x^2+96)*exp(x)+x^4+10*x^3+24*x^2-3
2*x-128)*exp(-log(x)*exp(1/(exp(x)^2+(-2*x-8)*exp(x)+x^2+8*x+16))+(2-x)*log(x))/(x*exp(x)^3+(-3*x^2-12*x)*exp(
x)^2+(3*x^3+24*x^2+48*x)*exp(x)-x^4-12*x^3-48*x^2-64*x),x, algorithm="fricas")

[Out]

e^(-(x - 2)*log(x) - e^(1/(x^2 - 2*(x + 4)*e^x + 8*x + e^(2*x) + 16))*log(x))

Sympy [A] (verification not implemented)

Time = 76.17 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.76 \[ \int \frac {e^{-e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \log (x)+(2-x) \log (x)} \left (-128+e^{3 x} (2-x)-32 x+24 x^2+10 x^3+x^4+e^{2 x} \left (-24+6 x+3 x^2\right )+e^x \left (96-18 x^2-3 x^3\right )+\left (64 x-e^{3 x} x+48 x^2+12 x^3+x^4+e^{2 x} \left (12 x+3 x^2\right )+e^x \left (-48 x-24 x^2-3 x^3\right )\right ) \log (x)+e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \left (64-e^{3 x}+48 x+12 x^2+x^3+e^{2 x} (12+3 x)+e^x \left (-48-24 x-3 x^2\right )+\left (-2 x+2 e^x x\right ) \log (x)\right )\right )}{-64 x+e^{3 x} x-48 x^2-12 x^3-x^4+e^{2 x} \left (-12 x-3 x^2\right )+e^x \left (48 x+24 x^2+3 x^3\right )} \, dx=e^{\left (2 - x\right ) \log {\left (x \right )} - e^{\frac {1}{x^{2} + 8 x + \left (- 2 x - 8\right ) e^{x} + e^{2 x} + 16}} \log {\left (x \right )}} \]

[In]

integrate((((2*exp(x)*x-2*x)*ln(x)-exp(x)**3+(3*x+12)*exp(x)**2+(-3*x**2-24*x-48)*exp(x)+x**3+12*x**2+48*x+64)
*exp(1/(exp(x)**2+(-2*x-8)*exp(x)+x**2+8*x+16))+(-x*exp(x)**3+(3*x**2+12*x)*exp(x)**2+(-3*x**3-24*x**2-48*x)*e
xp(x)+x**4+12*x**3+48*x**2+64*x)*ln(x)+(2-x)*exp(x)**3+(3*x**2+6*x-24)*exp(x)**2+(-3*x**3-18*x**2+96)*exp(x)+x
**4+10*x**3+24*x**2-32*x-128)*exp(-ln(x)*exp(1/(exp(x)**2+(-2*x-8)*exp(x)+x**2+8*x+16))+(2-x)*ln(x))/(x*exp(x)
**3+(-3*x**2-12*x)*exp(x)**2+(3*x**3+24*x**2+48*x)*exp(x)-x**4-12*x**3-48*x**2-64*x),x)

[Out]

exp((2 - x)*log(x) - exp(1/(x**2 + 8*x + (-2*x - 8)*exp(x) + exp(2*x) + 16))*log(x))

Maxima [A] (verification not implemented)

none

Time = 0.40 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.76 \[ \int \frac {e^{-e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \log (x)+(2-x) \log (x)} \left (-128+e^{3 x} (2-x)-32 x+24 x^2+10 x^3+x^4+e^{2 x} \left (-24+6 x+3 x^2\right )+e^x \left (96-18 x^2-3 x^3\right )+\left (64 x-e^{3 x} x+48 x^2+12 x^3+x^4+e^{2 x} \left (12 x+3 x^2\right )+e^x \left (-48 x-24 x^2-3 x^3\right )\right ) \log (x)+e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \left (64-e^{3 x}+48 x+12 x^2+x^3+e^{2 x} (12+3 x)+e^x \left (-48-24 x-3 x^2\right )+\left (-2 x+2 e^x x\right ) \log (x)\right )\right )}{-64 x+e^{3 x} x-48 x^2-12 x^3-x^4+e^{2 x} \left (-12 x-3 x^2\right )+e^x \left (48 x+24 x^2+3 x^3\right )} \, dx=x^{2} e^{\left (-x \log \left (x\right ) - e^{\left (\frac {1}{x^{2} - 2 \, {\left (x + 4\right )} e^{x} + 8 \, x + e^{\left (2 \, x\right )} + 16}\right )} \log \left (x\right )\right )} \]

[In]

integrate((((2*exp(x)*x-2*x)*log(x)-exp(x)^3+(3*x+12)*exp(x)^2+(-3*x^2-24*x-48)*exp(x)+x^3+12*x^2+48*x+64)*exp
(1/(exp(x)^2+(-2*x-8)*exp(x)+x^2+8*x+16))+(-x*exp(x)^3+(3*x^2+12*x)*exp(x)^2+(-3*x^3-24*x^2-48*x)*exp(x)+x^4+1
2*x^3+48*x^2+64*x)*log(x)+(2-x)*exp(x)^3+(3*x^2+6*x-24)*exp(x)^2+(-3*x^3-18*x^2+96)*exp(x)+x^4+10*x^3+24*x^2-3
2*x-128)*exp(-log(x)*exp(1/(exp(x)^2+(-2*x-8)*exp(x)+x^2+8*x+16))+(2-x)*log(x))/(x*exp(x)^3+(-3*x^2-12*x)*exp(
x)^2+(3*x^3+24*x^2+48*x)*exp(x)-x^4-12*x^3-48*x^2-64*x),x, algorithm="maxima")

[Out]

x^2*e^(-x*log(x) - e^(1/(x^2 - 2*(x + 4)*e^x + 8*x + e^(2*x) + 16))*log(x))

Giac [F]

\[ \int \frac {e^{-e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \log (x)+(2-x) \log (x)} \left (-128+e^{3 x} (2-x)-32 x+24 x^2+10 x^3+x^4+e^{2 x} \left (-24+6 x+3 x^2\right )+e^x \left (96-18 x^2-3 x^3\right )+\left (64 x-e^{3 x} x+48 x^2+12 x^3+x^4+e^{2 x} \left (12 x+3 x^2\right )+e^x \left (-48 x-24 x^2-3 x^3\right )\right ) \log (x)+e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \left (64-e^{3 x}+48 x+12 x^2+x^3+e^{2 x} (12+3 x)+e^x \left (-48-24 x-3 x^2\right )+\left (-2 x+2 e^x x\right ) \log (x)\right )\right )}{-64 x+e^{3 x} x-48 x^2-12 x^3-x^4+e^{2 x} \left (-12 x-3 x^2\right )+e^x \left (48 x+24 x^2+3 x^3\right )} \, dx=\int { -\frac {{\left (x^{4} + 10 \, x^{3} + 24 \, x^{2} - {\left (x - 2\right )} e^{\left (3 \, x\right )} + 3 \, {\left (x^{2} + 2 \, x - 8\right )} e^{\left (2 \, x\right )} - 3 \, {\left (x^{3} + 6 \, x^{2} - 32\right )} e^{x} + {\left (x^{3} + 12 \, x^{2} + 3 \, {\left (x + 4\right )} e^{\left (2 \, x\right )} - 3 \, {\left (x^{2} + 8 \, x + 16\right )} e^{x} + 2 \, {\left (x e^{x} - x\right )} \log \left (x\right ) + 48 \, x - e^{\left (3 \, x\right )} + 64\right )} e^{\left (\frac {1}{x^{2} - 2 \, {\left (x + 4\right )} e^{x} + 8 \, x + e^{\left (2 \, x\right )} + 16}\right )} + {\left (x^{4} + 12 \, x^{3} + 48 \, x^{2} - x e^{\left (3 \, x\right )} + 3 \, {\left (x^{2} + 4 \, x\right )} e^{\left (2 \, x\right )} - 3 \, {\left (x^{3} + 8 \, x^{2} + 16 \, x\right )} e^{x} + 64 \, x\right )} \log \left (x\right ) - 32 \, x - 128\right )} e^{\left (-{\left (x - 2\right )} \log \left (x\right ) - e^{\left (\frac {1}{x^{2} - 2 \, {\left (x + 4\right )} e^{x} + 8 \, x + e^{\left (2 \, x\right )} + 16}\right )} \log \left (x\right )\right )}}{x^{4} + 12 \, x^{3} + 48 \, x^{2} - x e^{\left (3 \, x\right )} + 3 \, {\left (x^{2} + 4 \, x\right )} e^{\left (2 \, x\right )} - 3 \, {\left (x^{3} + 8 \, x^{2} + 16 \, x\right )} e^{x} + 64 \, x} \,d x } \]

[In]

integrate((((2*exp(x)*x-2*x)*log(x)-exp(x)^3+(3*x+12)*exp(x)^2+(-3*x^2-24*x-48)*exp(x)+x^3+12*x^2+48*x+64)*exp
(1/(exp(x)^2+(-2*x-8)*exp(x)+x^2+8*x+16))+(-x*exp(x)^3+(3*x^2+12*x)*exp(x)^2+(-3*x^3-24*x^2-48*x)*exp(x)+x^4+1
2*x^3+48*x^2+64*x)*log(x)+(2-x)*exp(x)^3+(3*x^2+6*x-24)*exp(x)^2+(-3*x^3-18*x^2+96)*exp(x)+x^4+10*x^3+24*x^2-3
2*x-128)*exp(-log(x)*exp(1/(exp(x)^2+(-2*x-8)*exp(x)+x^2+8*x+16))+(2-x)*log(x))/(x*exp(x)^3+(-3*x^2-12*x)*exp(
x)^2+(3*x^3+24*x^2+48*x)*exp(x)-x^4-12*x^3-48*x^2-64*x),x, algorithm="giac")

[Out]

integrate(-(x^4 + 10*x^3 + 24*x^2 - (x - 2)*e^(3*x) + 3*(x^2 + 2*x - 8)*e^(2*x) - 3*(x^3 + 6*x^2 - 32)*e^x + (
x^3 + 12*x^2 + 3*(x + 4)*e^(2*x) - 3*(x^2 + 8*x + 16)*e^x + 2*(x*e^x - x)*log(x) + 48*x - e^(3*x) + 64)*e^(1/(
x^2 - 2*(x + 4)*e^x + 8*x + e^(2*x) + 16)) + (x^4 + 12*x^3 + 48*x^2 - x*e^(3*x) + 3*(x^2 + 4*x)*e^(2*x) - 3*(x
^3 + 8*x^2 + 16*x)*e^x + 64*x)*log(x) - 32*x - 128)*e^(-(x - 2)*log(x) - e^(1/(x^2 - 2*(x + 4)*e^x + 8*x + e^(
2*x) + 16))*log(x))/(x^4 + 12*x^3 + 48*x^2 - x*e^(3*x) + 3*(x^2 + 4*x)*e^(2*x) - 3*(x^3 + 8*x^2 + 16*x)*e^x +
64*x), x)

Mupad [B] (verification not implemented)

Time = 10.13 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.76 \[ \int \frac {e^{-e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \log (x)+(2-x) \log (x)} \left (-128+e^{3 x} (2-x)-32 x+24 x^2+10 x^3+x^4+e^{2 x} \left (-24+6 x+3 x^2\right )+e^x \left (96-18 x^2-3 x^3\right )+\left (64 x-e^{3 x} x+48 x^2+12 x^3+x^4+e^{2 x} \left (12 x+3 x^2\right )+e^x \left (-48 x-24 x^2-3 x^3\right )\right ) \log (x)+e^{\frac {1}{16+e^{2 x}+e^x (-8-2 x)+8 x+x^2}} \left (64-e^{3 x}+48 x+12 x^2+x^3+e^{2 x} (12+3 x)+e^x \left (-48-24 x-3 x^2\right )+\left (-2 x+2 e^x x\right ) \log (x)\right )\right )}{-64 x+e^{3 x} x-48 x^2-12 x^3-x^4+e^{2 x} \left (-12 x-3 x^2\right )+e^x \left (48 x+24 x^2+3 x^3\right )} \, dx=\frac {x^2}{x^{{\mathrm {e}}^{\frac {1}{8\,x+{\mathrm {e}}^{2\,x}-8\,{\mathrm {e}}^x-2\,x\,{\mathrm {e}}^x+x^2+16}}}\,x^x} \]

[In]

int(-(exp(- log(x)*(x - 2) - exp(1/(8*x + exp(2*x) - exp(x)*(2*x + 8) + x^2 + 16))*log(x))*(exp(2*x)*(6*x + 3*
x^2 - 24) - 32*x - exp(x)*(18*x^2 + 3*x^3 - 96) + exp(1/(8*x + exp(2*x) - exp(x)*(2*x + 8) + x^2 + 16))*(48*x
- exp(3*x) - log(x)*(2*x - 2*x*exp(x)) - exp(x)*(24*x + 3*x^2 + 48) + exp(2*x)*(3*x + 12) + 12*x^2 + x^3 + 64)
- exp(3*x)*(x - 2) + log(x)*(64*x + exp(2*x)*(12*x + 3*x^2) - x*exp(3*x) + 48*x^2 + 12*x^3 + x^4 - exp(x)*(48
*x + 24*x^2 + 3*x^3)) + 24*x^2 + 10*x^3 + x^4 - 128))/(64*x + exp(2*x)*(12*x + 3*x^2) - x*exp(3*x) + 48*x^2 +
12*x^3 + x^4 - exp(x)*(48*x + 24*x^2 + 3*x^3)),x)

[Out]

x^2/(x^exp(1/(8*x + exp(2*x) - 8*exp(x) - 2*x*exp(x) + x^2 + 16))*x^x)