Integrand size = 38, antiderivative size = 22 \[ \int \frac {-5-x^2+\left (5+3 x^2\right ) \log (x)+e^7 (1-2 x) \log ^2(x)}{e^7 \log ^2(x)} \, dx=5+x-x^2+\frac {x \left (5+x^2\right )}{e^7 \log (x)} \]
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Time = 0.11 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.50, number of steps used = 15, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {12, 6874, 2367, 2334, 2335, 2343, 2346, 2209} \[ \int \frac {-5-x^2+\left (5+3 x^2\right ) \log (x)+e^7 (1-2 x) \log ^2(x)}{e^7 \log ^2(x)} \, dx=\frac {x^3}{e^7 \log (x)}-\frac {1}{4} (1-2 x)^2+\frac {5 x}{e^7 \log (x)} \]
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Rule 12
Rule 2209
Rule 2334
Rule 2335
Rule 2343
Rule 2346
Rule 2367
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \frac {\int \frac {-5-x^2+\left (5+3 x^2\right ) \log (x)+e^7 (1-2 x) \log ^2(x)}{\log ^2(x)} \, dx}{e^7} \\ & = \frac {\int \left (-e^7 (-1+2 x)+\frac {-5-x^2}{\log ^2(x)}+\frac {5+3 x^2}{\log (x)}\right ) \, dx}{e^7} \\ & = -\frac {1}{4} (1-2 x)^2+\frac {\int \frac {-5-x^2}{\log ^2(x)} \, dx}{e^7}+\frac {\int \frac {5+3 x^2}{\log (x)} \, dx}{e^7} \\ & = -\frac {1}{4} (1-2 x)^2+\frac {\int \left (-\frac {5}{\log ^2(x)}-\frac {x^2}{\log ^2(x)}\right ) \, dx}{e^7}+\frac {\int \left (\frac {5}{\log (x)}+\frac {3 x^2}{\log (x)}\right ) \, dx}{e^7} \\ & = -\frac {1}{4} (1-2 x)^2-\frac {\int \frac {x^2}{\log ^2(x)} \, dx}{e^7}+\frac {3 \int \frac {x^2}{\log (x)} \, dx}{e^7}-\frac {5 \int \frac {1}{\log ^2(x)} \, dx}{e^7}+\frac {5 \int \frac {1}{\log (x)} \, dx}{e^7} \\ & = -\frac {1}{4} (1-2 x)^2+\frac {5 x}{e^7 \log (x)}+\frac {x^3}{e^7 \log (x)}+\frac {5 \operatorname {LogIntegral}(x)}{e^7}-\frac {3 \int \frac {x^2}{\log (x)} \, dx}{e^7}+\frac {3 \text {Subst}\left (\int \frac {e^{3 x}}{x} \, dx,x,\log (x)\right )}{e^7}-\frac {5 \int \frac {1}{\log (x)} \, dx}{e^7} \\ & = -\frac {1}{4} (1-2 x)^2+\frac {3 \operatorname {ExpIntegralEi}(3 \log (x))}{e^7}+\frac {5 x}{e^7 \log (x)}+\frac {x^3}{e^7 \log (x)}-\frac {3 \text {Subst}\left (\int \frac {e^{3 x}}{x} \, dx,x,\log (x)\right )}{e^7} \\ & = -\frac {1}{4} (1-2 x)^2+\frac {5 x}{e^7 \log (x)}+\frac {x^3}{e^7 \log (x)} \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {-5-x^2+\left (5+3 x^2\right ) \log (x)+e^7 (1-2 x) \log ^2(x)}{e^7 \log ^2(x)} \, dx=\frac {x \left (5+x^2-e^7 (-1+x) \log (x)\right )}{e^7 \log (x)} \]
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Time = 0.22 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.95
method | result | size |
risch | \(-x \left (-1+x \right )+\frac {\left (x^{2}+5\right ) x \,{\mathrm e}^{-7}}{\ln \left (x \right )}\) | \(21\) |
parallelrisch | \(\frac {{\mathrm e}^{-7} \left (-{\mathrm e}^{7} x^{2} \ln \left (x \right )+{\mathrm e}^{7} x \ln \left (x \right )+x^{3}+5 x \right )}{\ln \left (x \right )}\) | \(32\) |
default | \({\mathrm e}^{-7} \left (-x^{2} {\mathrm e}^{7}+x \,{\mathrm e}^{7}+\frac {x^{3}}{\ln \left (x \right )}+\frac {5 x}{\ln \left (x \right )}\right )\) | \(33\) |
norman | \(\frac {x \ln \left (x \right )+{\mathrm e}^{-7} x^{3}-x^{2} \ln \left (x \right )+5 \,{\mathrm e}^{-7} x}{\ln \left (x \right )}\) | \(33\) |
parts | \(x +{\mathrm e}^{-7} \left (-3 \,\operatorname {Ei}_{1}\left (-3 \ln \left (x \right )\right )-5 \,\operatorname {Ei}_{1}\left (-\ln \left (x \right )\right )\right )-x^{2}-{\mathrm e}^{-7} \left (-\frac {x^{3}}{\ln \left (x \right )}-3 \,\operatorname {Ei}_{1}\left (-3 \ln \left (x \right )\right )-\frac {5 x}{\ln \left (x \right )}-5 \,\operatorname {Ei}_{1}\left (-\ln \left (x \right )\right )\right )\) | \(69\) |
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Time = 0.25 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.23 \[ \int \frac {-5-x^2+\left (5+3 x^2\right ) \log (x)+e^7 (1-2 x) \log ^2(x)}{e^7 \log ^2(x)} \, dx=\frac {{\left (x^{3} - {\left (x^{2} - x\right )} e^{7} \log \left (x\right ) + 5 \, x\right )} e^{\left (-7\right )}}{\log \left (x\right )} \]
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Time = 0.04 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.77 \[ \int \frac {-5-x^2+\left (5+3 x^2\right ) \log (x)+e^7 (1-2 x) \log ^2(x)}{e^7 \log ^2(x)} \, dx=- x^{2} + x + \frac {x^{3} + 5 x}{e^{7} \log {\left (x \right )}} \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 0.25 (sec) , antiderivative size = 44, normalized size of antiderivative = 2.00 \[ \int \frac {-5-x^2+\left (5+3 x^2\right ) \log (x)+e^7 (1-2 x) \log ^2(x)}{e^7 \log ^2(x)} \, dx=-{\left (x^{2} e^{7} - x e^{7} - 3 \, {\rm Ei}\left (3 \, \log \left (x\right )\right ) - 5 \, {\rm Ei}\left (\log \left (x\right )\right ) + 5 \, \Gamma \left (-1, -\log \left (x\right )\right ) + 3 \, \Gamma \left (-1, -3 \, \log \left (x\right )\right )\right )} e^{\left (-7\right )} \]
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Time = 0.28 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.45 \[ \int \frac {-5-x^2+\left (5+3 x^2\right ) \log (x)+e^7 (1-2 x) \log ^2(x)}{e^7 \log ^2(x)} \, dx=-{\left (x^{2} e^{7} - x e^{7} - \frac {x^{3}}{\log \left (x\right )} - \frac {5 \, x}{\log \left (x\right )}\right )} e^{\left (-7\right )} \]
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Time = 13.39 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.18 \[ \int \frac {-5-x^2+\left (5+3 x^2\right ) \log (x)+e^7 (1-2 x) \log ^2(x)}{e^7 \log ^2(x)} \, dx=x\,{\mathrm {e}}^{-7}\,\left ({\mathrm {e}}^7-x\,{\mathrm {e}}^7\right )+\frac {x\,{\mathrm {e}}^{-7}\,\left (x^2+5\right )}{\ln \left (x\right )} \]
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