Integrand size = 71, antiderivative size = 20 \[ \int \frac {2 e \log (2)+(-4 e \log (2)+2 e x \log (2) \log (3)) \log (x)+(e \log (2)-e x \log (2) \log (3)) \log ^2(x)}{4\ 3^x \log ^2(x)-4\ 3^x \log ^3(x)+3^x \log ^4(x)} \, dx=\frac {3^{-x} e x \log (2)}{(-2+\log (x)) \log (x)} \]
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\[ \int \frac {2 e \log (2)+(-4 e \log (2)+2 e x \log (2) \log (3)) \log (x)+(e \log (2)-e x \log (2) \log (3)) \log ^2(x)}{4\ 3^x \log ^2(x)-4\ 3^x \log ^3(x)+3^x \log ^4(x)} \, dx=\int \frac {2 e \log (2)+(-4 e \log (2)+2 e x \log (2) \log (3)) \log (x)+(e \log (2)-e x \log (2) \log (3)) \log ^2(x)}{4\ 3^x \log ^2(x)-4\ 3^x \log ^3(x)+3^x \log ^4(x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {3^{-x} e \log (2) \left (2+(-4+x \log (9)) \log (x)+(1-x \log (3)) \log ^2(x)\right )}{(2-\log (x))^2 \log ^2(x)} \, dx \\ & = (e \log (2)) \int \frac {3^{-x} \left (2+(-4+x \log (9)) \log (x)+(1-x \log (3)) \log ^2(x)\right )}{(2-\log (x))^2 \log ^2(x)} \, dx \\ & = (e \log (2)) \int \left (-\frac {3^{-x}}{2 (-2+\log (x))^2}+\frac {3^{-x} (2-x \log (9))}{4 (-2+\log (x))}+\frac {3^{-x}}{2 \log ^2(x)}+\frac {3^{-x} (-2+x \log (9))}{4 \log (x)}\right ) \, dx \\ & = \frac {1}{4} (e \log (2)) \int \frac {3^{-x} (2-x \log (9))}{-2+\log (x)} \, dx+\frac {1}{4} (e \log (2)) \int \frac {3^{-x} (-2+x \log (9))}{\log (x)} \, dx-\frac {1}{2} (e \log (2)) \int \frac {3^{-x}}{(-2+\log (x))^2} \, dx+\frac {1}{2} (e \log (2)) \int \frac {3^{-x}}{\log ^2(x)} \, dx \\ & = \frac {1}{4} (e \log (2)) \int \left (\frac {2\ 3^{-x}}{-2+\log (x)}-\frac {3^{-x} x \log (9)}{-2+\log (x)}\right ) \, dx+\frac {1}{4} (e \log (2)) \int \left (-\frac {2\ 3^{-x}}{\log (x)}+\frac {3^{-x} x \log (9)}{\log (x)}\right ) \, dx-\frac {1}{2} (e \log (2)) \int \frac {3^{-x}}{(-2+\log (x))^2} \, dx+\frac {1}{2} (e \log (2)) \int \frac {3^{-x}}{\log ^2(x)} \, dx \\ & = -\left (\frac {1}{2} (e \log (2)) \int \frac {3^{-x}}{(-2+\log (x))^2} \, dx\right )+\frac {1}{2} (e \log (2)) \int \frac {3^{-x}}{-2+\log (x)} \, dx+\frac {1}{2} (e \log (2)) \int \frac {3^{-x}}{\log ^2(x)} \, dx-\frac {1}{2} (e \log (2)) \int \frac {3^{-x}}{\log (x)} \, dx-\frac {1}{4} (e \log (2) \log (9)) \int \frac {3^{-x} x}{-2+\log (x)} \, dx+\frac {1}{4} (e \log (2) \log (9)) \int \frac {3^{-x} x}{\log (x)} \, dx \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.70 \[ \int \frac {2 e \log (2)+(-4 e \log (2)+2 e x \log (2) \log (3)) \log (x)+(e \log (2)-e x \log (2) \log (3)) \log ^2(x)}{4\ 3^x \log ^2(x)-4\ 3^x \log ^3(x)+3^x \log ^4(x)} \, dx=\frac {3^{-x} e x \log (2) (-\log (9)+\log (3) \log (x))}{\log (3) (-2+\log (x))^2 \log (x)} \]
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Time = 1.16 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.10
method | result | size |
risch | \(\frac {{\mathrm e} 3^{-x} x \ln \left (2\right )}{\left (\ln \left (x \right )-2\right ) \ln \left (x \right )}\) | \(22\) |
norman | \(\frac {{\mathrm e} \,{\mathrm e}^{-x \ln \left (3\right )} x \ln \left (2\right )}{\left (\ln \left (x \right )-2\right ) \ln \left (x \right )}\) | \(24\) |
parallelrisch | \(\frac {{\mathrm e} \,{\mathrm e}^{-x \ln \left (3\right )} x \ln \left (2\right )}{\left (\ln \left (x \right )-2\right ) \ln \left (x \right )}\) | \(24\) |
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Time = 0.24 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.20 \[ \int \frac {2 e \log (2)+(-4 e \log (2)+2 e x \log (2) \log (3)) \log (x)+(e \log (2)-e x \log (2) \log (3)) \log ^2(x)}{4\ 3^x \log ^2(x)-4\ 3^x \log ^3(x)+3^x \log ^4(x)} \, dx=\frac {x e \log \left (2\right )}{3^{x} \log \left (x\right )^{2} - 2 \cdot 3^{x} \log \left (x\right )} \]
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Time = 0.13 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.20 \[ \int \frac {2 e \log (2)+(-4 e \log (2)+2 e x \log (2) \log (3)) \log (x)+(e \log (2)-e x \log (2) \log (3)) \log ^2(x)}{4\ 3^x \log ^2(x)-4\ 3^x \log ^3(x)+3^x \log ^4(x)} \, dx=\frac {e x e^{- x \log {\left (3 \right )}} \log {\left (2 \right )}}{\log {\left (x \right )}^{2} - 2 \log {\left (x \right )}} \]
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Time = 0.36 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.15 \[ \int \frac {2 e \log (2)+(-4 e \log (2)+2 e x \log (2) \log (3)) \log (x)+(e \log (2)-e x \log (2) \log (3)) \log ^2(x)}{4\ 3^x \log ^2(x)-4\ 3^x \log ^3(x)+3^x \log ^4(x)} \, dx=\frac {x e^{\left (-x \log \left (3\right ) + 1\right )} \log \left (2\right )}{\log \left (x\right )^{2} - 2 \, \log \left (x\right )} \]
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\[ \int \frac {2 e \log (2)+(-4 e \log (2)+2 e x \log (2) \log (3)) \log (x)+(e \log (2)-e x \log (2) \log (3)) \log ^2(x)}{4\ 3^x \log ^2(x)-4\ 3^x \log ^3(x)+3^x \log ^4(x)} \, dx=\int { -\frac {{\left (x e \log \left (3\right ) \log \left (2\right ) - e \log \left (2\right )\right )} \log \left (x\right )^{2} - 2 \, e \log \left (2\right ) - 2 \, {\left (x e \log \left (3\right ) \log \left (2\right ) - 2 \, e \log \left (2\right )\right )} \log \left (x\right )}{3^{x} \log \left (x\right )^{4} - 4 \cdot 3^{x} \log \left (x\right )^{3} + 4 \cdot 3^{x} \log \left (x\right )^{2}} \,d x } \]
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Time = 14.67 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.05 \[ \int \frac {2 e \log (2)+(-4 e \log (2)+2 e x \log (2) \log (3)) \log (x)+(e \log (2)-e x \log (2) \log (3)) \log ^2(x)}{4\ 3^x \log ^2(x)-4\ 3^x \log ^3(x)+3^x \log ^4(x)} \, dx=\frac {x\,\mathrm {e}\,\ln \left (2\right )}{3^x\,\ln \left (x\right )\,\left (\ln \left (x\right )-2\right )} \]
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