Integrand size = 88, antiderivative size = 27 \[ \int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{\left (25 x+10 x^2+x^3\right ) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx=\frac {\left (-5+2 x^4-\frac {x}{5+x}\right ) \log (4)}{\log \left (\frac {2}{\log (x)}\right )} \]
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\[ \int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{\left (25 x+10 x^2+x^3\right ) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx=\int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{\left (25 x+10 x^2+x^3\right ) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{x \left (25+10 x+x^2\right ) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx \\ & = \int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{x (5+x)^2 \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx \\ & = \int \left (\frac {\left (-25-6 x+10 x^4+2 x^5\right ) \log (4)}{x (5+x) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )}+\frac {\left (-5+200 x^3+80 x^4+8 x^5\right ) \log (4)}{(5+x)^2 \log \left (\frac {2}{\log (x)}\right )}\right ) \, dx \\ & = \log (4) \int \frac {-25-6 x+10 x^4+2 x^5}{x (5+x) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx+\log (4) \int \frac {-5+200 x^3+80 x^4+8 x^5}{(5+x)^2 \log \left (\frac {2}{\log (x)}\right )} \, dx \\ & = \log (4) \int \left (-\frac {5}{x \log (x) \log ^2\left (\frac {2}{\log (x)}\right )}+\frac {2 x^3}{\log (x) \log ^2\left (\frac {2}{\log (x)}\right )}-\frac {1}{(5+x) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )}\right ) \, dx+\log (4) \int \left (\frac {8 x^3}{\log \left (\frac {2}{\log (x)}\right )}-\frac {5}{(5+x)^2 \log \left (\frac {2}{\log (x)}\right )}\right ) \, dx \\ & = -\left (\log (4) \int \frac {1}{(5+x) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx\right )+(2 \log (4)) \int \frac {x^3}{\log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx-(5 \log (4)) \int \frac {1}{x \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx-(5 \log (4)) \int \frac {1}{(5+x)^2 \log \left (\frac {2}{\log (x)}\right )} \, dx+(8 \log (4)) \int \frac {x^3}{\log \left (\frac {2}{\log (x)}\right )} \, dx \\ & = -\left (\log (4) \int \frac {1}{(5+x) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx\right )+(2 \log (4)) \int \frac {x^3}{\log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx-(5 \log (4)) \int \frac {1}{(5+x)^2 \log \left (\frac {2}{\log (x)}\right )} \, dx-(5 \log (4)) \text {Subst}\left (\int \frac {1}{x \log ^2\left (\frac {2}{x}\right )} \, dx,x,\log (x)\right )+(8 \log (4)) \int \frac {x^3}{\log \left (\frac {2}{\log (x)}\right )} \, dx \\ & = -\left (\log (4) \int \frac {1}{(5+x) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx\right )+(2 \log (4)) \int \frac {x^3}{\log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx-(5 \log (4)) \int \frac {1}{(5+x)^2 \log \left (\frac {2}{\log (x)}\right )} \, dx+(5 \log (4)) \text {Subst}\left (\int \frac {1}{x^2} \, dx,x,\log \left (\frac {2}{\log (x)}\right )\right )+(8 \log (4)) \int \frac {x^3}{\log \left (\frac {2}{\log (x)}\right )} \, dx \\ & = -\frac {5 \log (4)}{\log \left (\frac {2}{\log (x)}\right )}-\log (4) \int \frac {1}{(5+x) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx+(2 \log (4)) \int \frac {x^3}{\log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx-(5 \log (4)) \int \frac {1}{(5+x)^2 \log \left (\frac {2}{\log (x)}\right )} \, dx+(8 \log (4)) \int \frac {x^3}{\log \left (\frac {2}{\log (x)}\right )} \, dx \\ \end{align*}
Time = 0.29 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.19 \[ \int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{\left (25 x+10 x^2+x^3\right ) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx=\frac {\left (-25-6 x+10 x^4+2 x^5\right ) \log (4)}{(5+x) \log \left (\frac {2}{\log (x)}\right )} \]
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Time = 5.45 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.37
method | result | size |
risch | \(\frac {4 \ln \left (2\right ) \left (2 x^{5}+10 x^{4}-6 x -25\right )}{\left (5+x \right ) \left (2 \ln \left (2\right )-2 \ln \left (\ln \left (x \right )\right )\right )}\) | \(37\) |
parallelrisch | \(\frac {4 x^{5} \ln \left (2\right )+20 x^{4} \ln \left (2\right )-12 x \ln \left (2\right )-50 \ln \left (2\right )}{\ln \left (\frac {2}{\ln \left (x \right )}\right ) \left (5+x \right )}\) | \(40\) |
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Time = 0.24 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.22 \[ \int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{\left (25 x+10 x^2+x^3\right ) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx=\frac {2 \, {\left (2 \, x^{5} + 10 \, x^{4} - 6 \, x - 25\right )} \log \left (2\right )}{{\left (x + 5\right )} \log \left (\frac {2}{\log \left (x\right )}\right )} \]
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Time = 0.12 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.37 \[ \int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{\left (25 x+10 x^2+x^3\right ) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx=\frac {4 x^{5} \log {\left (2 \right )} + 20 x^{4} \log {\left (2 \right )} - 12 x \log {\left (2 \right )} - 50 \log {\left (2 \right )}}{\left (x + 5\right ) \log {\left (\frac {2}{\log {\left (x \right )}} \right )}} \]
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Time = 0.32 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.67 \[ \int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{\left (25 x+10 x^2+x^3\right ) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx=\frac {2 \, {\left (2 \, x^{5} \log \left (2\right ) + 10 \, x^{4} \log \left (2\right ) - 6 \, x \log \left (2\right ) - 25 \, \log \left (2\right )\right )}}{x \log \left (2\right ) - {\left (x + 5\right )} \log \left (\log \left (x\right )\right ) + 5 \, \log \left (2\right )} \]
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Time = 0.29 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.78 \[ \int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{\left (25 x+10 x^2+x^3\right ) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx=\frac {2 \, {\left (2 \, x^{5} \log \left (2\right ) + 10 \, x^{4} \log \left (2\right ) - 6 \, x \log \left (2\right ) - 25 \, \log \left (2\right )\right )}}{x \log \left (2\right ) - x \log \left (\log \left (x\right )\right ) + 5 \, \log \left (2\right ) - 5 \, \log \left (\log \left (x\right )\right )} \]
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Time = 15.73 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.22 \[ \int \frac {\left (-125-55 x-6 x^2+50 x^4+20 x^5+2 x^6\right ) \log (4)+\left (-5 x+200 x^4+80 x^5+8 x^6\right ) \log (4) \log (x) \log \left (\frac {2}{\log (x)}\right )}{\left (25 x+10 x^2+x^3\right ) \log (x) \log ^2\left (\frac {2}{\log (x)}\right )} \, dx=-\frac {2\,\ln \left (2\right )\,\left (-2\,x^5-10\,x^4+6\,x+25\right )}{\ln \left (\frac {2}{\ln \left (x\right )}\right )\,\left (x+5\right )} \]
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