Integrand size = 13, antiderivative size = 81 \[ \int f^{a+\frac {b}{x^2}} x^5 \, dx=\frac {1}{6} f^{a+\frac {b}{x^2}} x^6+\frac {1}{12} b f^{a+\frac {b}{x^2}} x^4 \log (f)+\frac {1}{12} b^2 f^{a+\frac {b}{x^2}} x^2 \log ^2(f)-\frac {1}{12} b^3 f^a \operatorname {ExpIntegralEi}\left (\frac {b \log (f)}{x^2}\right ) \log ^3(f) \]
[Out]
Time = 0.06 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {2245, 2241} \[ \int f^{a+\frac {b}{x^2}} x^5 \, dx=-\frac {1}{12} b^3 f^a \log ^3(f) \operatorname {ExpIntegralEi}\left (\frac {b \log (f)}{x^2}\right )+\frac {1}{12} b^2 x^2 \log ^2(f) f^{a+\frac {b}{x^2}}+\frac {1}{6} x^6 f^{a+\frac {b}{x^2}}+\frac {1}{12} b x^4 \log (f) f^{a+\frac {b}{x^2}} \]
[In]
[Out]
Rule 2241
Rule 2245
Rubi steps \begin{align*} \text {integral}& = \frac {1}{6} f^{a+\frac {b}{x^2}} x^6+\frac {1}{3} (b \log (f)) \int f^{a+\frac {b}{x^2}} x^3 \, dx \\ & = \frac {1}{6} f^{a+\frac {b}{x^2}} x^6+\frac {1}{12} b f^{a+\frac {b}{x^2}} x^4 \log (f)+\frac {1}{6} \left (b^2 \log ^2(f)\right ) \int f^{a+\frac {b}{x^2}} x \, dx \\ & = \frac {1}{6} f^{a+\frac {b}{x^2}} x^6+\frac {1}{12} b f^{a+\frac {b}{x^2}} x^4 \log (f)+\frac {1}{12} b^2 f^{a+\frac {b}{x^2}} x^2 \log ^2(f)+\frac {1}{6} \left (b^3 \log ^3(f)\right ) \int \frac {f^{a+\frac {b}{x^2}}}{x} \, dx \\ & = \frac {1}{6} f^{a+\frac {b}{x^2}} x^6+\frac {1}{12} b f^{a+\frac {b}{x^2}} x^4 \log (f)+\frac {1}{12} b^2 f^{a+\frac {b}{x^2}} x^2 \log ^2(f)-\frac {1}{12} b^3 f^a \text {Ei}\left (\frac {b \log (f)}{x^2}\right ) \log ^3(f) \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.70 \[ \int f^{a+\frac {b}{x^2}} x^5 \, dx=\frac {1}{12} f^a \left (-b^3 \operatorname {ExpIntegralEi}\left (\frac {b \log (f)}{x^2}\right ) \log ^3(f)+f^{\frac {b}{x^2}} x^2 \left (2 x^4+b x^2 \log (f)+b^2 \log ^2(f)\right )\right ) \]
[In]
[Out]
Time = 0.12 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.98
method | result | size |
risch | \(\frac {f^{a} x^{6} f^{\frac {b}{x^{2}}}}{6}+\frac {f^{a} \ln \left (f \right ) b \,x^{4} f^{\frac {b}{x^{2}}}}{12}+\frac {f^{a} \ln \left (f \right )^{2} b^{2} x^{2} f^{\frac {b}{x^{2}}}}{12}+\frac {f^{a} \ln \left (f \right )^{3} b^{3} \operatorname {Ei}_{1}\left (-\frac {b \ln \left (f \right )}{x^{2}}\right )}{12}\) | \(79\) |
meijerg | \(\frac {f^{a} b^{3} \ln \left (f \right )^{3} \left (\frac {x^{6}}{3 b^{3} \ln \left (f \right )^{3}}+\frac {x^{4}}{2 b^{2} \ln \left (f \right )^{2}}+\frac {x^{2}}{2 b \ln \left (f \right )}+\frac {11}{36}+\frac {\ln \left (x \right )}{3}-\frac {\ln \left (-b \right )}{6}-\frac {\ln \left (\ln \left (f \right )\right )}{6}-\frac {x^{6} \left (\frac {22 b^{3} \ln \left (f \right )^{3}}{x^{6}}+\frac {36 b^{2} \ln \left (f \right )^{2}}{x^{4}}+\frac {36 b \ln \left (f \right )}{x^{2}}+24\right )}{72 b^{3} \ln \left (f \right )^{3}}+\frac {x^{6} \left (\frac {4 b^{2} \ln \left (f \right )^{2}}{x^{4}}+\frac {4 b \ln \left (f \right )}{x^{2}}+8\right ) {\mathrm e}^{\frac {b \ln \left (f \right )}{x^{2}}}}{24 b^{3} \ln \left (f \right )^{3}}+\frac {\ln \left (-\frac {b \ln \left (f \right )}{x^{2}}\right )}{6}+\frac {\operatorname {Ei}_{1}\left (-\frac {b \ln \left (f \right )}{x^{2}}\right )}{6}\right )}{2}\) | \(177\) |
[In]
[Out]
none
Time = 0.30 (sec) , antiderivative size = 60, normalized size of antiderivative = 0.74 \[ \int f^{a+\frac {b}{x^2}} x^5 \, dx=-\frac {1}{12} \, b^{3} f^{a} {\rm Ei}\left (\frac {b \log \left (f\right )}{x^{2}}\right ) \log \left (f\right )^{3} + \frac {1}{12} \, {\left (2 \, x^{6} + b x^{4} \log \left (f\right ) + b^{2} x^{2} \log \left (f\right )^{2}\right )} f^{\frac {a x^{2} + b}{x^{2}}} \]
[In]
[Out]
\[ \int f^{a+\frac {b}{x^2}} x^5 \, dx=\int f^{a + \frac {b}{x^{2}}} x^{5}\, dx \]
[In]
[Out]
none
Time = 0.23 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.27 \[ \int f^{a+\frac {b}{x^2}} x^5 \, dx=-\frac {1}{2} \, b^{3} f^{a} \Gamma \left (-3, -\frac {b \log \left (f\right )}{x^{2}}\right ) \log \left (f\right )^{3} \]
[In]
[Out]
\[ \int f^{a+\frac {b}{x^2}} x^5 \, dx=\int { f^{a + \frac {b}{x^{2}}} x^{5} \,d x } \]
[In]
[Out]
Time = 0.29 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.85 \[ \int f^{a+\frac {b}{x^2}} x^5 \, dx=\frac {b^3\,f^a\,{\ln \left (f\right )}^3\,\left (f^{\frac {b}{x^2}}\,\left (\frac {x^2}{6\,b\,\ln \left (f\right )}+\frac {x^4}{6\,b^2\,{\ln \left (f\right )}^2}+\frac {x^6}{3\,b^3\,{\ln \left (f\right )}^3}\right )+\frac {\mathrm {expint}\left (-\frac {b\,\ln \left (f\right )}{x^2}\right )}{6}\right )}{2} \]
[In]
[Out]