Integrand size = 11, antiderivative size = 44 \[ \int f^{c (a+b x)^3} \, dx=-\frac {(a+b x) \Gamma \left (\frac {1}{3},-c (a+b x)^3 \log (f)\right )}{3 b \sqrt [3]{-c (a+b x)^3 \log (f)}} \]
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Time = 0.00 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {2239} \[ \int f^{c (a+b x)^3} \, dx=-\frac {(a+b x) \Gamma \left (\frac {1}{3},-c (a+b x)^3 \log (f)\right )}{3 b \sqrt [3]{-c \log (f) (a+b x)^3}} \]
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Rule 2239
Rubi steps \begin{align*} \text {integral}& = -\frac {(a+b x) \Gamma \left (\frac {1}{3},-c (a+b x)^3 \log (f)\right )}{3 b \sqrt [3]{-c (a+b x)^3 \log (f)}} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.00 \[ \int f^{c (a+b x)^3} \, dx=-\frac {(a+b x) \Gamma \left (\frac {1}{3},-c (a+b x)^3 \log (f)\right )}{3 b \sqrt [3]{-c (a+b x)^3 \log (f)}} \]
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\[\int f^{c \left (b x +a \right )^{3}}d x\]
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none
Time = 0.08 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.36 \[ \int f^{c (a+b x)^3} \, dx=\frac {\left (-b^{3} c \log \left (f\right )\right )^{\frac {2}{3}} \Gamma \left (\frac {1}{3}, -{\left (b^{3} c x^{3} + 3 \, a b^{2} c x^{2} + 3 \, a^{2} b c x + a^{3} c\right )} \log \left (f\right )\right )}{3 \, b^{3} c \log \left (f\right )} \]
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\[ \int f^{c (a+b x)^3} \, dx=\int f^{c \left (a + b x\right )^{3}}\, dx \]
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\[ \int f^{c (a+b x)^3} \, dx=\int { f^{{\left (b x + a\right )}^{3} c} \,d x } \]
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\[ \int f^{c (a+b x)^3} \, dx=\int { f^{{\left (b x + a\right )}^{3} c} \,d x } \]
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Timed out. \[ \int f^{c (a+b x)^3} \, dx=\int f^{c\,{\left (a+b\,x\right )}^3} \,d x \]
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