Integrand size = 33, antiderivative size = 183 \[ \int e^{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} x^4 \, dx=\frac {2 a^2 e^{(a+b x)^3}}{b^5}-\frac {a^4 (a+b x) \Gamma \left (\frac {1}{3},-(a+b x)^3\right )}{3 b^5 \sqrt [3]{-(a+b x)^3}}+\frac {4 a^3 (a+b x)^2 \Gamma \left (\frac {2}{3},-(a+b x)^3\right )}{3 b^5 \left (-(a+b x)^3\right )^{2/3}}+\frac {4 a (a+b x)^4 \Gamma \left (\frac {4}{3},-(a+b x)^3\right )}{3 b^5 \left (-(a+b x)^3\right )^{4/3}}-\frac {(a+b x)^5 \Gamma \left (\frac {5}{3},-(a+b x)^3\right )}{3 b^5 \left (-(a+b x)^3\right )^{5/3}} \]
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Time = 0.12 (sec) , antiderivative size = 183, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.152, Rules used = {2259, 2258, 2239, 2250, 2240} \[ \int e^{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} x^4 \, dx=-\frac {a^4 (a+b x) \Gamma \left (\frac {1}{3},-(a+b x)^3\right )}{3 b^5 \sqrt [3]{-(a+b x)^3}}+\frac {4 a^3 (a+b x)^2 \Gamma \left (\frac {2}{3},-(a+b x)^3\right )}{3 b^5 \left (-(a+b x)^3\right )^{2/3}}+\frac {2 a^2 e^{(a+b x)^3}}{b^5}-\frac {(a+b x)^5 \Gamma \left (\frac {5}{3},-(a+b x)^3\right )}{3 b^5 \left (-(a+b x)^3\right )^{5/3}}+\frac {4 a (a+b x)^4 \Gamma \left (\frac {4}{3},-(a+b x)^3\right )}{3 b^5 \left (-(a+b x)^3\right )^{4/3}} \]
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Rule 2239
Rule 2240
Rule 2250
Rule 2258
Rule 2259
Rubi steps \begin{align*} \text {integral}& = \int e^{(a+b x)^3} x^4 \, dx \\ & = \int \left (\frac {a^4 e^{(a+b x)^3}}{b^4}-\frac {4 a^3 e^{(a+b x)^3} (a+b x)}{b^4}+\frac {6 a^2 e^{(a+b x)^3} (a+b x)^2}{b^4}-\frac {4 a e^{(a+b x)^3} (a+b x)^3}{b^4}+\frac {e^{(a+b x)^3} (a+b x)^4}{b^4}\right ) \, dx \\ & = \frac {\int e^{(a+b x)^3} (a+b x)^4 \, dx}{b^4}-\frac {(4 a) \int e^{(a+b x)^3} (a+b x)^3 \, dx}{b^4}+\frac {\left (6 a^2\right ) \int e^{(a+b x)^3} (a+b x)^2 \, dx}{b^4}-\frac {\left (4 a^3\right ) \int e^{(a+b x)^3} (a+b x) \, dx}{b^4}+\frac {a^4 \int e^{(a+b x)^3} \, dx}{b^4} \\ & = \frac {2 a^2 e^{(a+b x)^3}}{b^5}-\frac {a^4 (a+b x) \Gamma \left (\frac {1}{3},-(a+b x)^3\right )}{3 b^5 \sqrt [3]{-(a+b x)^3}}+\frac {4 a^3 (a+b x)^2 \Gamma \left (\frac {2}{3},-(a+b x)^3\right )}{3 b^5 \left (-(a+b x)^3\right )^{2/3}}+\frac {4 a (a+b x)^4 \Gamma \left (\frac {4}{3},-(a+b x)^3\right )}{3 b^5 \left (-(a+b x)^3\right )^{4/3}}-\frac {(a+b x)^5 \Gamma \left (\frac {5}{3},-(a+b x)^3\right )}{3 b^5 \left (-(a+b x)^3\right )^{5/3}} \\ \end{align*}
Time = 0.40 (sec) , antiderivative size = 164, normalized size of antiderivative = 0.90 \[ \int e^{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} x^4 \, dx=\frac {6 a^2 e^{(a+b x)^3} \left (-(a+b x)^3\right )^{2/3}-a^4 (a+b x) \sqrt [3]{-(a+b x)^3} \Gamma \left (\frac {1}{3},-(a+b x)^3\right )+4 a^3 (a+b x)^2 \Gamma \left (\frac {2}{3},-(a+b x)^3\right )-4 a (a+b x) \sqrt [3]{-(a+b x)^3} \Gamma \left (\frac {4}{3},-(a+b x)^3\right )+(a+b x)^2 \Gamma \left (\frac {5}{3},-(a+b x)^3\right )}{3 b^5 \left (-(a+b x)^3\right )^{2/3}} \]
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\[\int {\mathrm e}^{b^{3} x^{3}+3 a \,b^{2} x^{2}+3 a^{2} b x +a^{3}} x^{4}d x\]
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none
Time = 0.08 (sec) , antiderivative size = 158, normalized size of antiderivative = 0.86 \[ \int e^{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} x^4 \, dx=-\frac {2 \, {\left (6 \, a^{3} + 1\right )} \left (-b^{3}\right )^{\frac {1}{3}} b \Gamma \left (\frac {2}{3}, -b^{3} x^{3} - 3 \, a b^{2} x^{2} - 3 \, a^{2} b x - a^{3}\right ) - {\left (3 \, a^{4} + 4 \, a\right )} \left (-b^{3}\right )^{\frac {2}{3}} \Gamma \left (\frac {1}{3}, -b^{3} x^{3} - 3 \, a b^{2} x^{2} - 3 \, a^{2} b x - a^{3}\right ) - 3 \, {\left (b^{4} x^{2} - 2 \, a b^{3} x + 3 \, a^{2} b^{2}\right )} e^{\left (b^{3} x^{3} + 3 \, a b^{2} x^{2} + 3 \, a^{2} b x + a^{3}\right )}}{9 \, b^{7}} \]
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\[ \int e^{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} x^4 \, dx=e^{a^{3}} \int x^{4} e^{b^{3} x^{3}} e^{3 a b^{2} x^{2}} e^{3 a^{2} b x}\, dx \]
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\[ \int e^{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} x^4 \, dx=\int { x^{4} e^{\left (b^{3} x^{3} + 3 \, a b^{2} x^{2} + 3 \, a^{2} b x + a^{3}\right )} \,d x } \]
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\[ \int e^{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} x^4 \, dx=\int { x^{4} e^{\left (b^{3} x^{3} + 3 \, a b^{2} x^{2} + 3 \, a^{2} b x + a^{3}\right )} \,d x } \]
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Timed out. \[ \int e^{a^3+3 a^2 b x+3 a b^2 x^2+b^3 x^3} x^4 \, dx=\int x^4\,{\mathrm {e}}^{a^3+3\,a^2\,b\,x+3\,a\,b^2\,x^2+b^3\,x^3} \,d x \]
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