Integrand size = 21, antiderivative size = 22 \[ \int \frac {F^{a+b (c+d x)^2}}{c+d x} \, dx=\frac {F^a \operatorname {ExpIntegralEi}\left (b (c+d x)^2 \log (F)\right )}{2 d} \]
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Time = 0.04 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {2241} \[ \int \frac {F^{a+b (c+d x)^2}}{c+d x} \, dx=\frac {F^a \operatorname {ExpIntegralEi}\left (b (c+d x)^2 \log (F)\right )}{2 d} \]
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Rule 2241
Rubi steps \begin{align*} \text {integral}& = \frac {F^a \text {Ei}\left (b (c+d x)^2 \log (F)\right )}{2 d} \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00 \[ \int \frac {F^{a+b (c+d x)^2}}{c+d x} \, dx=\frac {F^a \operatorname {ExpIntegralEi}\left (b (c+d x)^2 \log (F)\right )}{2 d} \]
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Time = 0.31 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.05
method | result | size |
risch | \(-\frac {F^{a} \operatorname {Ei}_{1}\left (-b \left (d x +c \right )^{2} \ln \left (F \right )\right )}{2 d}\) | \(23\) |
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none
Time = 0.30 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.45 \[ \int \frac {F^{a+b (c+d x)^2}}{c+d x} \, dx=\frac {F^{a} {\rm Ei}\left ({\left (b d^{2} x^{2} + 2 \, b c d x + b c^{2}\right )} \log \left (F\right )\right )}{2 \, d} \]
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\[ \int \frac {F^{a+b (c+d x)^2}}{c+d x} \, dx=\int \frac {F^{a + b \left (c + d x\right )^{2}}}{c + d x}\, dx \]
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\[ \int \frac {F^{a+b (c+d x)^2}}{c+d x} \, dx=\int { \frac {F^{{\left (d x + c\right )}^{2} b + a}}{d x + c} \,d x } \]
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\[ \int \frac {F^{a+b (c+d x)^2}}{c+d x} \, dx=\int { \frac {F^{{\left (d x + c\right )}^{2} b + a}}{d x + c} \,d x } \]
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Time = 0.30 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.91 \[ \int \frac {F^{a+b (c+d x)^2}}{c+d x} \, dx=\frac {F^a\,\mathrm {ei}\left (b\,\ln \left (F\right )\,{\left (c+d\,x\right )}^2\right )}{2\,d} \]
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