Integrand size = 21, antiderivative size = 31 \[ \int \frac {F^{a+b (c+d x)^3}}{(c+d x)^{13}} \, dx=-\frac {b^4 F^a \Gamma \left (-4,-b (c+d x)^3 \log (F)\right ) \log ^4(F)}{3 d} \]
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Time = 0.04 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {2250} \[ \int \frac {F^{a+b (c+d x)^3}}{(c+d x)^{13}} \, dx=-\frac {b^4 F^a \log ^4(F) \Gamma \left (-4,-b (c+d x)^3 \log (F)\right )}{3 d} \]
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Rule 2250
Rubi steps \begin{align*} \text {integral}& = -\frac {b^4 F^a \Gamma \left (-4,-b (c+d x)^3 \log (F)\right ) \log ^4(F)}{3 d} \\ \end{align*}
Time = 0.19 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.00 \[ \int \frac {F^{a+b (c+d x)^3}}{(c+d x)^{13}} \, dx=-\frac {b^4 F^a \Gamma \left (-4,-b (c+d x)^3 \log (F)\right ) \log ^4(F)}{3 d} \]
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\[\int \frac {F^{a +b \left (d x +c \right )^{3}}}{\left (d x +c \right )^{13}}d x\]
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Leaf count of result is larger than twice the leaf count of optimal. 636 vs. \(2 (29) = 58\).
Time = 0.29 (sec) , antiderivative size = 636, normalized size of antiderivative = 20.52 \[ \int \frac {F^{a+b (c+d x)^3}}{(c+d x)^{13}} \, dx=\frac {{\left (b^{4} d^{12} x^{12} + 12 \, b^{4} c d^{11} x^{11} + 66 \, b^{4} c^{2} d^{10} x^{10} + 220 \, b^{4} c^{3} d^{9} x^{9} + 495 \, b^{4} c^{4} d^{8} x^{8} + 792 \, b^{4} c^{5} d^{7} x^{7} + 924 \, b^{4} c^{6} d^{6} x^{6} + 792 \, b^{4} c^{7} d^{5} x^{5} + 495 \, b^{4} c^{8} d^{4} x^{4} + 220 \, b^{4} c^{9} d^{3} x^{3} + 66 \, b^{4} c^{10} d^{2} x^{2} + 12 \, b^{4} c^{11} d x + b^{4} c^{12}\right )} F^{a} {\rm Ei}\left ({\left (b d^{3} x^{3} + 3 \, b c d^{2} x^{2} + 3 \, b c^{2} d x + b c^{3}\right )} \log \left (F\right )\right ) \log \left (F\right )^{4} - {\left ({\left (b^{3} d^{9} x^{9} + 9 \, b^{3} c d^{8} x^{8} + 36 \, b^{3} c^{2} d^{7} x^{7} + 84 \, b^{3} c^{3} d^{6} x^{6} + 126 \, b^{3} c^{4} d^{5} x^{5} + 126 \, b^{3} c^{5} d^{4} x^{4} + 84 \, b^{3} c^{6} d^{3} x^{3} + 36 \, b^{3} c^{7} d^{2} x^{2} + 9 \, b^{3} c^{8} d x + b^{3} c^{9}\right )} \log \left (F\right )^{3} + {\left (b^{2} d^{6} x^{6} + 6 \, b^{2} c d^{5} x^{5} + 15 \, b^{2} c^{2} d^{4} x^{4} + 20 \, b^{2} c^{3} d^{3} x^{3} + 15 \, b^{2} c^{4} d^{2} x^{2} + 6 \, b^{2} c^{5} d x + b^{2} c^{6}\right )} \log \left (F\right )^{2} + 2 \, {\left (b d^{3} x^{3} + 3 \, b c d^{2} x^{2} + 3 \, b c^{2} d x + b c^{3}\right )} \log \left (F\right ) + 6\right )} F^{b d^{3} x^{3} + 3 \, b c d^{2} x^{2} + 3 \, b c^{2} d x + b c^{3} + a}}{72 \, {\left (d^{13} x^{12} + 12 \, c d^{12} x^{11} + 66 \, c^{2} d^{11} x^{10} + 220 \, c^{3} d^{10} x^{9} + 495 \, c^{4} d^{9} x^{8} + 792 \, c^{5} d^{8} x^{7} + 924 \, c^{6} d^{7} x^{6} + 792 \, c^{7} d^{6} x^{5} + 495 \, c^{8} d^{5} x^{4} + 220 \, c^{9} d^{4} x^{3} + 66 \, c^{10} d^{3} x^{2} + 12 \, c^{11} d^{2} x + c^{12} d\right )}} \]
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\[ \int \frac {F^{a+b (c+d x)^3}}{(c+d x)^{13}} \, dx=\int \frac {F^{a + b \left (c + d x\right )^{3}}}{\left (c + d x\right )^{13}}\, dx \]
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\[ \int \frac {F^{a+b (c+d x)^3}}{(c+d x)^{13}} \, dx=\int { \frac {F^{{\left (d x + c\right )}^{3} b + a}}{{\left (d x + c\right )}^{13}} \,d x } \]
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\[ \int \frac {F^{a+b (c+d x)^3}}{(c+d x)^{13}} \, dx=\int { \frac {F^{{\left (d x + c\right )}^{3} b + a}}{{\left (d x + c\right )}^{13}} \,d x } \]
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Time = 0.72 (sec) , antiderivative size = 120, normalized size of antiderivative = 3.87 \[ \int \frac {F^{a+b (c+d x)^3}}{(c+d x)^{13}} \, dx=-\frac {F^a\,b^4\,{\ln \left (F\right )}^4\,\mathrm {expint}\left (-b\,\ln \left (F\right )\,{\left (c+d\,x\right )}^3\right )}{72\,d}-\frac {F^a\,F^{b\,{\left (c+d\,x\right )}^3}\,b^4\,{\ln \left (F\right )}^4\,\left (\frac {1}{24\,b\,\ln \left (F\right )\,{\left (c+d\,x\right )}^3}+\frac {1}{24\,b^2\,{\ln \left (F\right )}^2\,{\left (c+d\,x\right )}^6}+\frac {1}{12\,b^3\,{\ln \left (F\right )}^3\,{\left (c+d\,x\right )}^9}+\frac {1}{4\,b^4\,{\ln \left (F\right )}^4\,{\left (c+d\,x\right )}^{12}}\right )}{3\,d} \]
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