Integrand size = 21, antiderivative size = 27 \[ \int \frac {F^{a+\frac {b}{(c+d x)^3}}}{(c+d x)^4} \, dx=-\frac {F^{a+\frac {b}{(c+d x)^3}}}{3 b d \log (F)} \]
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Time = 0.03 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {2240} \[ \int \frac {F^{a+\frac {b}{(c+d x)^3}}}{(c+d x)^4} \, dx=-\frac {F^{a+\frac {b}{(c+d x)^3}}}{3 b d \log (F)} \]
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Rule 2240
Rubi steps \begin{align*} \text {integral}& = -\frac {F^{a+\frac {b}{(c+d x)^3}}}{3 b d \log (F)} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00 \[ \int \frac {F^{a+\frac {b}{(c+d x)^3}}}{(c+d x)^4} \, dx=-\frac {F^{a+\frac {b}{(c+d x)^3}}}{3 b d \log (F)} \]
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Time = 0.62 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.96
method | result | size |
derivativedivides | \(-\frac {F^{a +\frac {b}{\left (d x +c \right )^{3}}}}{3 b d \ln \left (F \right )}\) | \(26\) |
default | \(-\frac {F^{a +\frac {b}{\left (d x +c \right )^{3}}}}{3 b d \ln \left (F \right )}\) | \(26\) |
parallelrisch | \(-\frac {F^{a +\frac {b}{\left (d x +c \right )^{3}}}}{3 b d \ln \left (F \right )}\) | \(26\) |
risch | \(-\frac {F^{\frac {a \,d^{3} x^{3}+3 a c \,d^{2} x^{2}+3 a \,c^{2} d x +a \,c^{3}+b}{\left (d x +c \right )^{3}}}}{3 b d \ln \left (F \right )}\) | \(56\) |
norman | \(\frac {-\frac {c^{3} {\mathrm e}^{\left (a +\frac {b}{\left (d x +c \right )^{3}}\right ) \ln \left (F \right )}}{3 \ln \left (F \right ) b d}-\frac {c^{2} x \,{\mathrm e}^{\left (a +\frac {b}{\left (d x +c \right )^{3}}\right ) \ln \left (F \right )}}{\ln \left (F \right ) b}-\frac {d^{2} x^{3} {\mathrm e}^{\left (a +\frac {b}{\left (d x +c \right )^{3}}\right ) \ln \left (F \right )}}{3 \ln \left (F \right ) b}-\frac {d c \,x^{2} {\mathrm e}^{\left (a +\frac {b}{\left (d x +c \right )^{3}}\right ) \ln \left (F \right )}}{\ln \left (F \right ) b}}{\left (d x +c \right )^{3}}\) | \(127\) |
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Leaf count of result is larger than twice the leaf count of optimal. 77 vs. \(2 (25) = 50\).
Time = 0.40 (sec) , antiderivative size = 77, normalized size of antiderivative = 2.85 \[ \int \frac {F^{a+\frac {b}{(c+d x)^3}}}{(c+d x)^4} \, dx=-\frac {F^{\frac {a d^{3} x^{3} + 3 \, a c d^{2} x^{2} + 3 \, a c^{2} d x + a c^{3} + b}{d^{3} x^{3} + 3 \, c d^{2} x^{2} + 3 \, c^{2} d x + c^{3}}}}{3 \, b d \log \left (F\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 65 vs. \(2 (20) = 40\).
Time = 0.18 (sec) , antiderivative size = 65, normalized size of antiderivative = 2.41 \[ \int \frac {F^{a+\frac {b}{(c+d x)^3}}}{(c+d x)^4} \, dx=\begin {cases} - \frac {F^{a + \frac {b}{\left (c + d x\right )^{3}}}}{3 b d \log {\left (F \right )}} & \text {for}\: b d \log {\left (F \right )} \neq 0 \\- \frac {1}{3 c^{3} d + 9 c^{2} d^{2} x + 9 c d^{3} x^{2} + 3 d^{4} x^{3}} & \text {otherwise} \end {cases} \]
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none
Time = 0.21 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.93 \[ \int \frac {F^{a+\frac {b}{(c+d x)^3}}}{(c+d x)^4} \, dx=-\frac {F^{a + \frac {b}{{\left (d x + c\right )}^{3}}}}{3 \, b d \log \left (F\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 77 vs. \(2 (25) = 50\).
Time = 0.34 (sec) , antiderivative size = 77, normalized size of antiderivative = 2.85 \[ \int \frac {F^{a+\frac {b}{(c+d x)^3}}}{(c+d x)^4} \, dx=-\frac {F^{\frac {a d^{3} x^{3} + 3 \, a c d^{2} x^{2} + 3 \, a c^{2} d x + a c^{3} + b}{d^{3} x^{3} + 3 \, c d^{2} x^{2} + 3 \, c^{2} d x + c^{3}}}}{3 \, b d \log \left (F\right )} \]
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Time = 0.31 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.78 \[ \int \frac {F^{a+\frac {b}{(c+d x)^3}}}{(c+d x)^4} \, dx=-\frac {F^a\,F^{\frac {b}{c^3+3\,c^2\,d\,x+3\,c\,d^2\,x^2+d^3\,x^3}}}{3\,b\,d\,\ln \left (F\right )} \]
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