Integrand size = 19, antiderivative size = 177 \[ \int e^{e (c+d x)^3} (a+b x)^3 \, dx=-\frac {b^2 (b c-a d) e^{e (c+d x)^3}}{d^4 e}+\frac {(b c-a d)^3 (c+d x) \Gamma \left (\frac {1}{3},-e (c+d x)^3\right )}{3 d^4 \sqrt [3]{-e (c+d x)^3}}-\frac {b (b c-a d)^2 (c+d x)^2 \Gamma \left (\frac {2}{3},-e (c+d x)^3\right )}{d^4 \left (-e (c+d x)^3\right )^{2/3}}-\frac {b^3 (c+d x)^4 \Gamma \left (\frac {4}{3},-e (c+d x)^3\right )}{3 d^4 \left (-e (c+d x)^3\right )^{4/3}} \]
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Time = 0.10 (sec) , antiderivative size = 177, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {2258, 2239, 2250, 2240} \[ \int e^{e (c+d x)^3} (a+b x)^3 \, dx=-\frac {b^2 (b c-a d) e^{e (c+d x)^3}}{d^4 e}-\frac {b (c+d x)^2 (b c-a d)^2 \Gamma \left (\frac {2}{3},-e (c+d x)^3\right )}{d^4 \left (-e (c+d x)^3\right )^{2/3}}+\frac {(c+d x) (b c-a d)^3 \Gamma \left (\frac {1}{3},-e (c+d x)^3\right )}{3 d^4 \sqrt [3]{-e (c+d x)^3}}-\frac {b^3 (c+d x)^4 \Gamma \left (\frac {4}{3},-e (c+d x)^3\right )}{3 d^4 \left (-e (c+d x)^3\right )^{4/3}} \]
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Rule 2239
Rule 2240
Rule 2250
Rule 2258
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {(-b c+a d)^3 e^{e (c+d x)^3}}{d^3}+\frac {3 b (b c-a d)^2 e^{e (c+d x)^3} (c+d x)}{d^3}-\frac {3 b^2 (b c-a d) e^{e (c+d x)^3} (c+d x)^2}{d^3}+\frac {b^3 e^{e (c+d x)^3} (c+d x)^3}{d^3}\right ) \, dx \\ & = \frac {b^3 \int e^{e (c+d x)^3} (c+d x)^3 \, dx}{d^3}-\frac {\left (3 b^2 (b c-a d)\right ) \int e^{e (c+d x)^3} (c+d x)^2 \, dx}{d^3}+\frac {\left (3 b (b c-a d)^2\right ) \int e^{e (c+d x)^3} (c+d x) \, dx}{d^3}-\frac {(b c-a d)^3 \int e^{e (c+d x)^3} \, dx}{d^3} \\ & = -\frac {b^2 (b c-a d) e^{e (c+d x)^3}}{d^4 e}+\frac {(b c-a d)^3 (c+d x) \Gamma \left (\frac {1}{3},-e (c+d x)^3\right )}{3 d^4 \sqrt [3]{-e (c+d x)^3}}-\frac {b (b c-a d)^2 (c+d x)^2 \Gamma \left (\frac {2}{3},-e (c+d x)^3\right )}{d^4 \left (-e (c+d x)^3\right )^{2/3}}-\frac {b^3 (c+d x)^4 \Gamma \left (\frac {4}{3},-e (c+d x)^3\right )}{3 d^4 \left (-e (c+d x)^3\right )^{4/3}} \\ \end{align*}
Time = 0.46 (sec) , antiderivative size = 167, normalized size of antiderivative = 0.94 \[ \int e^{e (c+d x)^3} (a+b x)^3 \, dx=\frac {-\frac {3 b^2 (b c-a d) e^{e (c+d x)^3}}{e}+\frac {(b c-a d)^3 (c+d x) \Gamma \left (\frac {1}{3},-e (c+d x)^3\right )}{\sqrt [3]{-e (c+d x)^3}}-\frac {3 b (b c-a d)^2 (c+d x)^2 \Gamma \left (\frac {2}{3},-e (c+d x)^3\right )}{\left (-e (c+d x)^3\right )^{2/3}}+\frac {b^3 (c+d x) \Gamma \left (\frac {4}{3},-e (c+d x)^3\right )}{e \sqrt [3]{-e (c+d x)^3}}}{3 d^4} \]
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\[\int {\mathrm e}^{e \left (d x +c \right )^{3}} \left (b x +a \right )^{3}d x\]
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none
Time = 0.09 (sec) , antiderivative size = 239, normalized size of antiderivative = 1.35 \[ \int e^{e (c+d x)^3} (a+b x)^3 \, dx=\frac {9 \, {\left (b^{3} c^{2} d - 2 \, a b^{2} c d^{2} + a^{2} b d^{3}\right )} \left (-d^{3} e\right )^{\frac {1}{3}} e \Gamma \left (\frac {2}{3}, -d^{3} e x^{3} - 3 \, c d^{2} e x^{2} - 3 \, c^{2} d e x - c^{3} e\right ) - \left (-d^{3} e\right )^{\frac {2}{3}} {\left (b^{3} + 3 \, {\left (b^{3} c^{3} - 3 \, a b^{2} c^{2} d + 3 \, a^{2} b c d^{2} - a^{3} d^{3}\right )} e\right )} \Gamma \left (\frac {1}{3}, -d^{3} e x^{3} - 3 \, c d^{2} e x^{2} - 3 \, c^{2} d e x - c^{3} e\right ) + 3 \, {\left (b^{3} d^{3} e x - {\left (2 \, b^{3} c d^{2} - 3 \, a b^{2} d^{3}\right )} e\right )} e^{\left (d^{3} e x^{3} + 3 \, c d^{2} e x^{2} + 3 \, c^{2} d e x + c^{3} e\right )}}{9 \, d^{6} e^{2}} \]
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\[ \int e^{e (c+d x)^3} (a+b x)^3 \, dx=\left (\int a^{3} e^{d^{3} e x^{3}} e^{3 c d^{2} e x^{2}} e^{3 c^{2} d e x}\, dx + \int b^{3} x^{3} e^{d^{3} e x^{3}} e^{3 c d^{2} e x^{2}} e^{3 c^{2} d e x}\, dx + \int 3 a b^{2} x^{2} e^{d^{3} e x^{3}} e^{3 c d^{2} e x^{2}} e^{3 c^{2} d e x}\, dx + \int 3 a^{2} b x e^{d^{3} e x^{3}} e^{3 c d^{2} e x^{2}} e^{3 c^{2} d e x}\, dx\right ) e^{c^{3} e} \]
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\[ \int e^{e (c+d x)^3} (a+b x)^3 \, dx=\int { {\left (b x + a\right )}^{3} e^{\left ({\left (d x + c\right )}^{3} e\right )} \,d x } \]
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\[ \int e^{e (c+d x)^3} (a+b x)^3 \, dx=\int { {\left (b x + a\right )}^{3} e^{\left ({\left (d x + c\right )}^{3} e\right )} \,d x } \]
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Timed out. \[ \int e^{e (c+d x)^3} (a+b x)^3 \, dx=\int {\mathrm {e}}^{e\,{\left (c+d\,x\right )}^3}\,{\left (a+b\,x\right )}^3 \,d x \]
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