Integrand size = 21, antiderivative size = 39 \[ \int \frac {f^{a+b x+c x^2}}{b+2 c x} \, dx=\frac {f^{a-\frac {b^2}{4 c}} \operatorname {ExpIntegralEi}\left (\frac {(b+2 c x)^2 \log (f)}{4 c}\right )}{4 c} \]
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Time = 0.02 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {2270} \[ \int \frac {f^{a+b x+c x^2}}{b+2 c x} \, dx=\frac {f^{a-\frac {b^2}{4 c}} \operatorname {ExpIntegralEi}\left (\frac {(b+2 c x)^2 \log (f)}{4 c}\right )}{4 c} \]
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Rule 2270
Rubi steps \begin{align*} \text {integral}& = \frac {f^{a-\frac {b^2}{4 c}} \text {Ei}\left (\frac {(b+2 c x)^2 \log (f)}{4 c}\right )}{4 c} \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.00 \[ \int \frac {f^{a+b x+c x^2}}{b+2 c x} \, dx=\frac {f^{a-\frac {b^2}{4 c}} \operatorname {ExpIntegralEi}\left (\frac {(b+2 c x)^2 \log (f)}{4 c}\right )}{4 c} \]
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Time = 0.29 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.03
method | result | size |
risch | \(-\frac {f^{\frac {4 c a -b^{2}}{4 c}} \operatorname {Ei}_{1}\left (-\frac {\left (2 x c +b \right )^{2} \ln \left (f \right )}{4 c}\right )}{4 c}\) | \(40\) |
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none
Time = 0.33 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.21 \[ \int \frac {f^{a+b x+c x^2}}{b+2 c x} \, dx=\frac {{\rm Ei}\left (\frac {{\left (4 \, c^{2} x^{2} + 4 \, b c x + b^{2}\right )} \log \left (f\right )}{4 \, c}\right )}{4 \, c f^{\frac {b^{2} - 4 \, a c}{4 \, c}}} \]
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\[ \int \frac {f^{a+b x+c x^2}}{b+2 c x} \, dx=\int \frac {f^{a + b x + c x^{2}}}{b + 2 c x}\, dx \]
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\[ \int \frac {f^{a+b x+c x^2}}{b+2 c x} \, dx=\int { \frac {f^{c x^{2} + b x + a}}{2 \, c x + b} \,d x } \]
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\[ \int \frac {f^{a+b x+c x^2}}{b+2 c x} \, dx=\int { \frac {f^{c x^{2} + b x + a}}{2 \, c x + b} \,d x } \]
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Timed out. \[ \int \frac {f^{a+b x+c x^2}}{b+2 c x} \, dx=\int \frac {f^{c\,x^2+b\,x+a}}{b+2\,c\,x} \,d x \]
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