Integrand size = 15, antiderivative size = 43 \[ \int \frac {2^x}{a+4^{-x} b} \, dx=\frac {2^x}{a \log (2)}-\frac {\sqrt {b} \arctan \left (\frac {2^x \sqrt {a}}{\sqrt {b}}\right )}{a^{3/2} \log (2)} \]
[Out]
Time = 0.03 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {2281, 199, 327, 211} \[ \int \frac {2^x}{a+4^{-x} b} \, dx=\frac {2^x}{a \log (2)}-\frac {\sqrt {b} \arctan \left (\frac {\sqrt {a} 2^x}{\sqrt {b}}\right )}{a^{3/2} \log (2)} \]
[In]
[Out]
Rule 199
Rule 211
Rule 327
Rule 2281
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1}{a+\frac {b}{x^2}} \, dx,x,2^x\right )}{\log (2)} \\ & = \frac {\text {Subst}\left (\int \frac {x^2}{b+a x^2} \, dx,x,2^x\right )}{\log (2)} \\ & = \frac {2^x}{a \log (2)}-\frac {b \text {Subst}\left (\int \frac {1}{b+a x^2} \, dx,x,2^x\right )}{a \log (2)} \\ & = \frac {2^x}{a \log (2)}-\frac {\sqrt {b} \tan ^{-1}\left (\frac {2^x \sqrt {a}}{\sqrt {b}}\right )}{a^{3/2} \log (2)} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.93 \[ \int \frac {2^x}{a+4^{-x} b} \, dx=\frac {\frac {2^x}{a}-\frac {\sqrt {b} \arctan \left (\frac {2^x \sqrt {a}}{\sqrt {b}}\right )}{a^{3/2}}}{\log (2)} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. \(73\) vs. \(2(35)=70\).
Time = 0.07 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.72
method | result | size |
risch | \(\frac {2^{x}}{a \ln \left (2\right )}+\frac {\sqrt {-a b}\, \ln \left (2^{x}-\frac {\sqrt {-a b}}{a}\right )}{2 a^{2} \ln \left (2\right )}-\frac {\sqrt {-a b}\, \ln \left (2^{x}+\frac {\sqrt {-a b}}{a}\right )}{2 a^{2} \ln \left (2\right )}\) | \(74\) |
[In]
[Out]
none
Time = 0.32 (sec) , antiderivative size = 102, normalized size of antiderivative = 2.37 \[ \int \frac {2^x}{a+4^{-x} b} \, dx=\left [\frac {\sqrt {-\frac {b}{a}} \log \left (-\frac {2 \cdot 2^{x} a \sqrt {-\frac {b}{a}} - 2^{2 \, x} a + b}{2^{2 \, x} a + b}\right ) + 2 \cdot 2^{x}}{2 \, a \log \left (2\right )}, -\frac {\sqrt {\frac {b}{a}} \arctan \left (\frac {2^{x} a \sqrt {\frac {b}{a}}}{b}\right ) - 2^{x}}{a \log \left (2\right )}\right ] \]
[In]
[Out]
Time = 0.26 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.26 \[ \int \frac {2^x}{a+4^{-x} b} \, dx=\begin {cases} \frac {e^{\frac {x \log {\left (4 \right )}}{2}}}{a \log {\left (2 \right )}} & \text {for}\: a \log {\left (2 \right )} \neq 0 \\\frac {x}{a} & \text {otherwise} \end {cases} + \frac {\operatorname {RootSum} {\left (4 z^{2} a^{3} + b, \left ( i \mapsto i \log {\left (\frac {2 i a^{2}}{b} + e^{- \frac {x \log {\left (4 \right )}}{2}} \right )} \right )\right )}}{\log {\left (2 \right )}} \]
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.58 \[ \int \frac {2^x}{a+4^{-x} b} \, dx=\frac {b \arctan \left (\frac {b}{\sqrt {a b} 2^{x}}\right )}{\sqrt {a b} a \log \left (2\right )} + \frac {4^{\frac {1}{2} \, x} a + \frac {b}{4^{\frac {1}{2} \, x}}}{a^{2} \log \left (2\right )} - \frac {b}{2^{x} a^{2} \log \left (2\right )} \]
[In]
[Out]
\[ \int \frac {2^x}{a+4^{-x} b} \, dx=\int { \frac {2^{x}}{a + \frac {b}{4^{x}}} \,d x } \]
[In]
[Out]
Time = 0.29 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.81 \[ \int \frac {2^x}{a+4^{-x} b} \, dx=\frac {2^x}{a\,\ln \left (2\right )}-\frac {\sqrt {b}\,\mathrm {atan}\left (\frac {2^x\,\sqrt {a}}{\sqrt {b}}\right )}{a^{3/2}\,\ln \left (2\right )} \]
[In]
[Out]