Integrand size = 15, antiderivative size = 31 \[ \int \frac {2^x}{\sqrt {a+4^x b}} \, dx=\frac {\text {arctanh}\left (\frac {2^x \sqrt {b}}{\sqrt {a+4^x b}}\right )}{\sqrt {b} \log (2)} \]
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Time = 0.03 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2281, 223, 212} \[ \int \frac {2^x}{\sqrt {a+4^x b}} \, dx=\frac {\text {arctanh}\left (\frac {\sqrt {b} 2^x}{\sqrt {a+b 4^x}}\right )}{\sqrt {b} \log (2)} \]
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Rule 212
Rule 223
Rule 2281
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1}{\sqrt {a+b x^2}} \, dx,x,2^x\right )}{\log (2)} \\ & = \frac {\text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {2^x}{\sqrt {a+4^x b}}\right )}{\log (2)} \\ & = \frac {\tanh ^{-1}\left (\frac {2^x \sqrt {b}}{\sqrt {a+4^x b}}\right )}{\sqrt {b} \log (2)} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.06 \[ \int \frac {2^x}{\sqrt {a+4^x b}} \, dx=\frac {\text {arctanh}\left (\frac {2^x \sqrt {b}}{\sqrt {a+2^{2 x} b}}\right )}{\sqrt {b} \log (2)} \]
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\[\int \frac {2^{x}}{\sqrt {a +4^{x} b}}d x\]
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none
Time = 0.32 (sec) , antiderivative size = 77, normalized size of antiderivative = 2.48 \[ \int \frac {2^x}{\sqrt {a+4^x b}} \, dx=\left [\frac {\log \left (-2 \, \sqrt {2^{2 \, x} b + a} 2^{x} \sqrt {b} - 2 \cdot 2^{2 \, x} b - a\right )}{2 \, \sqrt {b} \log \left (2\right )}, -\frac {\sqrt {-b} \arctan \left (\frac {2^{x} \sqrt {-b}}{\sqrt {2^{2 \, x} b + a}}\right )}{b \log \left (2\right )}\right ] \]
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Time = 0.42 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.97 \[ \int \frac {2^x}{\sqrt {a+4^x b}} \, dx=\frac {\begin {cases} \frac {\log {\left (2 \cdot 2^{x} b + 2 \sqrt {b} \sqrt {2^{2 x} b + a} \right )}}{\sqrt {b}} & \text {for}\: a \neq 0 \wedge b \neq 0 \\\frac {2^{x} \log {\left (2^{x} \right )}}{\sqrt {2^{2 x} b}} & \text {for}\: b \neq 0 \\\frac {2^{x}}{\sqrt {a}} & \text {otherwise} \end {cases}}{\log {\left (2 \right )}} \]
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\[ \int \frac {2^x}{\sqrt {a+4^x b}} \, dx=\int { \frac {2^{x}}{\sqrt {4^{x} b + a}} \,d x } \]
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\[ \int \frac {2^x}{\sqrt {a+4^x b}} \, dx=\int { \frac {2^{x}}{\sqrt {4^{x} b + a}} \,d x } \]
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Time = 0.46 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.90 \[ \int \frac {2^x}{\sqrt {a+4^x b}} \, dx=\frac {\ln \left (\sqrt {a+2^{2\,x}\,b}+2^x\,\sqrt {b}\right )}{\sqrt {b}\,\ln \left (2\right )} \]
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