Integrand size = 18, antiderivative size = 276 \[ \int \frac {x}{a+b e^x+c e^{2 x}} \, dx=-\frac {c x^2}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {c x^2}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c e^x}{b-\sqrt {b^2-4 a c}}\right )}{b^2-4 a c-b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c e^x}{b+\sqrt {b^2-4 a c}}\right )}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {2 c \operatorname {PolyLog}\left (2,-\frac {2 c e^x}{b-\sqrt {b^2-4 a c}}\right )}{b^2-4 a c-b \sqrt {b^2-4 a c}}+\frac {2 c \operatorname {PolyLog}\left (2,-\frac {2 c e^x}{b+\sqrt {b^2-4 a c}}\right )}{b^2-4 a c+b \sqrt {b^2-4 a c}} \]
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Time = 0.25 (sec) , antiderivative size = 276, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {2295, 2215, 2221, 2317, 2438} \[ \int \frac {x}{a+b e^x+c e^{2 x}} \, dx=\frac {2 c \operatorname {PolyLog}\left (2,-\frac {2 c e^x}{b-\sqrt {b^2-4 a c}}\right )}{-b \sqrt {b^2-4 a c}-4 a c+b^2}+\frac {2 c \operatorname {PolyLog}\left (2,-\frac {2 c e^x}{b+\sqrt {b^2-4 a c}}\right )}{b \sqrt {b^2-4 a c}-4 a c+b^2}-\frac {c x^2}{-b \sqrt {b^2-4 a c}-4 a c+b^2}-\frac {c x^2}{b \sqrt {b^2-4 a c}-4 a c+b^2}+\frac {2 c x \log \left (\frac {2 c e^x}{b-\sqrt {b^2-4 a c}}+1\right )}{-b \sqrt {b^2-4 a c}-4 a c+b^2}+\frac {2 c x \log \left (\frac {2 c e^x}{\sqrt {b^2-4 a c}+b}+1\right )}{b \sqrt {b^2-4 a c}-4 a c+b^2} \]
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Rule 2215
Rule 2221
Rule 2295
Rule 2317
Rule 2438
Rubi steps \begin{align*} \text {integral}& = \frac {(2 c) \int \frac {x}{b-\sqrt {b^2-4 a c}+2 c e^x} \, dx}{\sqrt {b^2-4 a c}}-\frac {(2 c) \int \frac {x}{b+\sqrt {b^2-4 a c}+2 c e^x} \, dx}{\sqrt {b^2-4 a c}} \\ & = -\frac {c x^2}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {c x^2}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {\left (4 c^2\right ) \int \frac {e^x x}{b-\sqrt {b^2-4 a c}+2 c e^x} \, dx}{b^2-4 a c-b \sqrt {b^2-4 a c}}+\frac {\left (4 c^2\right ) \int \frac {e^x x}{b+\sqrt {b^2-4 a c}+2 c e^x} \, dx}{b^2-4 a c+b \sqrt {b^2-4 a c}} \\ & = -\frac {c x^2}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {c x^2}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c e^x}{b-\sqrt {b^2-4 a c}}\right )}{b^2-4 a c-b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c e^x}{b+\sqrt {b^2-4 a c}}\right )}{b^2-4 a c+b \sqrt {b^2-4 a c}}-\frac {(2 c) \int \log \left (1+\frac {2 c e^x}{b-\sqrt {b^2-4 a c}}\right ) \, dx}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {(2 c) \int \log \left (1+\frac {2 c e^x}{b+\sqrt {b^2-4 a c}}\right ) \, dx}{b^2-4 a c+b \sqrt {b^2-4 a c}} \\ & = -\frac {c x^2}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {c x^2}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c e^x}{b-\sqrt {b^2-4 a c}}\right )}{b^2-4 a c-b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c e^x}{b+\sqrt {b^2-4 a c}}\right )}{b^2-4 a c+b \sqrt {b^2-4 a c}}-\frac {(2 c) \text {Subst}\left (\int \frac {\log \left (1+\frac {2 c x}{b-\sqrt {b^2-4 a c}}\right )}{x} \, dx,x,e^x\right )}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {(2 c) \text {Subst}\left (\int \frac {\log \left (1+\frac {2 c x}{b+\sqrt {b^2-4 a c}}\right )}{x} \, dx,x,e^x\right )}{b^2-4 a c+b \sqrt {b^2-4 a c}} \\ & = -\frac {c x^2}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {c x^2}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c e^x}{b-\sqrt {b^2-4 a c}}\right )}{b^2-4 a c-b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c e^x}{b+\sqrt {b^2-4 a c}}\right )}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {2 c \text {Li}_2\left (-\frac {2 c e^x}{b-\sqrt {b^2-4 a c}}\right )}{b^2-4 a c-b \sqrt {b^2-4 a c}}+\frac {2 c \text {Li}_2\left (-\frac {2 c e^x}{b+\sqrt {b^2-4 a c}}\right )}{b^2-4 a c+b \sqrt {b^2-4 a c}} \\ \end{align*}
Time = 0.16 (sec) , antiderivative size = 205, normalized size of antiderivative = 0.74 \[ \int \frac {x}{a+b e^x+c e^{2 x}} \, dx=-\frac {\left (b+\sqrt {b^2-4 a c}\right ) x \log \left (1+\frac {\left (b-\sqrt {b^2-4 a c}\right ) e^{-x}}{2 c}\right )+\left (-b+\sqrt {b^2-4 a c}\right ) x \log \left (1+\frac {\left (b+\sqrt {b^2-4 a c}\right ) e^{-x}}{2 c}\right )-\left (b+\sqrt {b^2-4 a c}\right ) \operatorname {PolyLog}\left (2,\frac {\left (-b+\sqrt {b^2-4 a c}\right ) e^{-x}}{2 c}\right )+\left (b-\sqrt {b^2-4 a c}\right ) \operatorname {PolyLog}\left (2,-\frac {\left (b+\sqrt {b^2-4 a c}\right ) e^{-x}}{2 c}\right )}{2 a \sqrt {b^2-4 a c}} \]
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Time = 0.03 (sec) , antiderivative size = 376, normalized size of antiderivative = 1.36
method | result | size |
default | \(\frac {-\frac {x \left (\ln \left (\frac {-2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) \sqrt {-4 c a +b^{2}}+\ln \left (\frac {-2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) b +\ln \left (\frac {2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) \sqrt {-4 c a +b^{2}}-\ln \left (\frac {2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) b \right )}{2 \sqrt {-4 c a +b^{2}}}-\frac {\operatorname {dilog}\left (\frac {-2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) \sqrt {-4 c a +b^{2}}+\operatorname {dilog}\left (\frac {-2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) b +\operatorname {dilog}\left (\frac {2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) \sqrt {-4 c a +b^{2}}-\operatorname {dilog}\left (\frac {2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) b}{2 \sqrt {-4 c a +b^{2}}}}{a}+\frac {x^{2}}{2 a}\) | \(376\) |
risch | \(-\frac {\ln \left (\frac {-2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) x}{2 a}-\frac {\ln \left (\frac {2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) x}{2 a}-\frac {x \ln \left (\frac {-2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) b}{2 a \sqrt {-4 c a +b^{2}}}+\frac {x \ln \left (\frac {2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) b}{2 a \sqrt {-4 c a +b^{2}}}-\frac {\operatorname {dilog}\left (\frac {-2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right )}{2 a}-\frac {\operatorname {dilog}\left (\frac {2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right )}{2 a}-\frac {\operatorname {dilog}\left (\frac {-2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) b}{2 a \sqrt {-4 c a +b^{2}}}+\frac {\operatorname {dilog}\left (\frac {2 c \,{\mathrm e}^{x}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) b}{2 a \sqrt {-4 c a +b^{2}}}+\frac {x^{2}}{2 a}\) | \(378\) |
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Time = 0.31 (sec) , antiderivative size = 280, normalized size of antiderivative = 1.01 \[ \int \frac {x}{a+b e^x+c e^{2 x}} \, dx=\frac {{\left (b^{2} - 4 \, a c\right )} x^{2} - {\left (a b \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} + b^{2} - 4 \, a c\right )} {\rm Li}_2\left (-\frac {a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} e^{x} + b e^{x} + 2 \, a}{2 \, a} + 1\right ) + {\left (a b \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} - b^{2} + 4 \, a c\right )} {\rm Li}_2\left (\frac {a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} e^{x} - b e^{x} - 2 \, a}{2 \, a} + 1\right ) - {\left (a b x \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} + {\left (b^{2} - 4 \, a c\right )} x\right )} \log \left (\frac {a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} e^{x} + b e^{x} + 2 \, a}{2 \, a}\right ) + {\left (a b x \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} - {\left (b^{2} - 4 \, a c\right )} x\right )} \log \left (-\frac {a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} e^{x} - b e^{x} - 2 \, a}{2 \, a}\right )}{2 \, {\left (a b^{2} - 4 \, a^{2} c\right )}} \]
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\[ \int \frac {x}{a+b e^x+c e^{2 x}} \, dx=\int \frac {x}{a + b e^{x} + c e^{2 x}}\, dx \]
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Exception generated. \[ \int \frac {x}{a+b e^x+c e^{2 x}} \, dx=\text {Exception raised: ValueError} \]
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\[ \int \frac {x}{a+b e^x+c e^{2 x}} \, dx=\int { \frac {x}{c e^{\left (2 \, x\right )} + b e^{x} + a} \,d x } \]
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Timed out. \[ \int \frac {x}{a+b e^x+c e^{2 x}} \, dx=\int \frac {x}{a+b\,{\mathrm {e}}^x+c\,{\mathrm {e}}^{2\,x}} \,d x \]
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