Integrand size = 27, antiderivative size = 338 \[ \int \frac {x}{a+b f^{c+d x}+c f^{2 c+2 d x}} \, dx=-\frac {c x^2}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {c x^2}{b^2-4 a c+b \sqrt {b^2-4 a c}}-\frac {2 c x \log \left (1+\frac {2 c f^{c+d x}}{b-\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (b-\sqrt {b^2-4 a c}\right ) d \log (f)}+\frac {2 c x \log \left (1+\frac {2 c f^{c+d x}}{b+\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (b+\sqrt {b^2-4 a c}\right ) d \log (f)}-\frac {2 c \operatorname {PolyLog}\left (2,-\frac {2 c f^{c+d x}}{b-\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (b-\sqrt {b^2-4 a c}\right ) d^2 \log ^2(f)}+\frac {2 c \operatorname {PolyLog}\left (2,-\frac {2 c f^{c+d x}}{b+\sqrt {b^2-4 a c}}\right )}{\sqrt {b^2-4 a c} \left (b+\sqrt {b^2-4 a c}\right ) d^2 \log ^2(f)} \]
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Time = 0.40 (sec) , antiderivative size = 338, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.185, Rules used = {2295, 2215, 2221, 2317, 2438} \[ \int \frac {x}{a+b f^{c+d x}+c f^{2 c+2 d x}} \, dx=-\frac {2 c \operatorname {PolyLog}\left (2,-\frac {2 c f^{c+d x}}{b-\sqrt {b^2-4 a c}}\right )}{d^2 \log ^2(f) \sqrt {b^2-4 a c} \left (b-\sqrt {b^2-4 a c}\right )}+\frac {2 c \operatorname {PolyLog}\left (2,-\frac {2 c f^{c+d x}}{b+\sqrt {b^2-4 a c}}\right )}{d^2 \log ^2(f) \sqrt {b^2-4 a c} \left (\sqrt {b^2-4 a c}+b\right )}-\frac {2 c x \log \left (\frac {2 c f^{c+d x}}{b-\sqrt {b^2-4 a c}}+1\right )}{d \log (f) \sqrt {b^2-4 a c} \left (b-\sqrt {b^2-4 a c}\right )}+\frac {2 c x \log \left (\frac {2 c f^{c+d x}}{\sqrt {b^2-4 a c}+b}+1\right )}{d \log (f) \sqrt {b^2-4 a c} \left (\sqrt {b^2-4 a c}+b\right )}-\frac {c x^2}{-b \sqrt {b^2-4 a c}-4 a c+b^2}-\frac {c x^2}{b \sqrt {b^2-4 a c}-4 a c+b^2} \]
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Rule 2215
Rule 2221
Rule 2295
Rule 2317
Rule 2438
Rubi steps \begin{align*} \text {integral}& = \frac {(2 c) \int \frac {x}{b-\sqrt {b^2-4 a c}+2 c f^{c+d x}} \, dx}{\sqrt {b^2-4 a c}}-\frac {(2 c) \int \frac {x}{b+\sqrt {b^2-4 a c}+2 c f^{c+d x}} \, dx}{\sqrt {b^2-4 a c}} \\ & = -\frac {c x^2}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {c x^2}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {\left (4 c^2\right ) \int \frac {f^{c+d x} x}{b-\sqrt {b^2-4 a c}+2 c f^{c+d x}} \, dx}{b^2-4 a c-b \sqrt {b^2-4 a c}}+\frac {\left (4 c^2\right ) \int \frac {f^{c+d x} x}{b+\sqrt {b^2-4 a c}+2 c f^{c+d x}} \, dx}{b^2-4 a c+b \sqrt {b^2-4 a c}} \\ & = -\frac {c x^2}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {c x^2}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c f^{c+d x}}{b-\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c-b \sqrt {b^2-4 a c}\right ) d \log (f)}+\frac {2 c x \log \left (1+\frac {2 c f^{c+d x}}{b+\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c+b \sqrt {b^2-4 a c}\right ) d \log (f)}-\frac {(2 c) \int \log \left (1+\frac {2 c f^{c+d x}}{b-\sqrt {b^2-4 a c}}\right ) \, dx}{\left (b^2-4 a c-b \sqrt {b^2-4 a c}\right ) d \log (f)}-\frac {(2 c) \int \log \left (1+\frac {2 c f^{c+d x}}{b+\sqrt {b^2-4 a c}}\right ) \, dx}{\left (b^2-4 a c+b \sqrt {b^2-4 a c}\right ) d \log (f)} \\ & = -\frac {c x^2}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {c x^2}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c f^{c+d x}}{b-\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c-b \sqrt {b^2-4 a c}\right ) d \log (f)}+\frac {2 c x \log \left (1+\frac {2 c f^{c+d x}}{b+\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c+b \sqrt {b^2-4 a c}\right ) d \log (f)}-\frac {(2 c) \text {Subst}\left (\int \frac {\log \left (1+\frac {2 c x}{b-\sqrt {b^2-4 a c}}\right )}{x} \, dx,x,f^{c+d x}\right )}{\left (b^2-4 a c-b \sqrt {b^2-4 a c}\right ) d^2 \log ^2(f)}-\frac {(2 c) \text {Subst}\left (\int \frac {\log \left (1+\frac {2 c x}{b+\sqrt {b^2-4 a c}}\right )}{x} \, dx,x,f^{c+d x}\right )}{\left (b^2-4 a c+b \sqrt {b^2-4 a c}\right ) d^2 \log ^2(f)} \\ & = -\frac {c x^2}{b^2-4 a c-b \sqrt {b^2-4 a c}}-\frac {c x^2}{b^2-4 a c+b \sqrt {b^2-4 a c}}+\frac {2 c x \log \left (1+\frac {2 c f^{c+d x}}{b-\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c-b \sqrt {b^2-4 a c}\right ) d \log (f)}+\frac {2 c x \log \left (1+\frac {2 c f^{c+d x}}{b+\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c+b \sqrt {b^2-4 a c}\right ) d \log (f)}+\frac {2 c \text {Li}_2\left (-\frac {2 c f^{c+d x}}{b-\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c-b \sqrt {b^2-4 a c}\right ) d^2 \log ^2(f)}+\frac {2 c \text {Li}_2\left (-\frac {2 c f^{c+d x}}{b+\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c+b \sqrt {b^2-4 a c}\right ) d^2 \log ^2(f)} \\ \end{align*}
Time = 0.24 (sec) , antiderivative size = 236, normalized size of antiderivative = 0.70 \[ \int \frac {x}{a+b f^{c+d x}+c f^{2 c+2 d x}} \, dx=\frac {-d x \log (f) \left (\left (b+\sqrt {b^2-4 a c}\right ) \log \left (1+\frac {\left (b-\sqrt {b^2-4 a c}\right ) f^{-c-d x}}{2 c}\right )+\left (-b+\sqrt {b^2-4 a c}\right ) \log \left (1+\frac {\left (b+\sqrt {b^2-4 a c}\right ) f^{-c-d x}}{2 c}\right )\right )+\left (b+\sqrt {b^2-4 a c}\right ) \operatorname {PolyLog}\left (2,\frac {\left (-b+\sqrt {b^2-4 a c}\right ) f^{-c-d x}}{2 c}\right )+\left (-b+\sqrt {b^2-4 a c}\right ) \operatorname {PolyLog}\left (2,-\frac {\left (b+\sqrt {b^2-4 a c}\right ) f^{-c-d x}}{2 c}\right )}{2 a \sqrt {b^2-4 a c} d^2 \log ^2(f)} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(854\) vs. \(2(310)=620\).
Time = 0.09 (sec) , antiderivative size = 855, normalized size of antiderivative = 2.53
method | result | size |
risch | \(\frac {x^{2}}{2 a}+\frac {c x}{d a}+\frac {c^{2}}{2 d^{2} a}-\frac {\ln \left (\frac {-2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) x}{2 d \ln \left (f \right ) a}-\frac {\ln \left (\frac {-2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) c}{2 d^{2} \ln \left (f \right ) a}-\frac {\ln \left (\frac {-2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) b x}{2 d \ln \left (f \right ) a \sqrt {-4 c a +b^{2}}}-\frac {\ln \left (\frac {-2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) b c}{2 d^{2} \ln \left (f \right ) a \sqrt {-4 c a +b^{2}}}-\frac {\ln \left (\frac {2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) x}{2 d \ln \left (f \right ) a}-\frac {\ln \left (\frac {2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) c}{2 d^{2} \ln \left (f \right ) a}+\frac {\ln \left (\frac {2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) b x}{2 d \ln \left (f \right ) a \sqrt {-4 c a +b^{2}}}+\frac {\ln \left (\frac {2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) b c}{2 d^{2} \ln \left (f \right ) a \sqrt {-4 c a +b^{2}}}-\frac {\operatorname {dilog}\left (\frac {-2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right )}{2 d^{2} \ln \left (f \right )^{2} a}-\frac {\operatorname {dilog}\left (\frac {-2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}-b}{-b +\sqrt {-4 c a +b^{2}}}\right ) b}{2 d^{2} \ln \left (f \right )^{2} a \sqrt {-4 c a +b^{2}}}-\frac {\operatorname {dilog}\left (\frac {2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right )}{2 d^{2} \ln \left (f \right )^{2} a}+\frac {\operatorname {dilog}\left (\frac {2 c \,f^{d x} f^{c}+\sqrt {-4 c a +b^{2}}+b}{b +\sqrt {-4 c a +b^{2}}}\right ) b}{2 d^{2} \ln \left (f \right )^{2} a \sqrt {-4 c a +b^{2}}}-\frac {c \ln \left (f^{d x} f^{c}\right )}{d^{2} \ln \left (f \right ) a}+\frac {c \ln \left (a +b \,f^{d x} f^{c}+c \,f^{2 d x} f^{2 c}\right )}{2 d^{2} \ln \left (f \right ) a}+\frac {c b \arctan \left (\frac {2 c \,f^{d x} f^{c}+b}{\sqrt {4 c a -b^{2}}}\right )}{d^{2} \ln \left (f \right ) a \sqrt {4 c a -b^{2}}}\) | \(855\) |
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Time = 0.31 (sec) , antiderivative size = 497, normalized size of antiderivative = 1.47 \[ \int \frac {x}{a+b f^{c+d x}+c f^{2 c+2 d x}} \, dx=\frac {{\left (b^{2} - 4 \, a c\right )} d^{2} x^{2} \log \left (f\right )^{2} - {\left (a b \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} + b^{2} - 4 \, a c\right )} {\rm Li}_2\left (-\frac {{\left (a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} + b\right )} f^{d x + c} + 2 \, a}{2 \, a} + 1\right ) + {\left (a b \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} - b^{2} + 4 \, a c\right )} {\rm Li}_2\left (\frac {{\left (a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} - b\right )} f^{d x + c} - 2 \, a}{2 \, a} + 1\right ) - {\left (a b c \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} \log \left (f\right ) - {\left (b^{2} c - 4 \, a c^{2}\right )} \log \left (f\right )\right )} \log \left (2 \, c f^{d x + c} + a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} + b\right ) + {\left (a b c \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} \log \left (f\right ) + {\left (b^{2} c - 4 \, a c^{2}\right )} \log \left (f\right )\right )} \log \left (2 \, c f^{d x + c} - a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} + b\right ) - {\left ({\left (a b d x + a b c\right )} \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} \log \left (f\right ) + {\left (b^{2} c - 4 \, a c^{2} + {\left (b^{2} - 4 \, a c\right )} d x\right )} \log \left (f\right )\right )} \log \left (\frac {{\left (a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} + b\right )} f^{d x + c} + 2 \, a}{2 \, a}\right ) + {\left ({\left (a b d x + a b c\right )} \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} \log \left (f\right ) - {\left (b^{2} c - 4 \, a c^{2} + {\left (b^{2} - 4 \, a c\right )} d x\right )} \log \left (f\right )\right )} \log \left (-\frac {{\left (a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} - b\right )} f^{d x + c} - 2 \, a}{2 \, a}\right )}{2 \, {\left (a b^{2} - 4 \, a^{2} c\right )} d^{2} \log \left (f\right )^{2}} \]
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\[ \int \frac {x}{a+b f^{c+d x}+c f^{2 c+2 d x}} \, dx=\int \frac {x}{a + b f^{c + d x} + c f^{2 c + 2 d x}}\, dx \]
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Exception generated. \[ \int \frac {x}{a+b f^{c+d x}+c f^{2 c+2 d x}} \, dx=\text {Exception raised: ValueError} \]
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\[ \int \frac {x}{a+b f^{c+d x}+c f^{2 c+2 d x}} \, dx=\int { \frac {x}{c f^{2 \, d x + 2 \, c} + b f^{d x + c} + a} \,d x } \]
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Timed out. \[ \int \frac {x}{a+b f^{c+d x}+c f^{2 c+2 d x}} \, dx=\int \frac {x}{a+b\,f^{c+d\,x}+c\,f^{2\,c+2\,d\,x}} \,d x \]
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