Integrand size = 23, antiderivative size = 88 \[ \int \frac {f^{a+3 b x}}{c+d f^{e+2 b x}} \, dx=\frac {f^{\frac {1}{2} (2 a-3 e)+\frac {1}{2} (e+2 b x)}}{b d \log (f)}-\frac {\sqrt {c} f^{a-\frac {3 e}{2}} \arctan \left (\frac {\sqrt {d} f^{\frac {1}{2} (e+2 b x)}}{\sqrt {c}}\right )}{b d^{3/2} \log (f)} \]
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Time = 0.05 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.130, Rules used = {2280, 327, 211} \[ \int \frac {f^{a+3 b x}}{c+d f^{e+2 b x}} \, dx=\frac {f^{\frac {1}{2} (2 a-3 e)+\frac {1}{2} (2 b x+e)}}{b d \log (f)}-\frac {\sqrt {c} f^{a-\frac {3 e}{2}} \arctan \left (\frac {\sqrt {d} f^{\frac {1}{2} (2 b x+e)}}{\sqrt {c}}\right )}{b d^{3/2} \log (f)} \]
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Rule 211
Rule 327
Rule 2280
Rubi steps \begin{align*} \text {integral}& = \frac {f^{a-\frac {3 e}{2}} \text {Subst}\left (\int \frac {x^2}{c+d x^2} \, dx,x,f^{\frac {1}{2} (e+2 b x)}\right )}{b \log (f)} \\ & = \frac {f^{\frac {1}{2} (2 a-3 e)+\frac {1}{2} (e+2 b x)}}{b d \log (f)}-\frac {\left (c f^{a-\frac {3 e}{2}}\right ) \text {Subst}\left (\int \frac {1}{c+d x^2} \, dx,x,f^{\frac {1}{2} (e+2 b x)}\right )}{b d \log (f)} \\ & = \frac {f^{\frac {1}{2} (2 a-3 e)+\frac {1}{2} (e+2 b x)}}{b d \log (f)}-\frac {\sqrt {c} f^{a-\frac {3 e}{2}} \tan ^{-1}\left (\frac {\sqrt {d} f^{\frac {1}{2} (e+2 b x)}}{\sqrt {c}}\right )}{b d^{3/2} \log (f)} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.76 \[ \int \frac {f^{a+3 b x}}{c+d f^{e+2 b x}} \, dx=\frac {\frac {f^{a-e+b x}}{d}-\frac {\sqrt {c} f^{a-\frac {3 e}{2}} \arctan \left (\frac {\sqrt {d} f^{\frac {e}{2}+b x}}{\sqrt {c}}\right )}{d^{3/2}}}{b \log (f)} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(170\) vs. \(2(61)=122\).
Time = 0.06 (sec) , antiderivative size = 171, normalized size of antiderivative = 1.94
method | result | size |
risch | \(\frac {f^{-e} f^{\frac {2 a}{3}} f^{b x +\frac {a}{3}}}{d \ln \left (f \right ) b}+\frac {\sqrt {-c d}\, f^{a} f^{-\frac {3 e}{2}} \ln \left (f^{b x +\frac {a}{3}}-\frac {\sqrt {-c d}\, f^{\frac {a}{3}} f^{-\frac {e}{2}}}{d}\right )}{2 d^{2} b \ln \left (f \right )}-\frac {\sqrt {-c d}\, f^{a} f^{-\frac {3 e}{2}} \ln \left (f^{b x +\frac {a}{3}}+\frac {\sqrt {-c d}\, f^{\frac {a}{3}} f^{-\frac {e}{2}}}{d}\right )}{2 d^{2} b \ln \left (f \right )}\) | \(171\) |
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Time = 0.28 (sec) , antiderivative size = 166, normalized size of antiderivative = 1.89 \[ \int \frac {f^{a+3 b x}}{c+d f^{e+2 b x}} \, dx=\left [\frac {f^{a - \frac {3}{2} \, e} \sqrt {-\frac {c}{d}} \log \left (-\frac {2 \, d f^{b x + \frac {1}{2} \, e} \sqrt {-\frac {c}{d}} - d f^{2 \, b x + e} + c}{d f^{2 \, b x + e} + c}\right ) + 2 \, f^{b x + \frac {1}{2} \, e} f^{a - \frac {3}{2} \, e}}{2 \, b d \log \left (f\right )}, -\frac {f^{a - \frac {3}{2} \, e} \sqrt {\frac {c}{d}} \arctan \left (\frac {d f^{b x + \frac {1}{2} \, e} \sqrt {\frac {c}{d}}}{c}\right ) - f^{b x + \frac {1}{2} \, e} f^{a - \frac {3}{2} \, e}}{b d \log \left (f\right )}\right ] \]
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Time = 0.66 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.25 \[ \int \frac {f^{a+3 b x}}{c+d f^{e+2 b x}} \, dx=\operatorname {RootSum} {\left (4 z^{2} b^{2} d^{3} e^{3 e \log {\left (f \right )}} \log {\left (f \right )}^{2} + c e^{2 a \log {\left (f \right )}}, \left ( i \mapsto i \log {\left (- 2 i b d e^{- \frac {2 a \log {\left (f \right )}}{3}} e^{e \log {\left (f \right )}} \log {\left (f \right )} + e^{\frac {\left (a + 3 b x\right ) \log {\left (f \right )}}{3}} \right )} \right )\right )} + \frac {\left (\begin {cases} x & \text {for}\: b = 0 \vee f = 1 \\\frac {e^{b x \log {\left (f \right )}}}{b \log {\left (f \right )}} & \text {otherwise} \end {cases}\right ) e^{a \log {\left (f \right )}} e^{- e \log {\left (f \right )}}}{d} \]
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Time = 0.27 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.77 \[ \int \frac {f^{a+3 b x}}{c+d f^{e+2 b x}} \, dx=-\frac {c f^{a - e} \arctan \left (\frac {d f^{b x + e}}{\sqrt {c d f^{e}}}\right )}{\sqrt {c d f^{e}} b d \log \left (f\right )} + \frac {f^{b x + a - e}}{b d \log \left (f\right )} \]
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Time = 0.32 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.78 \[ \int \frac {f^{a+3 b x}}{c+d f^{e+2 b x}} \, dx=-\frac {f^{a} {\left (\frac {c \arctan \left (\frac {d f^{b x} f^{e}}{\sqrt {c d f^{e}}}\right )}{\sqrt {c d f^{e}} d f^{e} \log \left (f\right )} - \frac {f^{b x}}{d f^{e} \log \left (f\right )}\right )}}{b} \]
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Time = 0.23 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.75 \[ \int \frac {f^{a+3 b x}}{c+d f^{e+2 b x}} \, dx=-\frac {f^a\,{\mathrm {e}}^{-\frac {3\,e\,\ln \left (f\right )}{2}}\,\left (c\,\mathrm {atan}\left (\frac {d\,f^{b\,x}\,{\mathrm {e}}^{\frac {e\,\ln \left (f\right )}{2}}}{\sqrt {c\,d}}\right )-f^{b\,x}\,{\mathrm {e}}^{\frac {e\,\ln \left (f\right )}{2}}\,\sqrt {c\,d}\right )}{b\,d\,\ln \left (f\right )\,\sqrt {c\,d}} \]
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