Integrand size = 18, antiderivative size = 15 \[ \int \frac {e^x}{2+3 e^x+e^{2 x}} \, dx=\log \left (1+e^x\right )-\log \left (2+e^x\right ) \]
[Out]
Time = 0.02 (sec) , antiderivative size = 15, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {2320, 630, 31} \[ \int \frac {e^x}{2+3 e^x+e^{2 x}} \, dx=\log \left (e^x+1\right )-\log \left (e^x+2\right ) \]
[In]
[Out]
Rule 31
Rule 630
Rule 2320
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {1}{2+3 x+x^2} \, dx,x,e^x\right ) \\ & = \text {Subst}\left (\int \frac {1}{1+x} \, dx,x,e^x\right )-\text {Subst}\left (\int \frac {1}{2+x} \, dx,x,e^x\right ) \\ & = \log \left (1+e^x\right )-\log \left (2+e^x\right ) \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.67 \[ \int \frac {e^x}{2+3 e^x+e^{2 x}} \, dx=-2 \text {arctanh}\left (3+2 e^x\right ) \]
[In]
[Out]
Time = 0.04 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.93
method | result | size |
default | \(\ln \left (1+{\mathrm e}^{x}\right )-\ln \left (2+{\mathrm e}^{x}\right )\) | \(14\) |
norman | \(\ln \left (1+{\mathrm e}^{x}\right )-\ln \left (2+{\mathrm e}^{x}\right )\) | \(14\) |
risch | \(\ln \left (1+{\mathrm e}^{x}\right )-\ln \left (2+{\mathrm e}^{x}\right )\) | \(14\) |
[In]
[Out]
none
Time = 0.27 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.87 \[ \int \frac {e^x}{2+3 e^x+e^{2 x}} \, dx=-\log \left (e^{x} + 2\right ) + \log \left (e^{x} + 1\right ) \]
[In]
[Out]
Time = 0.06 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.80 \[ \int \frac {e^x}{2+3 e^x+e^{2 x}} \, dx=\log {\left (e^{x} + 1 \right )} - \log {\left (e^{x} + 2 \right )} \]
[In]
[Out]
none
Time = 0.20 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.87 \[ \int \frac {e^x}{2+3 e^x+e^{2 x}} \, dx=-\log \left (e^{x} + 2\right ) + \log \left (e^{x} + 1\right ) \]
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.87 \[ \int \frac {e^x}{2+3 e^x+e^{2 x}} \, dx=-\log \left (e^{x} + 2\right ) + \log \left (e^{x} + 1\right ) \]
[In]
[Out]
Time = 0.29 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.87 \[ \int \frac {e^x}{2+3 e^x+e^{2 x}} \, dx=\ln \left ({\mathrm {e}}^x+1\right )-\ln \left ({\mathrm {e}}^x+2\right ) \]
[In]
[Out]