Integrand size = 34, antiderivative size = 75 \[ \int \frac {F^{e (c+d x)} H^{t (r+s x)}}{a+b F^{e (c+d x)}} \, dx=\frac {H^{t (r+s x)} \operatorname {Hypergeometric2F1}\left (1,-\frac {s t \log (H)}{d e \log (F)},1-\frac {s t \log (H)}{d e \log (F)},-\frac {a F^{-e (c+d x)}}{b}\right )}{b s t \log (H)} \]
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Time = 0.08 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {2288, 2283} \[ \int \frac {F^{e (c+d x)} H^{t (r+s x)}}{a+b F^{e (c+d x)}} \, dx=\frac {H^{t (r+s x)} \operatorname {Hypergeometric2F1}\left (1,-\frac {s t \log (H)}{d e \log (F)},1-\frac {s t \log (H)}{d e \log (F)},-\frac {a F^{-e (c+d x)}}{b}\right )}{b s t \log (H)} \]
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Rule 2283
Rule 2288
Rubi steps \begin{align*} \text {integral}& = \int \frac {H^{t (r+s x)}}{b+a F^{-e (c+d x)}} \, dx \\ & = \frac {H^{t (r+s x)} \, _2F_1\left (1,-\frac {s t \log (H)}{d e \log (F)};1-\frac {s t \log (H)}{d e \log (F)};-\frac {a F^{-e (c+d x)}}{b}\right )}{b s t \log (H)} \\ \end{align*}
Time = 0.27 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00 \[ \int \frac {F^{e (c+d x)} H^{t (r+s x)}}{a+b F^{e (c+d x)}} \, dx=-\frac {H^{t (r+s x)} \left (-1+\operatorname {Hypergeometric2F1}\left (1,\frac {s t \log (H)}{d e \log (F)},1+\frac {s t \log (H)}{d e \log (F)},-\frac {b F^{e (c+d x)}}{a}\right )\right )}{b s t \log (H)} \]
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\[\int \frac {F^{e \left (d x +c \right )} H^{t \left (s x +r \right )}}{a +b \,F^{e \left (d x +c \right )}}d x\]
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\[ \int \frac {F^{e (c+d x)} H^{t (r+s x)}}{a+b F^{e (c+d x)}} \, dx=\int { \frac {F^{{\left (d x + c\right )} e} H^{{\left (s x + r\right )} t}}{F^{{\left (d x + c\right )} e} b + a} \,d x } \]
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\[ \int \frac {F^{e (c+d x)} H^{t (r+s x)}}{a+b F^{e (c+d x)}} \, dx=\int \frac {F^{e \left (c + d x\right )} H^{t \left (r + s x\right )}}{F^{c e + d e x} b + a}\, dx \]
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\[ \int \frac {F^{e (c+d x)} H^{t (r+s x)}}{a+b F^{e (c+d x)}} \, dx=\int { \frac {F^{{\left (d x + c\right )} e} H^{{\left (s x + r\right )} t}}{F^{{\left (d x + c\right )} e} b + a} \,d x } \]
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\[ \int \frac {F^{e (c+d x)} H^{t (r+s x)}}{a+b F^{e (c+d x)}} \, dx=\int { \frac {F^{{\left (d x + c\right )} e} H^{{\left (s x + r\right )} t}}{F^{{\left (d x + c\right )} e} b + a} \,d x } \]
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Timed out. \[ \int \frac {F^{e (c+d x)} H^{t (r+s x)}}{a+b F^{e (c+d x)}} \, dx=\int \frac {F^{e\,\left (c+d\,x\right )}\,H^{t\,\left (r+s\,x\right )}}{a+F^{e\,\left (c+d\,x\right )}\,b} \,d x \]
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