Integrand size = 13, antiderivative size = 81 \[ \int \frac {f^{a+b x^2}}{x^7} \, dx=-\frac {f^{a+b x^2}}{6 x^6}-\frac {b f^{a+b x^2} \log (f)}{12 x^4}-\frac {b^2 f^{a+b x^2} \log ^2(f)}{12 x^2}+\frac {1}{12} b^3 f^a \operatorname {ExpIntegralEi}\left (b x^2 \log (f)\right ) \log ^3(f) \]
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Time = 0.06 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {2245, 2241} \[ \int \frac {f^{a+b x^2}}{x^7} \, dx=\frac {1}{12} b^3 f^a \log ^3(f) \operatorname {ExpIntegralEi}\left (b x^2 \log (f)\right )-\frac {b^2 \log ^2(f) f^{a+b x^2}}{12 x^2}-\frac {f^{a+b x^2}}{6 x^6}-\frac {b \log (f) f^{a+b x^2}}{12 x^4} \]
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Rule 2241
Rule 2245
Rubi steps \begin{align*} \text {integral}& = -\frac {f^{a+b x^2}}{6 x^6}+\frac {1}{3} (b \log (f)) \int \frac {f^{a+b x^2}}{x^5} \, dx \\ & = -\frac {f^{a+b x^2}}{6 x^6}-\frac {b f^{a+b x^2} \log (f)}{12 x^4}+\frac {1}{6} \left (b^2 \log ^2(f)\right ) \int \frac {f^{a+b x^2}}{x^3} \, dx \\ & = -\frac {f^{a+b x^2}}{6 x^6}-\frac {b f^{a+b x^2} \log (f)}{12 x^4}-\frac {b^2 f^{a+b x^2} \log ^2(f)}{12 x^2}+\frac {1}{6} \left (b^3 \log ^3(f)\right ) \int \frac {f^{a+b x^2}}{x} \, dx \\ & = -\frac {f^{a+b x^2}}{6 x^6}-\frac {b f^{a+b x^2} \log (f)}{12 x^4}-\frac {b^2 f^{a+b x^2} \log ^2(f)}{12 x^2}+\frac {1}{12} b^3 f^a \text {Ei}\left (b x^2 \log (f)\right ) \log ^3(f) \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.73 \[ \int \frac {f^{a+b x^2}}{x^7} \, dx=\frac {f^a \left (b^3 x^6 \operatorname {ExpIntegralEi}\left (b x^2 \log (f)\right ) \log ^3(f)-f^{b x^2} \left (2+b x^2 \log (f)+b^2 x^4 \log ^2(f)\right )\right )}{12 x^6} \]
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Time = 0.08 (sec) , antiderivative size = 72, normalized size of antiderivative = 0.89
method | result | size |
risch | \(-\frac {f^{a} \left (\ln \left (f \right )^{3} \operatorname {Ei}_{1}\left (-b \,x^{2} \ln \left (f \right )\right ) b^{3} x^{6}+\ln \left (f \right )^{2} f^{b \,x^{2}} b^{2} x^{4}+\ln \left (f \right ) f^{b \,x^{2}} b \,x^{2}+2 f^{b \,x^{2}}\right )}{12 x^{6}}\) | \(72\) |
meijerg | \(-\frac {f^{a} b^{3} \ln \left (f \right )^{3} \left (\frac {1}{3 b^{3} x^{6} \ln \left (f \right )^{3}}+\frac {1}{2 b^{2} x^{4} \ln \left (f \right )^{2}}+\frac {1}{2 b \,x^{2} \ln \left (f \right )}+\frac {11}{36}-\frac {\ln \left (x \right )}{3}-\frac {\ln \left (-b \right )}{6}-\frac {\ln \left (\ln \left (f \right )\right )}{6}-\frac {22 b^{3} x^{6} \ln \left (f \right )^{3}+36 b^{2} x^{4} \ln \left (f \right )^{2}+36 b \,x^{2} \ln \left (f \right )+24}{72 b^{3} x^{6} \ln \left (f \right )^{3}}+\frac {\left (4 b^{2} x^{4} \ln \left (f \right )^{2}+4 b \,x^{2} \ln \left (f \right )+8\right ) {\mathrm e}^{b \,x^{2} \ln \left (f \right )}}{24 b^{3} x^{6} \ln \left (f \right )^{3}}+\frac {\ln \left (-b \,x^{2} \ln \left (f \right )\right )}{6}+\frac {\operatorname {Ei}_{1}\left (-b \,x^{2} \ln \left (f \right )\right )}{6}\right )}{2}\) | \(177\) |
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Time = 0.28 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.73 \[ \int \frac {f^{a+b x^2}}{x^7} \, dx=\frac {b^{3} f^{a} x^{6} {\rm Ei}\left (b x^{2} \log \left (f\right )\right ) \log \left (f\right )^{3} - {\left (b^{2} x^{4} \log \left (f\right )^{2} + b x^{2} \log \left (f\right ) + 2\right )} f^{b x^{2} + a}}{12 \, x^{6}} \]
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\[ \int \frac {f^{a+b x^2}}{x^7} \, dx=\int \frac {f^{a + b x^{2}}}{x^{7}}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.27 \[ \int \frac {f^{a+b x^2}}{x^7} \, dx=\frac {1}{2} \, b^{3} f^{a} \Gamma \left (-3, -b x^{2} \log \left (f\right )\right ) \log \left (f\right )^{3} \]
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\[ \int \frac {f^{a+b x^2}}{x^7} \, dx=\int { \frac {f^{b x^{2} + a}}{x^{7}} \,d x } \]
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Time = 0.19 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.85 \[ \int \frac {f^{a+b x^2}}{x^7} \, dx=-\frac {b^3\,f^a\,{\ln \left (f\right )}^3\,\left (f^{b\,x^2}\,\left (\frac {1}{6\,b\,x^2\,\ln \left (f\right )}+\frac {1}{6\,b^2\,x^4\,{\ln \left (f\right )}^2}+\frac {1}{3\,b^3\,x^6\,{\ln \left (f\right )}^3}\right )+\frac {\mathrm {expint}\left (-b\,x^2\,\ln \left (f\right )\right )}{6}\right )}{2} \]
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