Integrand size = 23, antiderivative size = 226 \[ \int (d+e x)^2 \log \left (d \left (a+b x+c x^2\right )^n\right ) \, dx=-\frac {\left (6 c^2 d^2+b^2 e^2-c e (3 b d+2 a e)\right ) n x}{3 c^2}-\frac {e (6 c d-b e) n x^2}{6 c}-\frac {2}{9} e^2 n x^3+\frac {\sqrt {b^2-4 a c} \left (3 c^2 d^2+b^2 e^2-c e (3 b d+a e)\right ) n \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{3 c^3}-\frac {(2 c d-b e) \left (c^2 d^2+b^2 e^2-c e (b d+3 a e)\right ) n \log \left (a+b x+c x^2\right )}{6 c^3 e}+\frac {(d+e x)^3 \log \left (d \left (a+b x+c x^2\right )^n\right )}{3 e} \]
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Time = 0.22 (sec) , antiderivative size = 226, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.261, Rules used = {2605, 814, 648, 632, 212, 642} \[ \int (d+e x)^2 \log \left (d \left (a+b x+c x^2\right )^n\right ) \, dx=\frac {n \sqrt {b^2-4 a c} \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right ) \left (-c e (a e+3 b d)+b^2 e^2+3 c^2 d^2\right )}{3 c^3}-\frac {n x \left (-c e (2 a e+3 b d)+b^2 e^2+6 c^2 d^2\right )}{3 c^2}-\frac {n (2 c d-b e) \left (-c e (3 a e+b d)+b^2 e^2+c^2 d^2\right ) \log \left (a+b x+c x^2\right )}{6 c^3 e}+\frac {(d+e x)^3 \log \left (d \left (a+b x+c x^2\right )^n\right )}{3 e}-\frac {e n x^2 (6 c d-b e)}{6 c}-\frac {2}{9} e^2 n x^3 \]
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Rule 212
Rule 632
Rule 642
Rule 648
Rule 814
Rule 2605
Rubi steps \begin{align*} \text {integral}& = \frac {(d+e x)^3 \log \left (d \left (a+b x+c x^2\right )^n\right )}{3 e}-\frac {n \int \frac {(b+2 c x) (d+e x)^3}{a+b x+c x^2} \, dx}{3 e} \\ & = \frac {(d+e x)^3 \log \left (d \left (a+b x+c x^2\right )^n\right )}{3 e}-\frac {n \int \left (\frac {e \left (6 c^2 d^2+b^2 e^2-c e (3 b d+2 a e)\right )}{c^2}+\frac {e^2 (6 c d-b e) x}{c}+2 e^3 x^2+\frac {-a b^2 e^3-2 a c e \left (3 c d^2-a e^2\right )+b c d \left (c d^2+3 a e^2\right )+(2 c d-b e) \left (c^2 d^2+b^2 e^2-c e (b d+3 a e)\right ) x}{c^2 \left (a+b x+c x^2\right )}\right ) \, dx}{3 e} \\ & = -\frac {\left (6 c^2 d^2+b^2 e^2-c e (3 b d+2 a e)\right ) n x}{3 c^2}-\frac {e (6 c d-b e) n x^2}{6 c}-\frac {2}{9} e^2 n x^3+\frac {(d+e x)^3 \log \left (d \left (a+b x+c x^2\right )^n\right )}{3 e}-\frac {n \int \frac {-a b^2 e^3-2 a c e \left (3 c d^2-a e^2\right )+b c d \left (c d^2+3 a e^2\right )+(2 c d-b e) \left (c^2 d^2+b^2 e^2-c e (b d+3 a e)\right ) x}{a+b x+c x^2} \, dx}{3 c^2 e} \\ & = -\frac {\left (6 c^2 d^2+b^2 e^2-c e (3 b d+2 a e)\right ) n x}{3 c^2}-\frac {e (6 c d-b e) n x^2}{6 c}-\frac {2}{9} e^2 n x^3+\frac {(d+e x)^3 \log \left (d \left (a+b x+c x^2\right )^n\right )}{3 e}-\frac {\left (\left (b^2-4 a c\right ) \left (3 c^2 d^2+b^2 e^2-c e (3 b d+a e)\right ) n\right ) \int \frac {1}{a+b x+c x^2} \, dx}{6 c^3}-\frac {\left ((2 c d-b e) \left (c^2 d^2+b^2 e^2-c e (b d+3 a e)\right ) n\right ) \int \frac {b+2 c x}{a+b x+c x^2} \, dx}{6 c^3 e} \\ & = -\frac {\left (6 c^2 d^2+b^2 e^2-c e (3 b d+2 a e)\right ) n x}{3 c^2}-\frac {e (6 c d-b e) n x^2}{6 c}-\frac {2}{9} e^2 n x^3-\frac {(2 c d-b e) \left (c^2 d^2+b^2 e^2-c e (b d+3 a e)\right ) n \log \left (a+b x+c x^2\right )}{6 c^3 e}+\frac {(d+e x)^3 \log \left (d \left (a+b x+c x^2\right )^n\right )}{3 e}+\frac {\left (\left (b^2-4 a c\right ) \left (3 c^2 d^2+b^2 e^2-c e (3 b d+a e)\right ) n\right ) \text {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 c x\right )}{3 c^3} \\ & = -\frac {\left (6 c^2 d^2+b^2 e^2-c e (3 b d+2 a e)\right ) n x}{3 c^2}-\frac {e (6 c d-b e) n x^2}{6 c}-\frac {2}{9} e^2 n x^3+\frac {\sqrt {b^2-4 a c} \left (3 c^2 d^2+b^2 e^2-c e (3 b d+a e)\right ) n \tanh ^{-1}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{3 c^3}-\frac {(2 c d-b e) \left (c^2 d^2+b^2 e^2-c e (b d+3 a e)\right ) n \log \left (a+b x+c x^2\right )}{6 c^3 e}+\frac {(d+e x)^3 \log \left (d \left (a+b x+c x^2\right )^n\right )}{3 e} \\ \end{align*}
Time = 0.24 (sec) , antiderivative size = 204, normalized size of antiderivative = 0.90 \[ \int (d+e x)^2 \log \left (d \left (a+b x+c x^2\right )^n\right ) \, dx=\frac {-\frac {n \left (c e x \left (6 b^2 e^2-3 c e (6 b d+4 a e+b e x)+2 c^2 \left (18 d^2+9 d e x+2 e^2 x^2\right )\right )-6 \sqrt {b^2-4 a c} e \left (3 c^2 d^2+b^2 e^2-c e (3 b d+a e)\right ) \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )+3 (2 c d-b e) \left (c^2 d^2+b^2 e^2-c e (b d+3 a e)\right ) \log (a+x (b+c x))\right )}{6 c^3}+(d+e x)^3 \log \left (d (a+x (b+c x))^n\right )}{3 e} \]
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Time = 1.61 (sec) , antiderivative size = 384, normalized size of antiderivative = 1.70
method | result | size |
parts | \(\frac {\ln \left (d \left (c \,x^{2}+b x +a \right )^{n}\right ) e^{2} x^{3}}{3}+\ln \left (d \left (c \,x^{2}+b x +a \right )^{n}\right ) e d \,x^{2}+\ln \left (d \left (c \,x^{2}+b x +a \right )^{n}\right ) d^{2} x +\frac {\ln \left (d \left (c \,x^{2}+b x +a \right )^{n}\right ) d^{3}}{3 e}-\frac {n \left (-\frac {e \left (-\frac {2}{3} c^{2} e^{2} x^{3}+\frac {1}{2} b c \,e^{2} x^{2}-3 c^{2} d e \,x^{2}+2 x c a \,e^{2}-x \,e^{2} b^{2}+3 x b c d e -6 c^{2} d^{2} x \right )}{c^{2}}+\frac {\frac {\left (3 a b c \,e^{3}-6 a \,c^{2} d \,e^{2}-b^{3} e^{3}+3 b^{2} c d \,e^{2}-3 b \,c^{2} d^{2} e +2 c^{3} d^{3}\right ) \ln \left (c \,x^{2}+b x +a \right )}{2 c}+\frac {2 \left (2 a^{2} c \,e^{3}-a \,b^{2} e^{3}+3 a b c d \,e^{2}-6 a \,c^{2} d^{2} e +b \,c^{2} d^{3}-\frac {\left (3 a b c \,e^{3}-6 a \,c^{2} d \,e^{2}-b^{3} e^{3}+3 b^{2} c d \,e^{2}-3 b \,c^{2} d^{2} e +2 c^{3} d^{3}\right ) b}{2 c}\right ) \arctan \left (\frac {2 x c +b}{\sqrt {4 c a -b^{2}}}\right )}{\sqrt {4 c a -b^{2}}}}{c^{2}}\right )}{3 e}\) | \(384\) |
risch | \(\text {Expression too large to display}\) | \(7155\) |
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Time = 0.32 (sec) , antiderivative size = 567, normalized size of antiderivative = 2.51 \[ \int (d+e x)^2 \log \left (d \left (a+b x+c x^2\right )^n\right ) \, dx=\left [-\frac {4 \, c^{3} e^{2} n x^{3} + 3 \, {\left (6 \, c^{3} d e - b c^{2} e^{2}\right )} n x^{2} + 3 \, {\left (3 \, c^{2} d^{2} - 3 \, b c d e + {\left (b^{2} - a c\right )} e^{2}\right )} \sqrt {b^{2} - 4 \, a c} n \log \left (\frac {2 \, c^{2} x^{2} + 2 \, b c x + b^{2} - 2 \, a c - \sqrt {b^{2} - 4 \, a c} {\left (2 \, c x + b\right )}}{c x^{2} + b x + a}\right ) + 6 \, {\left (6 \, c^{3} d^{2} - 3 \, b c^{2} d e + {\left (b^{2} c - 2 \, a c^{2}\right )} e^{2}\right )} n x - 3 \, {\left (2 \, c^{3} e^{2} n x^{3} + 6 \, c^{3} d e n x^{2} + 6 \, c^{3} d^{2} n x + {\left (3 \, b c^{2} d^{2} - 3 \, {\left (b^{2} c - 2 \, a c^{2}\right )} d e + {\left (b^{3} - 3 \, a b c\right )} e^{2}\right )} n\right )} \log \left (c x^{2} + b x + a\right ) - 6 \, {\left (c^{3} e^{2} x^{3} + 3 \, c^{3} d e x^{2} + 3 \, c^{3} d^{2} x\right )} \log \left (d\right )}{18 \, c^{3}}, -\frac {4 \, c^{3} e^{2} n x^{3} + 3 \, {\left (6 \, c^{3} d e - b c^{2} e^{2}\right )} n x^{2} - 6 \, {\left (3 \, c^{2} d^{2} - 3 \, b c d e + {\left (b^{2} - a c\right )} e^{2}\right )} \sqrt {-b^{2} + 4 \, a c} n \arctan \left (-\frac {\sqrt {-b^{2} + 4 \, a c} {\left (2 \, c x + b\right )}}{b^{2} - 4 \, a c}\right ) + 6 \, {\left (6 \, c^{3} d^{2} - 3 \, b c^{2} d e + {\left (b^{2} c - 2 \, a c^{2}\right )} e^{2}\right )} n x - 3 \, {\left (2 \, c^{3} e^{2} n x^{3} + 6 \, c^{3} d e n x^{2} + 6 \, c^{3} d^{2} n x + {\left (3 \, b c^{2} d^{2} - 3 \, {\left (b^{2} c - 2 \, a c^{2}\right )} d e + {\left (b^{3} - 3 \, a b c\right )} e^{2}\right )} n\right )} \log \left (c x^{2} + b x + a\right ) - 6 \, {\left (c^{3} e^{2} x^{3} + 3 \, c^{3} d e x^{2} + 3 \, c^{3} d^{2} x\right )} \log \left (d\right )}{18 \, c^{3}}\right ] \]
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Timed out. \[ \int (d+e x)^2 \log \left (d \left (a+b x+c x^2\right )^n\right ) \, dx=\text {Timed out} \]
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Exception generated. \[ \int (d+e x)^2 \log \left (d \left (a+b x+c x^2\right )^n\right ) \, dx=\text {Exception raised: ValueError} \]
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Time = 0.34 (sec) , antiderivative size = 307, normalized size of antiderivative = 1.36 \[ \int (d+e x)^2 \log \left (d \left (a+b x+c x^2\right )^n\right ) \, dx=-\frac {1}{9} \, {\left (2 \, e^{2} n - 3 \, e^{2} \log \left (d\right )\right )} x^{3} - \frac {{\left (6 \, c d e n - b e^{2} n - 6 \, c d e \log \left (d\right )\right )} x^{2}}{6 \, c} + \frac {1}{3} \, {\left (e^{2} n x^{3} + 3 \, d e n x^{2} + 3 \, d^{2} n x\right )} \log \left (c x^{2} + b x + a\right ) - \frac {{\left (6 \, c^{2} d^{2} n - 3 \, b c d e n + b^{2} e^{2} n - 2 \, a c e^{2} n - 3 \, c^{2} d^{2} \log \left (d\right )\right )} x}{3 \, c^{2}} + \frac {{\left (3 \, b c^{2} d^{2} n - 3 \, b^{2} c d e n + 6 \, a c^{2} d e n + b^{3} e^{2} n - 3 \, a b c e^{2} n\right )} \log \left (c x^{2} + b x + a\right )}{6 \, c^{3}} - \frac {{\left (3 \, b^{2} c^{2} d^{2} n - 12 \, a c^{3} d^{2} n - 3 \, b^{3} c d e n + 12 \, a b c^{2} d e n + b^{4} e^{2} n - 5 \, a b^{2} c e^{2} n + 4 \, a^{2} c^{2} e^{2} n\right )} \arctan \left (\frac {2 \, c x + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{3 \, \sqrt {-b^{2} + 4 \, a c} c^{3}} \]
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Time = 1.75 (sec) , antiderivative size = 457, normalized size of antiderivative = 2.02 \[ \int (d+e x)^2 \log \left (d \left (a+b x+c x^2\right )^n\right ) \, dx=\ln \left (b\,\sqrt {b^2-4\,a\,c}-4\,a\,c+b^2+2\,c\,x\,\sqrt {b^2-4\,a\,c}\right )\,\left (\frac {\frac {d^2\,n\,\sqrt {b^2-4\,a\,c}}{2}+\frac {b\,d^2\,n}{2}+a\,d\,e\,n}{c}-\frac {\frac {a\,b\,e^2\,n}{2}+\frac {b^2\,d\,e\,n}{2}+\frac {a\,e^2\,n\,\sqrt {b^2-4\,a\,c}}{6}+\frac {b\,d\,e\,n\,\sqrt {b^2-4\,a\,c}}{2}}{c^2}+\frac {b^3\,e^2\,n}{6\,c^3}+\frac {b^2\,e^2\,n\,\sqrt {b^2-4\,a\,c}}{6\,c^3}\right )+x\,\left (\frac {b\,\left (\frac {e\,n\,\left (b\,e+6\,c\,d\right )}{3\,c}-\frac {2\,b\,e^2\,n}{3\,c}\right )}{c}-\frac {d\,n\,\left (b\,e+2\,c\,d\right )}{c}+\frac {2\,a\,e^2\,n}{3\,c}\right )-\ln \left (4\,a\,c+b\,\sqrt {b^2-4\,a\,c}-b^2+2\,c\,x\,\sqrt {b^2-4\,a\,c}\right )\,\left (\frac {\frac {a\,b\,e^2\,n}{2}+\frac {b^2\,d\,e\,n}{2}-\frac {a\,e^2\,n\,\sqrt {b^2-4\,a\,c}}{6}-\frac {b\,d\,e\,n\,\sqrt {b^2-4\,a\,c}}{2}}{c^2}-\frac {\frac {b\,d^2\,n}{2}-\frac {d^2\,n\,\sqrt {b^2-4\,a\,c}}{2}+a\,d\,e\,n}{c}-\frac {b^3\,e^2\,n}{6\,c^3}+\frac {b^2\,e^2\,n\,\sqrt {b^2-4\,a\,c}}{6\,c^3}\right )+\ln \left (d\,{\left (c\,x^2+b\,x+a\right )}^n\right )\,\left (d^2\,x+d\,e\,x^2+\frac {e^2\,x^3}{3}\right )-x^2\,\left (\frac {e\,n\,\left (b\,e+6\,c\,d\right )}{6\,c}-\frac {b\,e^2\,n}{3\,c}\right )-\frac {2\,e^2\,n\,x^3}{9} \]
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