Integrand size = 20, antiderivative size = 132 \[ \int x^3 \log \left (1+e \left (f^{c (a+b x)}\right )^n\right ) \, dx=-\frac {x^3 \operatorname {PolyLog}\left (2,-e \left (f^{c (a+b x)}\right )^n\right )}{b c n \log (f)}+\frac {3 x^2 \operatorname {PolyLog}\left (3,-e \left (f^{c (a+b x)}\right )^n\right )}{b^2 c^2 n^2 \log ^2(f)}-\frac {6 x \operatorname {PolyLog}\left (4,-e \left (f^{c (a+b x)}\right )^n\right )}{b^3 c^3 n^3 \log ^3(f)}+\frac {6 \operatorname {PolyLog}\left (5,-e \left (f^{c (a+b x)}\right )^n\right )}{b^4 c^4 n^4 \log ^4(f)} \]
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Time = 0.07 (sec) , antiderivative size = 132, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2611, 6744, 2320, 6724} \[ \int x^3 \log \left (1+e \left (f^{c (a+b x)}\right )^n\right ) \, dx=\frac {6 \operatorname {PolyLog}\left (5,-e \left (f^{c (a+b x)}\right )^n\right )}{b^4 c^4 n^4 \log ^4(f)}-\frac {6 x \operatorname {PolyLog}\left (4,-e \left (f^{c (a+b x)}\right )^n\right )}{b^3 c^3 n^3 \log ^3(f)}+\frac {3 x^2 \operatorname {PolyLog}\left (3,-e \left (f^{c (a+b x)}\right )^n\right )}{b^2 c^2 n^2 \log ^2(f)}-\frac {x^3 \operatorname {PolyLog}\left (2,-e \left (f^{c (a+b x)}\right )^n\right )}{b c n \log (f)} \]
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Rule 2320
Rule 2611
Rule 6724
Rule 6744
Rubi steps \begin{align*} \text {integral}& = -\frac {x^3 \text {Li}_2\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b c n \log (f)}+\frac {3 \int x^2 \text {Li}_2\left (-e \left (f^{c (a+b x)}\right )^n\right ) \, dx}{b c n \log (f)} \\ & = -\frac {x^3 \text {Li}_2\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b c n \log (f)}+\frac {3 x^2 \text {Li}_3\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b^2 c^2 n^2 \log ^2(f)}-\frac {6 \int x \text {Li}_3\left (-e \left (f^{c (a+b x)}\right )^n\right ) \, dx}{b^2 c^2 n^2 \log ^2(f)} \\ & = -\frac {x^3 \text {Li}_2\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b c n \log (f)}+\frac {3 x^2 \text {Li}_3\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b^2 c^2 n^2 \log ^2(f)}-\frac {6 x \text {Li}_4\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b^3 c^3 n^3 \log ^3(f)}+\frac {6 \int \text {Li}_4\left (-e \left (f^{c (a+b x)}\right )^n\right ) \, dx}{b^3 c^3 n^3 \log ^3(f)} \\ & = -\frac {x^3 \text {Li}_2\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b c n \log (f)}+\frac {3 x^2 \text {Li}_3\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b^2 c^2 n^2 \log ^2(f)}-\frac {6 x \text {Li}_4\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b^3 c^3 n^3 \log ^3(f)}+\frac {6 \text {Subst}\left (\int \frac {\text {Li}_4\left (-e x^n\right )}{x} \, dx,x,f^{c (a+b x)}\right )}{b^4 c^4 n^3 \log ^4(f)} \\ & = -\frac {x^3 \text {Li}_2\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b c n \log (f)}+\frac {3 x^2 \text {Li}_3\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b^2 c^2 n^2 \log ^2(f)}-\frac {6 x \text {Li}_4\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b^3 c^3 n^3 \log ^3(f)}+\frac {6 \text {Li}_5\left (-e \left (f^{c (a+b x)}\right )^n\right )}{b^4 c^4 n^4 \log ^4(f)} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 132, normalized size of antiderivative = 1.00 \[ \int x^3 \log \left (1+e \left (f^{c (a+b x)}\right )^n\right ) \, dx=-\frac {x^3 \operatorname {PolyLog}\left (2,-e \left (f^{c (a+b x)}\right )^n\right )}{b c n \log (f)}+\frac {3 x^2 \operatorname {PolyLog}\left (3,-e \left (f^{c (a+b x)}\right )^n\right )}{b^2 c^2 n^2 \log ^2(f)}-\frac {6 x \operatorname {PolyLog}\left (4,-e \left (f^{c (a+b x)}\right )^n\right )}{b^3 c^3 n^3 \log ^3(f)}+\frac {6 \operatorname {PolyLog}\left (5,-e \left (f^{c (a+b x)}\right )^n\right )}{b^4 c^4 n^4 \log ^4(f)} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(600\) vs. \(2(132)=264\).
Time = 2.09 (sec) , antiderivative size = 601, normalized size of antiderivative = 4.55
method | result | size |
risch | \(\frac {x^{4} \ln \left (1+e \left (f^{c \left (b x +a \right )}\right )^{n}\right )}{4}-\frac {\operatorname {Li}_{2}\left (-f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right ) \ln \left (f^{c \left (b x +a \right )}\right )^{3}}{c^{4} b^{4} \ln \left (f \right )^{4} n}+\frac {\operatorname {dilog}\left (1+f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right ) \ln \left (f^{c \left (b x +a \right )}\right )^{3}}{c^{4} b^{4} \ln \left (f \right )^{4} n}+\frac {3 \,\operatorname {Li}_{3}\left (-f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right ) x^{2}}{c^{2} b^{2} \ln \left (f \right )^{2} n^{2}}-\frac {\ln \left (1+f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right ) x^{4}}{4}-\frac {6 \,\operatorname {Li}_{4}\left (-f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right ) x}{c^{3} b^{3} \ln \left (f \right )^{3} n^{3}}-\frac {\operatorname {dilog}\left (1+f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right ) x^{3}}{c b \ln \left (f \right ) n}+\frac {6 \,\operatorname {Li}_{5}\left (-f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right )}{c^{4} b^{4} \ln \left (f \right )^{4} n^{4}}+\frac {3 \operatorname {dilog}\left (1+f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right ) \ln \left (f^{c \left (b x +a \right )}\right ) x^{2}}{c^{2} b^{2} \ln \left (f \right )^{2} n}-\frac {3 \operatorname {dilog}\left (1+f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right ) \ln \left (f^{c \left (b x +a \right )}\right )^{2} x}{c^{3} b^{3} \ln \left (f \right )^{3} n}+\frac {3 \,\operatorname {Li}_{2}\left (-f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right ) \ln \left (f^{c \left (b x +a \right )}\right )^{2} x}{c^{3} b^{3} \ln \left (f \right )^{3} n}-\frac {3 \,\operatorname {Li}_{2}\left (-f^{x b c n} f^{-x b c n} \left (f^{c \left (b x +a \right )}\right )^{n} e \right ) \ln \left (f^{c \left (b x +a \right )}\right ) x^{2}}{c^{2} b^{2} \ln \left (f \right )^{2} n}\) | \(601\) |
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Time = 0.34 (sec) , antiderivative size = 128, normalized size of antiderivative = 0.97 \[ \int x^3 \log \left (1+e \left (f^{c (a+b x)}\right )^n\right ) \, dx=-\frac {b^{3} c^{3} n^{3} x^{3} {\rm Li}_2\left (-e f^{b c n x + a c n}\right ) \log \left (f\right )^{3} - 3 \, b^{2} c^{2} n^{2} x^{2} \log \left (f\right )^{2} {\rm polylog}\left (3, -e f^{b c n x + a c n}\right ) + 6 \, b c n x \log \left (f\right ) {\rm polylog}\left (4, -e f^{b c n x + a c n}\right ) - 6 \, {\rm polylog}\left (5, -e f^{b c n x + a c n}\right )}{b^{4} c^{4} n^{4} \log \left (f\right )^{4}} \]
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\[ \int x^3 \log \left (1+e \left (f^{c (a+b x)}\right )^n\right ) \, dx=\int x^{3} \log {\left (e \left (f^{a c + b c x}\right )^{n} + 1 \right )}\, dx \]
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Time = 0.23 (sec) , antiderivative size = 189, normalized size of antiderivative = 1.43 \[ \int x^3 \log \left (1+e \left (f^{c (a+b x)}\right )^n\right ) \, dx=\frac {1}{4} \, x^{4} \log \left (e f^{{\left (b x + a\right )} c n} + 1\right ) - \frac {b^{4} c^{4} n^{4} x^{4} \log \left (e f^{b c n x} f^{a c n} + 1\right ) \log \left (f\right )^{4} + 4 \, b^{3} c^{3} n^{3} x^{3} {\rm Li}_2\left (-e f^{b c n x} f^{a c n}\right ) \log \left (f\right )^{3} - 12 \, b^{2} c^{2} n^{2} x^{2} \log \left (f\right )^{2} {\rm Li}_{3}(-e f^{b c n x} f^{a c n}) + 24 \, b c n x \log \left (f\right ) {\rm Li}_{4}(-e f^{b c n x} f^{a c n}) - 24 \, {\rm Li}_{5}(-e f^{b c n x} f^{a c n})}{4 \, b^{4} c^{4} n^{4} \log \left (f\right )^{4}} \]
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\[ \int x^3 \log \left (1+e \left (f^{c (a+b x)}\right )^n\right ) \, dx=\int { x^{3} \log \left (e {\left (f^{{\left (b x + a\right )} c}\right )}^{n} + 1\right ) \,d x } \]
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Timed out. \[ \int x^3 \log \left (1+e \left (f^{c (a+b x)}\right )^n\right ) \, dx=\int x^3\,\ln \left (e\,{\left (f^{c\,\left (a+b\,x\right )}\right )}^n+1\right ) \,d x \]
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