Integrand size = 5, antiderivative size = 51 \[ \int \log (a \tan (x)) \, dx=2 x \text {arctanh}\left (e^{2 i x}\right )+x \log (a \tan (x))-\frac {1}{2} i \operatorname {PolyLog}\left (2,-e^{2 i x}\right )+\frac {1}{2} i \operatorname {PolyLog}\left (2,e^{2 i x}\right ) \]
[Out]
Time = 0.03 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.000, Rules used = {2628, 4504, 4268, 2317, 2438} \[ \int \log (a \tan (x)) \, dx=x \log (a \tan (x))+2 x \text {arctanh}\left (e^{2 i x}\right )-\frac {1}{2} i \operatorname {PolyLog}\left (2,-e^{2 i x}\right )+\frac {1}{2} i \operatorname {PolyLog}\left (2,e^{2 i x}\right ) \]
[In]
[Out]
Rule 2317
Rule 2438
Rule 2628
Rule 4268
Rule 4504
Rubi steps \begin{align*} \text {integral}& = x \log (a \tan (x))-\int x \csc (x) \sec (x) \, dx \\ & = x \log (a \tan (x))-2 \int x \csc (2 x) \, dx \\ & = 2 x \tanh ^{-1}\left (e^{2 i x}\right )+x \log (a \tan (x))+\int \log \left (1-e^{2 i x}\right ) \, dx-\int \log \left (1+e^{2 i x}\right ) \, dx \\ & = 2 x \tanh ^{-1}\left (e^{2 i x}\right )+x \log (a \tan (x))-\frac {1}{2} i \text {Subst}\left (\int \frac {\log (1-x)}{x} \, dx,x,e^{2 i x}\right )+\frac {1}{2} i \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 i x}\right ) \\ & = 2 x \tanh ^{-1}\left (e^{2 i x}\right )+x \log (a \tan (x))-\frac {1}{2} i \text {Li}_2\left (-e^{2 i x}\right )+\frac {1}{2} i \text {Li}_2\left (e^{2 i x}\right ) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.47 \[ \int \log (a \tan (x)) \, dx=-\frac {1}{2} i \log (-i (i-\tan (x))) \log (a \tan (x))+\frac {1}{2} i \log (a \tan (x)) \log (-i (i+\tan (x)))-\frac {1}{2} i \operatorname {PolyLog}(2,-i \tan (x))+\frac {1}{2} i \operatorname {PolyLog}(2,i \tan (x)) \]
[In]
[Out]
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 84 vs. \(2 (39 ) = 78\).
Time = 1.04 (sec) , antiderivative size = 85, normalized size of antiderivative = 1.67
method | result | size |
derivativedivides | \(a \left (-\frac {i \ln \left (a \tan \left (x \right )\right ) \left (\ln \left (\frac {i \tan \left (x \right ) a +a}{a}\right )-\ln \left (-\frac {i \tan \left (x \right ) a -a}{a}\right )\right )}{2 a}-\frac {i \left (\operatorname {dilog}\left (\frac {i \tan \left (x \right ) a +a}{a}\right )-\operatorname {dilog}\left (-\frac {i \tan \left (x \right ) a -a}{a}\right )\right )}{2 a}\right )\) | \(85\) |
default | \(a \left (-\frac {i \ln \left (a \tan \left (x \right )\right ) \left (\ln \left (\frac {i \tan \left (x \right ) a +a}{a}\right )-\ln \left (-\frac {i \tan \left (x \right ) a -a}{a}\right )\right )}{2 a}-\frac {i \left (\operatorname {dilog}\left (\frac {i \tan \left (x \right ) a +a}{a}\right )-\operatorname {dilog}\left (-\frac {i \tan \left (x \right ) a -a}{a}\right )\right )}{2 a}\right )\) | \(85\) |
risch | \(-x \ln \left (1+{\mathrm e}^{2 i x}\right )-\frac {i \pi \,\operatorname {csgn}\left (i \left ({\mathrm e}^{2 i x}-1\right )\right ) \operatorname {csgn}\left (\frac {i}{1+{\mathrm e}^{2 i x}}\right ) \operatorname {csgn}\left (\frac {i \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right ) x}{2}-\frac {i \pi {\operatorname {csgn}\left (\frac {i a \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right )}^{3} x}{2}-i \ln \left ({\mathrm e}^{i x}\right ) \ln \left ({\mathrm e}^{2 i x}-1\right )-\frac {i \pi x}{2}-\frac {i \pi \,\operatorname {csgn}\left (\frac {i a \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right ) \operatorname {csgn}\left (\frac {a \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right ) x}{2}+\frac {i \pi \,\operatorname {csgn}\left (\frac {i \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right ) {\operatorname {csgn}\left (\frac {i a \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right )}^{2} x}{2}+\ln \left (a \right ) x -\frac {i \pi {\operatorname {csgn}\left (\frac {a \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right )}^{3} x}{2}+i \ln \left ({\mathrm e}^{i x}\right ) \ln \left ({\mathrm e}^{i x}+1\right )-\frac {i \pi \,\operatorname {csgn}\left (\frac {i \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right ) \operatorname {csgn}\left (\frac {i a \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right ) \operatorname {csgn}\left (i a \right ) x}{2}+i \operatorname {dilog}\left ({\mathrm e}^{i x}+1\right )+x \ln \left (1+i {\mathrm e}^{i x}\right )+x \ln \left (1-i {\mathrm e}^{i x}\right )+\frac {i \pi \,\operatorname {csgn}\left (\frac {i a \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right ) {\operatorname {csgn}\left (\frac {a \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right )}^{2} x}{2}-i \operatorname {dilog}\left (1+i {\mathrm e}^{i x}\right )-i \operatorname {dilog}\left ({\mathrm e}^{i x}\right )+\frac {i \pi {\operatorname {csgn}\left (\frac {i a \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right )}^{2} \operatorname {csgn}\left (i a \right ) x}{2}+\frac {i \pi \,\operatorname {csgn}\left (\frac {i}{1+{\mathrm e}^{2 i x}}\right ) {\operatorname {csgn}\left (\frac {i \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right )}^{2} x}{2}+\frac {i \pi {\operatorname {csgn}\left (\frac {a \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right )}^{2} x}{2}-i \operatorname {dilog}\left (1-i {\mathrm e}^{i x}\right )+\frac {i \pi \,\operatorname {csgn}\left (i \left ({\mathrm e}^{2 i x}-1\right )\right ) {\operatorname {csgn}\left (\frac {i \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right )}^{2} x}{2}-\frac {i \pi {\operatorname {csgn}\left (\frac {i \left ({\mathrm e}^{2 i x}-1\right )}{1+{\mathrm e}^{2 i x}}\right )}^{3} x}{2}\) | \(588\) |
[In]
[Out]
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 184 vs. \(2 (32) = 64\).
Time = 0.36 (sec) , antiderivative size = 184, normalized size of antiderivative = 3.61 \[ \int \log (a \tan (x)) \, dx=x \log \left (a \tan \left (x\right )\right ) - \frac {1}{2} \, x \log \left (\frac {2 \, {\left (\tan \left (x\right )^{2} + i \, \tan \left (x\right )\right )}}{\tan \left (x\right )^{2} + 1}\right ) - \frac {1}{2} \, x \log \left (\frac {2 \, {\left (\tan \left (x\right )^{2} - i \, \tan \left (x\right )\right )}}{\tan \left (x\right )^{2} + 1}\right ) + \frac {1}{2} \, x \log \left (-\frac {2 \, {\left (i \, \tan \left (x\right ) - 1\right )}}{\tan \left (x\right )^{2} + 1}\right ) + \frac {1}{2} \, x \log \left (-\frac {2 \, {\left (-i \, \tan \left (x\right ) - 1\right )}}{\tan \left (x\right )^{2} + 1}\right ) - \frac {1}{4} i \, {\rm Li}_2\left (-\frac {2 \, {\left (\tan \left (x\right )^{2} + i \, \tan \left (x\right )\right )}}{\tan \left (x\right )^{2} + 1} + 1\right ) + \frac {1}{4} i \, {\rm Li}_2\left (-\frac {2 \, {\left (\tan \left (x\right )^{2} - i \, \tan \left (x\right )\right )}}{\tan \left (x\right )^{2} + 1} + 1\right ) + \frac {1}{4} i \, {\rm Li}_2\left (\frac {2 \, {\left (i \, \tan \left (x\right ) - 1\right )}}{\tan \left (x\right )^{2} + 1} + 1\right ) - \frac {1}{4} i \, {\rm Li}_2\left (\frac {2 \, {\left (-i \, \tan \left (x\right ) - 1\right )}}{\tan \left (x\right )^{2} + 1} + 1\right ) \]
[In]
[Out]
\[ \int \log (a \tan (x)) \, dx=\int \log {\left (a \tan {\left (x \right )} \right )}\, dx \]
[In]
[Out]
none
Time = 0.31 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.82 \[ \int \log (a \tan (x)) \, dx=x \log \left (a \tan \left (x\right )\right ) + \frac {1}{4} \, \pi \log \left (\tan \left (x\right )^{2} + 1\right ) - x \log \left (\tan \left (x\right )\right ) + \frac {1}{2} i \, {\rm Li}_2\left (i \, \tan \left (x\right ) + 1\right ) - \frac {1}{2} i \, {\rm Li}_2\left (-i \, \tan \left (x\right ) + 1\right ) \]
[In]
[Out]
\[ \int \log (a \tan (x)) \, dx=\int { \log \left (a \tan \left (x\right )\right ) \,d x } \]
[In]
[Out]
Time = 0.09 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.76 \[ \int \log (a \tan (x)) \, dx=2\,x\,\mathrm {atanh}\left ({\mathrm {e}}^{x\,2{}\mathrm {i}}\right )+x\,\ln \left (a\,\mathrm {tan}\left (x\right )\right )-\frac {\mathrm {polylog}\left (2,-{\mathrm {e}}^{x\,2{}\mathrm {i}}\right )\,1{}\mathrm {i}}{2}+\frac {\mathrm {polylog}\left (2,{\mathrm {e}}^{x\,2{}\mathrm {i}}\right )\,1{}\mathrm {i}}{2} \]
[In]
[Out]