Integrand size = 15, antiderivative size = 122 \[ \int \frac {\log \left (1+\sqrt {x}-x\right )}{x} \, dx=-2 \log \left (\frac {1}{2} \left (1+\sqrt {5}\right )\right ) \log \left (1+\sqrt {5}-2 \sqrt {x}\right )-2 \log \left (1-\frac {2 \sqrt {x}}{1-\sqrt {5}}\right ) \log \left (\sqrt {x}\right )+2 \log \left (1+\sqrt {x}-x\right ) \log \left (\sqrt {x}\right )+2 \operatorname {PolyLog}\left (2,1-\frac {2 \sqrt {x}}{1+\sqrt {5}}\right )-2 \operatorname {PolyLog}\left (2,\frac {2 \sqrt {x}}{1-\sqrt {5}}\right ) \]
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Time = 0.10 (sec) , antiderivative size = 122, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.467, Rules used = {2610, 2604, 2404, 2354, 2438, 2353, 2352} \[ \int \frac {\log \left (1+\sqrt {x}-x\right )}{x} \, dx=2 \operatorname {PolyLog}\left (2,1-\frac {2 \sqrt {x}}{1+\sqrt {5}}\right )-2 \operatorname {PolyLog}\left (2,\frac {2 \sqrt {x}}{1-\sqrt {5}}\right )-2 \log \left (\frac {1}{2} \left (1+\sqrt {5}\right )\right ) \log \left (-2 \sqrt {x}+\sqrt {5}+1\right )-2 \log \left (1-\frac {2 \sqrt {x}}{1-\sqrt {5}}\right ) \log \left (\sqrt {x}\right )+2 \log \left (-x+\sqrt {x}+1\right ) \log \left (\sqrt {x}\right ) \]
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Rule 2352
Rule 2353
Rule 2354
Rule 2404
Rule 2438
Rule 2604
Rule 2610
Rubi steps \begin{align*} \text {integral}& = 2 \text {Subst}\left (\int \frac {\log \left (1+x-x^2\right )}{x} \, dx,x,\sqrt {x}\right ) \\ & = 2 \log \left (1+\sqrt {x}-x\right ) \log \left (\sqrt {x}\right )-2 \text {Subst}\left (\int \frac {(1-2 x) \log (x)}{1+x-x^2} \, dx,x,\sqrt {x}\right ) \\ & = 2 \log \left (1+\sqrt {x}-x\right ) \log \left (\sqrt {x}\right )-2 \text {Subst}\left (\int \left (-\frac {2 \log (x)}{1-\sqrt {5}-2 x}-\frac {2 \log (x)}{1+\sqrt {5}-2 x}\right ) \, dx,x,\sqrt {x}\right ) \\ & = 2 \log \left (1+\sqrt {x}-x\right ) \log \left (\sqrt {x}\right )+4 \text {Subst}\left (\int \frac {\log (x)}{1-\sqrt {5}-2 x} \, dx,x,\sqrt {x}\right )+4 \text {Subst}\left (\int \frac {\log (x)}{1+\sqrt {5}-2 x} \, dx,x,\sqrt {x}\right ) \\ & = -2 \log \left (\frac {1}{2} \left (1+\sqrt {5}\right )\right ) \log \left (1+\sqrt {5}-2 \sqrt {x}\right )-2 \log \left (1-\frac {2 \sqrt {x}}{1-\sqrt {5}}\right ) \log \left (\sqrt {x}\right )+2 \log \left (1+\sqrt {x}-x\right ) \log \left (\sqrt {x}\right )+2 \text {Subst}\left (\int \frac {\log \left (1-\frac {2 x}{1-\sqrt {5}}\right )}{x} \, dx,x,\sqrt {x}\right )+4 \text {Subst}\left (\int \frac {\log \left (\frac {2 x}{1+\sqrt {5}}\right )}{1+\sqrt {5}-2 x} \, dx,x,\sqrt {x}\right ) \\ & = -2 \log \left (\frac {1}{2} \left (1+\sqrt {5}\right )\right ) \log \left (1+\sqrt {5}-2 \sqrt {x}\right )-2 \log \left (1-\frac {2 \sqrt {x}}{1-\sqrt {5}}\right ) \log \left (\sqrt {x}\right )+2 \log \left (1+\sqrt {x}-x\right ) \log \left (\sqrt {x}\right )+2 \text {Li}_2\left (1-\frac {2 \sqrt {x}}{1+\sqrt {5}}\right )-2 \text {Li}_2\left (\frac {2 \sqrt {x}}{1-\sqrt {5}}\right ) \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 121, normalized size of antiderivative = 0.99 \[ \int \frac {\log \left (1+\sqrt {x}-x\right )}{x} \, dx=-2 \log \left (\frac {1}{2} \left (1+\sqrt {5}\right )\right ) \log \left (1+\sqrt {5}-2 \sqrt {x}\right )+\left (\log \left (-1+\sqrt {5}\right )-\log \left (-1+\sqrt {5}+2 \sqrt {x}\right )\right ) \log (x)+\log \left (1+\sqrt {x}-x\right ) \log (x)+2 \operatorname {PolyLog}\left (2,\frac {1+\sqrt {5}-2 \sqrt {x}}{1+\sqrt {5}}\right )-2 \operatorname {PolyLog}\left (2,-\frac {2 \sqrt {x}}{-1+\sqrt {5}}\right ) \]
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Time = 0.59 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.84
method | result | size |
derivativedivides | \(\ln \left (x \right ) \ln \left (1-x +\sqrt {x}\right )-\ln \left (x \right ) \ln \left (\frac {1+\sqrt {5}-2 \sqrt {x}}{\sqrt {5}+1}\right )-\ln \left (x \right ) \ln \left (\frac {-1+\sqrt {5}+2 \sqrt {x}}{\sqrt {5}-1}\right )-2 \operatorname {dilog}\left (\frac {1+\sqrt {5}-2 \sqrt {x}}{\sqrt {5}+1}\right )-2 \operatorname {dilog}\left (\frac {-1+\sqrt {5}+2 \sqrt {x}}{\sqrt {5}-1}\right )\) | \(102\) |
default | \(\ln \left (x \right ) \ln \left (1-x +\sqrt {x}\right )-\ln \left (x \right ) \ln \left (\frac {1+\sqrt {5}-2 \sqrt {x}}{\sqrt {5}+1}\right )-\ln \left (x \right ) \ln \left (\frac {-1+\sqrt {5}+2 \sqrt {x}}{\sqrt {5}-1}\right )-2 \operatorname {dilog}\left (\frac {1+\sqrt {5}-2 \sqrt {x}}{\sqrt {5}+1}\right )-2 \operatorname {dilog}\left (\frac {-1+\sqrt {5}+2 \sqrt {x}}{\sqrt {5}-1}\right )\) | \(102\) |
parts | \(\ln \left (x \right ) \ln \left (1-x +\sqrt {x}\right )-\ln \left (x \right ) \ln \left (\frac {1+\sqrt {5}-2 \sqrt {x}}{\sqrt {5}+1}\right )-\ln \left (x \right ) \ln \left (\frac {-1+\sqrt {5}+2 \sqrt {x}}{\sqrt {5}-1}\right )-2 \operatorname {dilog}\left (\frac {1+\sqrt {5}-2 \sqrt {x}}{\sqrt {5}+1}\right )-2 \operatorname {dilog}\left (\frac {-1+\sqrt {5}+2 \sqrt {x}}{\sqrt {5}-1}\right )\) | \(102\) |
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\[ \int \frac {\log \left (1+\sqrt {x}-x\right )}{x} \, dx=\int { \frac {\log \left (-x + \sqrt {x} + 1\right )}{x} \,d x } \]
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\[ \int \frac {\log \left (1+\sqrt {x}-x\right )}{x} \, dx=\int \frac {\log {\left (\sqrt {x} - x + 1 \right )}}{x}\, dx \]
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\[ \int \frac {\log \left (1+\sqrt {x}-x\right )}{x} \, dx=\int { \frac {\log \left (-x + \sqrt {x} + 1\right )}{x} \,d x } \]
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\[ \int \frac {\log \left (1+\sqrt {x}-x\right )}{x} \, dx=\int { \frac {\log \left (-x + \sqrt {x} + 1\right )}{x} \,d x } \]
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Timed out. \[ \int \frac {\log \left (1+\sqrt {x}-x\right )}{x} \, dx=\int \frac {\ln \left (\sqrt {x}-x+1\right )}{x} \,d x \]
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