Integrand size = 14, antiderivative size = 69 \[ \int \log \left (-2+\sqrt {\frac {1+x}{x}}\right ) \, dx=\frac {1}{2} \log \left (1-\sqrt {1+\frac {1}{x}}\right )-\frac {1}{3} \log \left (2-\sqrt {1+\frac {1}{x}}\right )-\frac {1}{6} \log \left (1+\sqrt {1+\frac {1}{x}}\right )+x \log \left (-2+\sqrt {\frac {1+x}{x}}\right ) \]
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Time = 0.04 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {2628, 720, 31, 647} \[ \int \log \left (-2+\sqrt {\frac {1+x}{x}}\right ) \, dx=\frac {1}{2} \log \left (1-\sqrt {\frac {1}{x}+1}\right )-\frac {1}{3} \log \left (2-\sqrt {\frac {1}{x}+1}\right )-\frac {1}{6} \log \left (\sqrt {\frac {1}{x}+1}+1\right )+x \log \left (\sqrt {\frac {x+1}{x}}-2\right ) \]
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Rule 31
Rule 647
Rule 720
Rule 2628
Rubi steps \begin{align*} \text {integral}& = x \log \left (-2+\sqrt {\frac {1+x}{x}}\right )-\int \frac {1}{-2+\left (-2+4 \sqrt {1+\frac {1}{x}}\right ) x} \, dx \\ & = x \log \left (-2+\sqrt {\frac {1+x}{x}}\right )-\text {Subst}\left (\int \frac {1}{(-2+x) \left (-1+x^2\right )} \, dx,x,\sqrt {1+\frac {1}{x}}\right ) \\ & = x \log \left (-2+\sqrt {\frac {1+x}{x}}\right )-\frac {1}{3} \text {Subst}\left (\int \frac {1}{-2+x} \, dx,x,\sqrt {1+\frac {1}{x}}\right )-\frac {1}{3} \text {Subst}\left (\int \frac {-2-x}{-1+x^2} \, dx,x,\sqrt {1+\frac {1}{x}}\right ) \\ & = -\frac {1}{3} \log \left (2-\sqrt {1+\frac {1}{x}}\right )+x \log \left (-2+\sqrt {\frac {1+x}{x}}\right )-\frac {1}{6} \text {Subst}\left (\int \frac {1}{1+x} \, dx,x,\sqrt {1+\frac {1}{x}}\right )+\frac {1}{2} \text {Subst}\left (\int \frac {1}{-1+x} \, dx,x,\sqrt {1+\frac {1}{x}}\right ) \\ & = \frac {1}{2} \log \left (1-\sqrt {1+\frac {1}{x}}\right )-\frac {1}{3} \log \left (2-\sqrt {1+\frac {1}{x}}\right )-\frac {1}{6} \log \left (1+\sqrt {1+\frac {1}{x}}\right )+x \log \left (-2+\sqrt {\frac {1+x}{x}}\right ) \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.93 \[ \int \log \left (-2+\sqrt {\frac {1+x}{x}}\right ) \, dx=\frac {1}{6} \left (-6 \text {arctanh}\left (3-2 \sqrt {1+\frac {1}{x}}\right )+\log \left (2-\sqrt {1+\frac {1}{x}}\right )+6 x \log \left (-2+\sqrt {1+\frac {1}{x}}\right )-\log \left (1+\sqrt {1+\frac {1}{x}}\right )\right ) \]
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Time = 0.16 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.57
method | result | size |
default | \(x \ln \left (-2+\sqrt {\frac {x +1}{x}}\right )-\frac {3 \sqrt {\frac {x +1}{x}}\, x \ln \left (-3 x +1\right )-\sqrt {9}\, \ln \left (\frac {4 \sqrt {9}\, \sqrt {x^{2}+x}+15 x +3}{9 x -3}\right ) \sqrt {x \left (x +1\right )}+6 \ln \left (\frac {1}{2}+x +\sqrt {x^{2}+x}\right ) \sqrt {x \left (x +1\right )}}{18 \sqrt {\frac {x +1}{x}}\, x}\) | \(108\) |
parts | \(x \ln \left (-2+\sqrt {\frac {x +1}{x}}\right )-\frac {3 \sqrt {\frac {x +1}{x}}\, x \ln \left (-3 x +1\right )-\sqrt {9}\, \ln \left (\frac {4 \sqrt {9}\, \sqrt {x^{2}+x}+15 x +3}{9 x -3}\right ) \sqrt {x \left (x +1\right )}+6 \ln \left (\frac {1}{2}+x +\sqrt {x^{2}+x}\right ) \sqrt {x \left (x +1\right )}}{18 \sqrt {\frac {x +1}{x}}\, x}\) | \(108\) |
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Time = 0.30 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.70 \[ \int \log \left (-2+\sqrt {\frac {1+x}{x}}\right ) \, dx=\frac {1}{3} \, {\left (3 \, x - 1\right )} \log \left (\sqrt {\frac {x + 1}{x}} - 2\right ) - \frac {1}{6} \, \log \left (\sqrt {\frac {x + 1}{x}} + 1\right ) + \frac {1}{2} \, \log \left (\sqrt {\frac {x + 1}{x}} - 1\right ) \]
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Time = 46.32 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.77 \[ \int \log \left (-2+\sqrt {\frac {1+x}{x}}\right ) \, dx=x \log {\left (\sqrt {\frac {x + 1}{x}} - 2 \right )} - \frac {\log {\left (\sqrt {1 + \frac {1}{x}} - 2 \right )}}{3} + \frac {\log {\left (\sqrt {1 + \frac {1}{x}} - 1 \right )}}{2} - \frac {\log {\left (\sqrt {1 + \frac {1}{x}} + 1 \right )}}{6} \]
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Time = 0.22 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.97 \[ \int \log \left (-2+\sqrt {\frac {1+x}{x}}\right ) \, dx=\frac {\log \left (\sqrt {\frac {x + 1}{x}} - 2\right )}{\frac {x + 1}{x} - 1} - \frac {1}{6} \, \log \left (\sqrt {\frac {x + 1}{x}} + 1\right ) + \frac {1}{2} \, \log \left (\sqrt {\frac {x + 1}{x}} - 1\right ) - \frac {1}{3} \, \log \left (\sqrt {\frac {x + 1}{x}} - 2\right ) \]
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Time = 0.35 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.28 \[ \int \log \left (-2+\sqrt {\frac {1+x}{x}}\right ) \, dx=x \log \left (\sqrt {\frac {x + 1}{x}} - 2\right ) + \frac {\log \left ({\left | -x + \sqrt {x^{2} + x} + 1 \right |}\right )}{6 \, \mathrm {sgn}\left (x\right )} + \frac {\log \left ({\left | -2 \, x + 2 \, \sqrt {x^{2} + x} - 1 \right |}\right )}{3 \, \mathrm {sgn}\left (x\right )} - \frac {\log \left ({\left | -3 \, x + 3 \, \sqrt {x^{2} + x} - 1 \right |}\right )}{6 \, \mathrm {sgn}\left (x\right )} - \frac {1}{6} \, \log \left ({\left | 3 \, x - 1 \right |}\right ) \]
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Time = 0.34 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.91 \[ \int \log \left (-2+\sqrt {\frac {1+x}{x}}\right ) \, dx=\frac {\ln \left (5-5\,\sqrt {\frac {x+1}{x}}\right )}{2}-\frac {\ln \left (\frac {\sqrt {\frac {x+1}{x}}}{9}+\frac {1}{9}\right )}{6}-\frac {\ln \left (\frac {10}{9}-\frac {5\,\sqrt {\frac {x+1}{x}}}{9}\right )}{3}+x\,\ln \left (\sqrt {\frac {x+1}{x}}-2\right ) \]
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