Integrand size = 40, antiderivative size = 49 \[ \int \frac {\log \left (\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )}{d+e x^2} \, dx=\frac {\operatorname {PolyLog}\left (2,1-\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )}{2 \sqrt {d} \sqrt {-e}} \]
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Time = 0.07 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.025, Rules used = {2497} \[ \int \frac {\log \left (\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )}{d+e x^2} \, dx=\frac {\operatorname {PolyLog}\left (2,1-\frac {2 x \left (e x+\sqrt {d} \sqrt {-e}\right )}{e x^2+d}\right )}{2 \sqrt {d} \sqrt {-e}} \]
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Rule 2497
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Li}_2\left (1-\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )}{2 \sqrt {d} \sqrt {-e}} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(641\) vs. \(2(49)=98\).
Time = 0.25 (sec) , antiderivative size = 641, normalized size of antiderivative = 13.08 \[ \int \frac {\log \left (\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )}{d+e x^2} \, dx=\frac {-2 \log \left (\frac {\sqrt {e} x}{\sqrt {-d}}\right ) \log \left (\sqrt {-d}-\sqrt {e} x\right )+\log ^2\left (\sqrt {-d}-\sqrt {e} x\right )+2 \log \left (\frac {d \sqrt {e} x}{(-d)^{3/2}}\right ) \log \left (\sqrt {-d}+\sqrt {e} x\right )-\log ^2\left (\sqrt {-d}+\sqrt {e} x\right )+2 \log \left (\sqrt {-d}-\sqrt {e} x\right ) \log \left (\frac {d-\sqrt {-d} \sqrt {e} x}{2 d}\right )-2 \log \left (\sqrt {-d}+\sqrt {e} x\right ) \log \left (\frac {d+\sqrt {-d} \sqrt {e} x}{2 d}\right )+2 \log \left (\sqrt {-d}+\sqrt {e} x\right ) \log \left (\frac {\sqrt {d} \sqrt {-e}+e x}{\sqrt {d} \sqrt {-e}-\sqrt {-d} \sqrt {e}}\right )-2 \log \left (\sqrt {-d}-\sqrt {e} x\right ) \log \left (\frac {\sqrt {d} \sqrt {-e}+e x}{\sqrt {d} \sqrt {-e}+\sqrt {-d} \sqrt {e}}\right )+2 \log \left (\sqrt {-d}-\sqrt {e} x\right ) \log \left (\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )-2 \log \left (\sqrt {-d}+\sqrt {e} x\right ) \log \left (\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )+2 \operatorname {PolyLog}\left (2,1+\frac {\sqrt {e} x}{\sqrt {-d}}\right )-2 \operatorname {PolyLog}\left (2,\frac {d-\sqrt {-d} \sqrt {e} x}{2 d}\right )+2 \operatorname {PolyLog}\left (2,\frac {d+\sqrt {-d} \sqrt {e} x}{2 d}\right )-2 \operatorname {PolyLog}\left (2,1+\frac {d \sqrt {e} x}{(-d)^{3/2}}\right )-2 \operatorname {PolyLog}\left (2,\frac {\sqrt {-d} \sqrt {e}-e x}{\sqrt {d} \sqrt {-e}+\sqrt {-d} \sqrt {e}}\right )+2 \operatorname {PolyLog}\left (2,\frac {\sqrt {-d} \sqrt {e}+e x}{-\sqrt {d} \sqrt {-e}+\sqrt {-d} \sqrt {e}}\right )}{4 \sqrt {-d} \sqrt {e}} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 1.61 (sec) , antiderivative size = 233, normalized size of antiderivative = 4.76
method | result | size |
risch | \(\frac {\ln \left (2\right ) \arctan \left (\frac {x e}{\sqrt {d e}}\right )}{\sqrt {d e}}+\frac {\munderset {\underline {\hspace {1.25 ex}}\alpha =\operatorname {RootOf}\left (e \,\textit {\_Z}^{2}+d \right )}{\sum }\frac {2 \ln \left (x -\underline {\hspace {1.25 ex}}\alpha \right ) \ln \left (\frac {x \left (e x +\sqrt {d}\, \sqrt {-e}\right )}{e \,x^{2}+d}\right )+e \left (\frac {\ln \left (x -\underline {\hspace {1.25 ex}}\alpha \right )^{2}}{\underline {\hspace {1.25 ex}}\alpha e}+\frac {2 \underline {\hspace {1.25 ex}}\alpha \ln \left (x -\underline {\hspace {1.25 ex}}\alpha \right ) \ln \left (\frac {x +\underline {\hspace {1.25 ex}}\alpha }{2 \underline {\hspace {1.25 ex}}\alpha }\right )}{d}+\frac {2 \underline {\hspace {1.25 ex}}\alpha \operatorname {dilog}\left (\frac {x +\underline {\hspace {1.25 ex}}\alpha }{2 \underline {\hspace {1.25 ex}}\alpha }\right )}{d}\right )-2 \operatorname {dilog}\left (\frac {\underline {\hspace {1.25 ex}}\alpha e +\sqrt {d}\, \sqrt {-e}+\left (x -\underline {\hspace {1.25 ex}}\alpha \right ) e}{\underline {\hspace {1.25 ex}}\alpha e +\sqrt {d}\, \sqrt {-e}}\right )-2 \ln \left (x -\underline {\hspace {1.25 ex}}\alpha \right ) \ln \left (\frac {\underline {\hspace {1.25 ex}}\alpha e +\sqrt {d}\, \sqrt {-e}+\left (x -\underline {\hspace {1.25 ex}}\alpha \right ) e}{\underline {\hspace {1.25 ex}}\alpha e +\sqrt {d}\, \sqrt {-e}}\right )-2 \operatorname {dilog}\left (\frac {x}{\underline {\hspace {1.25 ex}}\alpha }\right )-2 \ln \left (x -\underline {\hspace {1.25 ex}}\alpha \right ) \ln \left (\frac {x}{\underline {\hspace {1.25 ex}}\alpha }\right )}{\underline {\hspace {1.25 ex}}\alpha }}{4 e}\) | \(233\) |
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none
Time = 0.31 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.88 \[ \int \frac {\log \left (\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )}{d+e x^2} \, dx=-\frac {\sqrt {-e} {\rm Li}_2\left (-\frac {2 \, {\left (e x^{2} + \sqrt {d} \sqrt {-e} x\right )}}{e x^{2} + d} + 1\right )}{2 \, \sqrt {d} e} \]
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Exception generated. \[ \int \frac {\log \left (\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )}{d+e x^2} \, dx=\text {Exception raised: AttributeError} \]
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Exception generated. \[ \int \frac {\log \left (\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )}{d+e x^2} \, dx=\text {Exception raised: ValueError} \]
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Exception generated. \[ \int \frac {\log \left (\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )}{d+e x^2} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {\log \left (\frac {2 x \left (\sqrt {d} \sqrt {-e}+e x\right )}{d+e x^2}\right )}{d+e x^2} \, dx=\int \frac {\ln \left (\frac {2\,x\,\left (e\,x+\sqrt {d}\,\sqrt {-e}\right )}{e\,x^2+d}\right )}{e\,x^2+d} \,d x \]
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