Integrand size = 6, antiderivative size = 30 \[ \int (x+\sin (x))^2 \, dx=\frac {x}{2}+\frac {x^3}{3}-2 x \cos (x)+2 \sin (x)-\frac {1}{2} \cos (x) \sin (x) \]
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Time = 0.04 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.833, Rules used = {6874, 3377, 2717, 2715, 8} \[ \int (x+\sin (x))^2 \, dx=\frac {x^3}{3}+\frac {x}{2}+2 \sin (x)-2 x \cos (x)-\frac {1}{2} \sin (x) \cos (x) \]
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Rule 8
Rule 2715
Rule 2717
Rule 3377
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \left (x^2+2 x \sin (x)+\sin ^2(x)\right ) \, dx \\ & = \frac {x^3}{3}+2 \int x \sin (x) \, dx+\int \sin ^2(x) \, dx \\ & = \frac {x^3}{3}-2 x \cos (x)-\frac {1}{2} \cos (x) \sin (x)+\frac {\int 1 \, dx}{2}+2 \int \cos (x) \, dx \\ & = \frac {x}{2}+\frac {x^3}{3}-2 x \cos (x)+2 \sin (x)-\frac {1}{2} \cos (x) \sin (x) \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00 \[ \int (x+\sin (x))^2 \, dx=\frac {1}{6} x \left (3+2 x^2\right )-2 x \cos (x)+2 \sin (x)-\frac {1}{4} \sin (2 x) \]
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Time = 0.46 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.83
method | result | size |
default | \(\frac {x}{2}+\frac {x^{3}}{3}-2 x \cos \left (x \right )+2 \sin \left (x \right )-\frac {\cos \left (x \right ) \sin \left (x \right )}{2}\) | \(25\) |
risch | \(\frac {x^{3}}{3}+\frac {x}{2}-2 x \cos \left (x \right )+2 \sin \left (x \right )-\frac {\sin \left (2 x \right )}{4}\) | \(25\) |
parallelrisch | \(\frac {x^{3}}{3}+\frac {x}{2}-2 x \cos \left (x \right )+2 \sin \left (x \right )-\frac {\sin \left (2 x \right )}{4}\) | \(25\) |
parts | \(\frac {x}{2}+\frac {x^{3}}{3}-2 x \cos \left (x \right )+2 \sin \left (x \right )-\frac {\cos \left (x \right ) \sin \left (x \right )}{2}\) | \(25\) |
norman | \(\frac {x \tan \left (\frac {x}{2}\right )^{2}-\frac {3 x}{2}+\frac {x^{3}}{3}+5 \tan \left (\frac {x}{2}\right )^{3}+\frac {5 x \tan \left (\frac {x}{2}\right )^{4}}{2}+\frac {2 x^{3} \tan \left (\frac {x}{2}\right )^{2}}{3}+\frac {x^{3} \tan \left (\frac {x}{2}\right )^{4}}{3}+3 \tan \left (\frac {x}{2}\right )}{\left (1+\tan \left (\frac {x}{2}\right )^{2}\right )^{2}}\) | \(74\) |
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Time = 0.25 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.73 \[ \int (x+\sin (x))^2 \, dx=\frac {1}{3} \, x^{3} - 2 \, x \cos \left (x\right ) - \frac {1}{2} \, {\left (\cos \left (x\right ) - 4\right )} \sin \left (x\right ) + \frac {1}{2} \, x \]
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Time = 0.07 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.37 \[ \int (x+\sin (x))^2 \, dx=\frac {x^{3}}{3} + \frac {x \sin ^{2}{\left (x \right )}}{2} + \frac {x \cos ^{2}{\left (x \right )}}{2} - 2 x \cos {\left (x \right )} - \frac {\sin {\left (x \right )} \cos {\left (x \right )}}{2} + 2 \sin {\left (x \right )} \]
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Time = 0.21 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80 \[ \int (x+\sin (x))^2 \, dx=\frac {1}{3} \, x^{3} - 2 \, x \cos \left (x\right ) + \frac {1}{2} \, x - \frac {1}{4} \, \sin \left (2 \, x\right ) + 2 \, \sin \left (x\right ) \]
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Time = 0.25 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80 \[ \int (x+\sin (x))^2 \, dx=\frac {1}{3} \, x^{3} - 2 \, x \cos \left (x\right ) + \frac {1}{2} \, x - \frac {1}{4} \, \sin \left (2 \, x\right ) + 2 \, \sin \left (x\right ) \]
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Time = 0.11 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80 \[ \int (x+\sin (x))^2 \, dx=\frac {x}{2}+2\,\sin \left (x\right )-\frac {\cos \left (x\right )\,\sin \left (x\right )}{2}-2\,x\,\cos \left (x\right )+\frac {x^3}{3} \]
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