Integrand size = 17, antiderivative size = 13 \[ \int e^{n \sin (a+b x)} \cot (a+b x) \, dx=\frac {\operatorname {ExpIntegralEi}(n \sin (a+b x))}{b} \]
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Time = 0.02 (sec) , antiderivative size = 13, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {4423, 2209} \[ \int e^{n \sin (a+b x)} \cot (a+b x) \, dx=\frac {\operatorname {ExpIntegralEi}(n \sin (a+b x))}{b} \]
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Rule 2209
Rule 4423
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {e^{n x}}{x} \, dx,x,\sin (a+b x)\right )}{b} \\ & = \frac {\operatorname {ExpIntegralEi}(n \sin (a+b x))}{b} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 13, normalized size of antiderivative = 1.00 \[ \int e^{n \sin (a+b x)} \cot (a+b x) \, dx=\frac {\operatorname {ExpIntegralEi}(n \sin (a+b x))}{b} \]
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\[\int {\mathrm e}^{n \sin \left (x b +a \right )} \cot \left (x b +a \right )d x\]
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Time = 0.25 (sec) , antiderivative size = 13, normalized size of antiderivative = 1.00 \[ \int e^{n \sin (a+b x)} \cot (a+b x) \, dx=\frac {{\rm Ei}\left (n \sin \left (b x + a\right )\right )}{b} \]
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\[ \int e^{n \sin (a+b x)} \cot (a+b x) \, dx=\int e^{n \sin {\left (a + b x \right )}} \cot {\left (a + b x \right )}\, dx \]
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Time = 0.25 (sec) , antiderivative size = 13, normalized size of antiderivative = 1.00 \[ \int e^{n \sin (a+b x)} \cot (a+b x) \, dx=\frac {{\rm Ei}\left (n \sin \left (b x + a\right )\right )}{b} \]
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Time = 0.28 (sec) , antiderivative size = 13, normalized size of antiderivative = 1.00 \[ \int e^{n \sin (a+b x)} \cot (a+b x) \, dx=\frac {{\rm Ei}\left (n \sin \left (b x + a\right )\right )}{b} \]
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Timed out. \[ \int e^{n \sin (a+b x)} \cot (a+b x) \, dx=\int \mathrm {cot}\left (a+b\,x\right )\,{\mathrm {e}}^{n\,\sin \left (a+b\,x\right )} \,d x \]
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