Integrand size = 12, antiderivative size = 37 \[ \int e^{-2 \pi x} \cos (2 \pi x) \, dx=-\frac {e^{-2 \pi x} \cos (2 \pi x)}{4 \pi }+\frac {e^{-2 \pi x} \sin (2 \pi x)}{4 \pi } \]
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Time = 0.02 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {4518} \[ \int e^{-2 \pi x} \cos (2 \pi x) \, dx=\frac {e^{-2 \pi x} \sin (2 \pi x)}{4 \pi }-\frac {e^{-2 \pi x} \cos (2 \pi x)}{4 \pi } \]
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Rule 4518
Rubi steps \begin{align*} \text {integral}& = -\frac {e^{-2 \pi x} \cos (2 \pi x)}{4 \pi }+\frac {e^{-2 \pi x} \sin (2 \pi x)}{4 \pi } \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.70 \[ \int e^{-2 \pi x} \cos (2 \pi x) \, dx=\frac {e^{-2 \pi x} (-\cos (2 \pi x)+\sin (2 \pi x))}{4 \pi } \]
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Time = 0.60 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.65
method | result | size |
parallelrisch | \(\frac {{\mathrm e}^{-2 \pi x} \left (-\cos \left (2 \pi x \right )+\sin \left (2 \pi x \right )\right )}{4 \pi }\) | \(24\) |
derivativedivides | \(\frac {-\frac {{\mathrm e}^{-2 \pi x} \cos \left (2 \pi x \right )}{2}+\frac {{\mathrm e}^{-2 \pi x} \sin \left (2 \pi x \right )}{2}}{2 \pi }\) | \(31\) |
default | \(\frac {-\frac {{\mathrm e}^{-2 \pi x} \cos \left (2 \pi x \right )}{2}+\frac {{\mathrm e}^{-2 \pi x} \sin \left (2 \pi x \right )}{2}}{2 \pi }\) | \(31\) |
norman | \(\frac {\left (-\frac {1}{4 \pi }+\frac {\tan \left (\pi x \right )}{2 \pi }+\frac {\tan \left (\pi x \right )^{2}}{4 \pi }\right ) {\mathrm e}^{-2 \pi x}}{1+\tan \left (\pi x \right )^{2}}\) | \(45\) |
risch | \(-\frac {{\mathrm e}^{\left (-2+2 i\right ) \pi x}}{8 \pi }-\frac {i {\mathrm e}^{\left (-2+2 i\right ) \pi x}}{8 \pi }-\frac {{\mathrm e}^{\left (-2-2 i\right ) \pi x}}{8 \pi }+\frac {i {\mathrm e}^{\left (-2-2 i\right ) \pi x}}{8 \pi }\) | \(52\) |
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none
Time = 0.23 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.78 \[ \int e^{-2 \pi x} \cos (2 \pi x) \, dx=-\frac {\cos \left (2 \, \pi x\right ) e^{\left (-2 \, \pi x\right )} - e^{\left (-2 \, \pi x\right )} \sin \left (2 \, \pi x\right )}{4 \, \pi } \]
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Time = 0.19 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.86 \[ \int e^{-2 \pi x} \cos (2 \pi x) \, dx=\frac {e^{- 2 \pi x} \sin {\left (2 \pi x \right )}}{4 \pi } - \frac {e^{- 2 \pi x} \cos {\left (2 \pi x \right )}}{4 \pi } \]
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none
Time = 0.19 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.70 \[ \int e^{-2 \pi x} \cos (2 \pi x) \, dx=-\frac {{\left (\pi \cos \left (2 \, \pi x\right ) - \pi \sin \left (2 \, \pi x\right )\right )} e^{\left (-2 \, \pi x\right )}}{4 \, \pi ^{2}} \]
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none
Time = 0.28 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.62 \[ \int e^{-2 \pi x} \cos (2 \pi x) \, dx=-\frac {{\left (\cos \left (2 \, \pi x\right ) - \sin \left (2 \, \pi x\right )\right )} e^{\left (-2 \, \pi x\right )}}{4 \, \pi } \]
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Time = 26.39 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.68 \[ \int e^{-2 \pi x} \cos (2 \pi x) \, dx=-\frac {{\mathrm {e}}^{-2\,\Pi \,x}\,\left (2\,\cos \left (2\,\Pi \,x\right )-2\,\sin \left (2\,\Pi \,x\right )\right )}{8\,\Pi } \]
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