Integrand size = 15, antiderivative size = 15 \[ \int \frac {\sin (8 x)}{9+\sin ^4(4 x)} \, dx=\frac {1}{12} \arctan \left (\frac {1}{3} \sin ^2(4 x)\right ) \]
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Time = 0.04 (sec) , antiderivative size = 15, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {12, 281, 209} \[ \int \frac {\sin (8 x)}{9+\sin ^4(4 x)} \, dx=\frac {1}{12} \arctan \left (\frac {1}{3} \sin ^2(4 x)\right ) \]
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Rule 12
Rule 209
Rule 281
Rubi steps \begin{align*} \text {integral}& = \frac {1}{4} \text {Subst}\left (\int \frac {2 x}{9+x^4} \, dx,x,\sin (4 x)\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \frac {x}{9+x^4} \, dx,x,\sin (4 x)\right ) \\ & = \frac {1}{4} \text {Subst}\left (\int \frac {1}{9+x^2} \, dx,x,\sin ^2(4 x)\right ) \\ & = \frac {1}{12} \arctan \left (\frac {1}{3} \sin ^2(4 x)\right ) \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 15, normalized size of antiderivative = 1.00 \[ \int \frac {\sin (8 x)}{9+\sin ^4(4 x)} \, dx=\frac {1}{12} \arctan \left (\frac {1}{3} \sin ^2(4 x)\right ) \]
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Time = 26.90 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.80
method | result | size |
derivativedivides | \(\frac {\arctan \left (\frac {\sin \left (4 x \right )^{2}}{3}\right )}{12}\) | \(12\) |
default | \(\frac {\arctan \left (\frac {\sin \left (4 x \right )^{2}}{3}\right )}{12}\) | \(12\) |
risch | \(\frac {i \ln \left ({\mathrm e}^{16 i x}+\left (-2-12 i\right ) {\mathrm e}^{8 i x}+1\right )}{24}-\frac {i \ln \left ({\mathrm e}^{16 i x}+\left (-2+12 i\right ) {\mathrm e}^{8 i x}+1\right )}{24}\) | \(42\) |
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Time = 0.26 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.87 \[ \int \frac {\sin (8 x)}{9+\sin ^4(4 x)} \, dx=-\frac {1}{12} \, \arctan \left (\frac {1}{3} \, \cos \left (4 \, x\right )^{2} - \frac {1}{3}\right ) \]
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Timed out. \[ \int \frac {\sin (8 x)}{9+\sin ^4(4 x)} \, dx=\text {Timed out} \]
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\[ \int \frac {\sin (8 x)}{9+\sin ^4(4 x)} \, dx=\int { \frac {\sin \left (8 \, x\right )}{\sin \left (4 \, x\right )^{4} + 9} \,d x } \]
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Time = 0.27 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.73 \[ \int \frac {\sin (8 x)}{9+\sin ^4(4 x)} \, dx=\frac {1}{12} \, \arctan \left (\frac {1}{3} \, \sin \left (4 \, x\right )^{2}\right ) \]
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Time = 26.98 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.87 \[ \int \frac {\sin (8 x)}{9+\sin ^4(4 x)} \, dx=\frac {\mathrm {atan}\left (\frac {10\,{\mathrm {tan}\left (4\,x\right )}^2}{3}+3\right )}{12} \]
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