Integrand size = 15, antiderivative size = 55 \[ \int \frac {\cos ^2(x)}{a+b \sin (2 x)} \, dx=\frac {\arctan \left (\frac {b+a \tan (x)}{\sqrt {a^2-b^2}}\right )}{2 \sqrt {a^2-b^2}}+\frac {\log (a+b \sin (2 x))}{4 b} \]
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Time = 0.14 (sec) , antiderivative size = 70, normalized size of antiderivative = 1.27, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.467, Rules used = {995, 648, 632, 210, 642, 12, 266} \[ \int \frac {\cos ^2(x)}{a+b \sin (2 x)} \, dx=\frac {\arctan \left (\frac {a \tan (x)+b}{\sqrt {a^2-b^2}}\right )}{2 \sqrt {a^2-b^2}}+\frac {\log \left (a \tan ^2(x)+a+2 b \tan (x)\right )}{4 b}+\frac {\log (\cos (x))}{2 b} \]
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Rule 12
Rule 210
Rule 266
Rule 632
Rule 642
Rule 648
Rule 995
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {1}{\left (1+x^2\right ) \left (a+2 b x+a x^2\right )} \, dx,x,\tan (x)\right ) \\ & = -\frac {\text {Subst}\left (\int \frac {2 b x}{1+x^2} \, dx,x,\tan (x)\right )}{4 b^2}+\frac {\text {Subst}\left (\int \frac {4 b^2+2 a b x}{a+2 b x+a x^2} \, dx,x,\tan (x)\right )}{4 b^2} \\ & = \frac {1}{2} \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan (x)\right )+\frac {\text {Subst}\left (\int \frac {2 b+2 a x}{a+2 b x+a x^2} \, dx,x,\tan (x)\right )}{4 b}-\frac {\text {Subst}\left (\int \frac {x}{1+x^2} \, dx,x,\tan (x)\right )}{2 b} \\ & = \frac {\log (\cos (x))}{2 b}+\frac {\log \left (a+2 b \tan (x)+a \tan ^2(x)\right )}{4 b}-\text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan (x)\right ) \\ & = \frac {\arctan \left (\frac {2 b+2 a \tan (x)}{2 \sqrt {a^2-b^2}}\right )}{2 \sqrt {a^2-b^2}}+\frac {\log (\cos (x))}{2 b}+\frac {\log \left (a+2 b \tan (x)+a \tan ^2(x)\right )}{4 b} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 54, normalized size of antiderivative = 0.98 \[ \int \frac {\cos ^2(x)}{a+b \sin (2 x)} \, dx=\frac {1}{4} \left (\frac {2 \arctan \left (\frac {b+a \tan (x)}{\sqrt {a^2-b^2}}\right )}{\sqrt {a^2-b^2}}+\frac {\log (a+b \sin (2 x))}{b}\right ) \]
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Time = 2.25 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.31
method | result | size |
default | \(-\frac {\ln \left (1+\tan \left (x \right )^{2}\right )}{4 b}+\frac {\frac {\ln \left (a \tan \left (x \right )^{2}+2 b \tan \left (x \right )+a \right )}{2}+\frac {b \arctan \left (\frac {2 a \tan \left (x \right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}}}{2 b}\) | \(72\) |
risch | \(\frac {i x}{2 b}-\frac {i x \,a^{2} b}{a^{2} b^{2}-b^{4}}+\frac {i x \,b^{3}}{a^{2} b^{2}-b^{4}}+\frac {\ln \left ({\mathrm e}^{2 i x}+\frac {i a b +\sqrt {-a^{2} b^{2}+b^{4}}}{b^{2}}\right ) a^{2}}{4 \left (a^{2}-b^{2}\right ) b}-\frac {b \ln \left ({\mathrm e}^{2 i x}+\frac {i a b +\sqrt {-a^{2} b^{2}+b^{4}}}{b^{2}}\right )}{4 \left (a^{2}-b^{2}\right )}+\frac {\ln \left ({\mathrm e}^{2 i x}+\frac {i a b +\sqrt {-a^{2} b^{2}+b^{4}}}{b^{2}}\right ) \sqrt {-a^{2} b^{2}+b^{4}}}{4 \left (a^{2}-b^{2}\right ) b}+\frac {\ln \left ({\mathrm e}^{2 i x}-\frac {-i a b +\sqrt {-a^{2} b^{2}+b^{4}}}{b^{2}}\right ) a^{2}}{4 \left (a^{2}-b^{2}\right ) b}-\frac {b \ln \left ({\mathrm e}^{2 i x}-\frac {-i a b +\sqrt {-a^{2} b^{2}+b^{4}}}{b^{2}}\right )}{4 \left (a^{2}-b^{2}\right )}-\frac {\ln \left ({\mathrm e}^{2 i x}-\frac {-i a b +\sqrt {-a^{2} b^{2}+b^{4}}}{b^{2}}\right ) \sqrt {-a^{2} b^{2}+b^{4}}}{4 \left (a^{2}-b^{2}\right ) b}\) | \(369\) |
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Leaf count of result is larger than twice the leaf count of optimal. 121 vs. \(2 (47) = 94\).
Time = 0.30 (sec) , antiderivative size = 322, normalized size of antiderivative = 5.85 \[ \int \frac {\cos ^2(x)}{a+b \sin (2 x)} \, dx=\left [-\frac {\sqrt {-a^{2} + b^{2}} b \log \left (-\frac {4 \, {\left (2 \, a^{2} - b^{2}\right )} \cos \left (x\right )^{4} - 4 \, a b \cos \left (x\right ) \sin \left (x\right ) - 4 \, {\left (2 \, a^{2} - b^{2}\right )} \cos \left (x\right )^{2} + a^{2} - 2 \, b^{2} + 2 \, {\left (2 \, b \cos \left (x\right )^{2} + 2 \, {\left (2 \, a \cos \left (x\right )^{3} - a \cos \left (x\right )\right )} \sin \left (x\right ) - b\right )} \sqrt {-a^{2} + b^{2}}}{4 \, b^{2} \cos \left (x\right )^{4} - 4 \, b^{2} \cos \left (x\right )^{2} - 4 \, a b \cos \left (x\right ) \sin \left (x\right ) - a^{2}}\right ) - {\left (a^{2} - b^{2}\right )} \log \left (-4 \, b^{2} \cos \left (x\right )^{4} + 4 \, b^{2} \cos \left (x\right )^{2} + 4 \, a b \cos \left (x\right ) \sin \left (x\right ) + a^{2}\right )}{8 \, {\left (a^{2} b - b^{3}\right )}}, -\frac {2 \, \sqrt {a^{2} - b^{2}} b \arctan \left (-\frac {{\left (2 \, a \cos \left (x\right ) \sin \left (x\right ) + b\right )} \sqrt {a^{2} - b^{2}}}{2 \, {\left (a^{2} - b^{2}\right )} \cos \left (x\right )^{2} - a^{2} + b^{2}}\right ) - {\left (a^{2} - b^{2}\right )} \log \left (-4 \, b^{2} \cos \left (x\right )^{4} + 4 \, b^{2} \cos \left (x\right )^{2} + 4 \, a b \cos \left (x\right ) \sin \left (x\right ) + a^{2}\right )}{8 \, {\left (a^{2} b - b^{3}\right )}}\right ] \]
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Time = 2.98 (sec) , antiderivative size = 124, normalized size of antiderivative = 2.25 \[ \int \frac {\cos ^2(x)}{a+b \sin (2 x)} \, dx=\begin {cases} \frac {\log {\left (\frac {a}{b} + \sin {\left (2 x \right )} \right )}}{4 b} & \text {for}\: b \neq 0 \\\frac {\sin {\left (2 x \right )}}{4 a} & \text {otherwise} \end {cases} + \begin {cases} \tilde {\infty } \log {\left (\tan {\left (x \right )} \right )} & \text {for}\: a = 0 \wedge b = 0 \\\frac {\log {\left (\tan {\left (x \right )} \right )}}{4 b} & \text {for}\: a = 0 \\\frac {1}{2 b \tan {\left (x \right )} - 2 b} & \text {for}\: a = - b \\- \frac {1}{2 b \tan {\left (x \right )} + 2 b} & \text {for}\: a = b \\\frac {\log {\left (\tan {\left (x \right )} + \frac {b}{a} - \frac {\sqrt {- a^{2} + b^{2}}}{a} \right )}}{4 \sqrt {- a^{2} + b^{2}}} - \frac {\log {\left (\tan {\left (x \right )} + \frac {b}{a} + \frac {\sqrt {- a^{2} + b^{2}}}{a} \right )}}{4 \sqrt {- a^{2} + b^{2}}} & \text {otherwise} \end {cases} \]
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Exception generated. \[ \int \frac {\cos ^2(x)}{a+b \sin (2 x)} \, dx=\text {Exception raised: ValueError} \]
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none
Time = 0.28 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.40 \[ \int \frac {\cos ^2(x)}{a+b \sin (2 x)} \, dx=\frac {\pi \left \lfloor \frac {x}{\pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (x\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )}{2 \, \sqrt {a^{2} - b^{2}}} + \frac {\log \left (a \tan \left (x\right )^{2} + 2 \, b \tan \left (x\right ) + a\right )}{4 \, b} - \frac {\log \left (\tan \left (x\right )^{2} + 1\right )}{4 \, b} \]
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Time = 26.73 (sec) , antiderivative size = 1374, normalized size of antiderivative = 24.98 \[ \int \frac {\cos ^2(x)}{a+b \sin (2 x)} \, dx=\text {Too large to display} \]
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