Integrand size = 12, antiderivative size = 147 \[ \int (a+b \arcsin (c+d x))^n \, dx=-\frac {i e^{-\frac {i a}{b}} (a+b \arcsin (c+d x))^n \left (-\frac {i (a+b \arcsin (c+d x))}{b}\right )^{-n} \Gamma \left (1+n,-\frac {i (a+b \arcsin (c+d x))}{b}\right )}{2 d}+\frac {i e^{\frac {i a}{b}} (a+b \arcsin (c+d x))^n \left (\frac {i (a+b \arcsin (c+d x))}{b}\right )^{-n} \Gamma \left (1+n,\frac {i (a+b \arcsin (c+d x))}{b}\right )}{2 d} \]
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Time = 0.09 (sec) , antiderivative size = 147, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {4887, 4719, 3388, 2212} \[ \int (a+b \arcsin (c+d x))^n \, dx=\frac {i e^{\frac {i a}{b}} (a+b \arcsin (c+d x))^n \left (\frac {i (a+b \arcsin (c+d x))}{b}\right )^{-n} \Gamma \left (n+1,\frac {i (a+b \arcsin (c+d x))}{b}\right )}{2 d}-\frac {i e^{-\frac {i a}{b}} (a+b \arcsin (c+d x))^n \left (-\frac {i (a+b \arcsin (c+d x))}{b}\right )^{-n} \Gamma \left (n+1,-\frac {i (a+b \arcsin (c+d x))}{b}\right )}{2 d} \]
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Rule 2212
Rule 3388
Rule 4719
Rule 4887
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int (a+b \arcsin (x))^n \, dx,x,c+d x\right )}{d} \\ & = \frac {\text {Subst}\left (\int x^n \cos \left (\frac {a}{b}-\frac {x}{b}\right ) \, dx,x,a+b \arcsin (c+d x)\right )}{b d} \\ & = \frac {\text {Subst}\left (\int e^{-i \left (\frac {a}{b}-\frac {x}{b}\right )} x^n \, dx,x,a+b \arcsin (c+d x)\right )}{2 b d}+\frac {\text {Subst}\left (\int e^{i \left (\frac {a}{b}-\frac {x}{b}\right )} x^n \, dx,x,a+b \arcsin (c+d x)\right )}{2 b d} \\ & = -\frac {i e^{-\frac {i a}{b}} (a+b \arcsin (c+d x))^n \left (-\frac {i (a+b \arcsin (c+d x))}{b}\right )^{-n} \Gamma \left (1+n,-\frac {i (a+b \arcsin (c+d x))}{b}\right )}{2 d}+\frac {i e^{\frac {i a}{b}} (a+b \arcsin (c+d x))^n \left (\frac {i (a+b \arcsin (c+d x))}{b}\right )^{-n} \Gamma \left (1+n,\frac {i (a+b \arcsin (c+d x))}{b}\right )}{2 d} \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 129, normalized size of antiderivative = 0.88 \[ \int (a+b \arcsin (c+d x))^n \, dx=-\frac {i e^{-\frac {i a}{b}} (a+b \arcsin (c+d x))^n \left (\left (-\frac {i (a+b \arcsin (c+d x))}{b}\right )^{-n} \Gamma \left (1+n,-\frac {i (a+b \arcsin (c+d x))}{b}\right )-e^{\frac {2 i a}{b}} \left (\frac {i (a+b \arcsin (c+d x))}{b}\right )^{-n} \Gamma \left (1+n,\frac {i (a+b \arcsin (c+d x))}{b}\right )\right )}{2 d} \]
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\[\int \left (a +b \arcsin \left (d x +c \right )\right )^{n}d x\]
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\[ \int (a+b \arcsin (c+d x))^n \, dx=\int { {\left (b \arcsin \left (d x + c\right ) + a\right )}^{n} \,d x } \]
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\[ \int (a+b \arcsin (c+d x))^n \, dx=\int \left (a + b \operatorname {asin}{\left (c + d x \right )}\right )^{n}\, dx \]
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\[ \int (a+b \arcsin (c+d x))^n \, dx=\int { {\left (b \arcsin \left (d x + c\right ) + a\right )}^{n} \,d x } \]
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\[ \int (a+b \arcsin (c+d x))^n \, dx=\int { {\left (b \arcsin \left (d x + c\right ) + a\right )}^{n} \,d x } \]
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Timed out. \[ \int (a+b \arcsin (c+d x))^n \, dx=\int {\left (a+b\,\mathrm {asin}\left (c+d\,x\right )\right )}^n \,d x \]
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