Integrand size = 12, antiderivative size = 93 \[ \int \frac {1}{(a+b \arcsin (c+d x))^2} \, dx=-\frac {\sqrt {1-(c+d x)^2}}{b d (a+b \arcsin (c+d x))}+\frac {\operatorname {CosIntegral}\left (\frac {a+b \arcsin (c+d x)}{b}\right ) \sin \left (\frac {a}{b}\right )}{b^2 d}-\frac {\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \arcsin (c+d x)}{b}\right )}{b^2 d} \]
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Time = 0.11 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {4887, 4717, 4809, 3384, 3380, 3383} \[ \int \frac {1}{(a+b \arcsin (c+d x))^2} \, dx=\frac {\sin \left (\frac {a}{b}\right ) \operatorname {CosIntegral}\left (\frac {a+b \arcsin (c+d x)}{b}\right )}{b^2 d}-\frac {\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \arcsin (c+d x)}{b}\right )}{b^2 d}-\frac {\sqrt {1-(c+d x)^2}}{b d (a+b \arcsin (c+d x))} \]
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Rule 3380
Rule 3383
Rule 3384
Rule 4717
Rule 4809
Rule 4887
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1}{(a+b \arcsin (x))^2} \, dx,x,c+d x\right )}{d} \\ & = -\frac {\sqrt {1-(c+d x)^2}}{b d (a+b \arcsin (c+d x))}-\frac {\text {Subst}\left (\int \frac {x}{\sqrt {1-x^2} (a+b \arcsin (x))} \, dx,x,c+d x\right )}{b d} \\ & = -\frac {\sqrt {1-(c+d x)^2}}{b d (a+b \arcsin (c+d x))}+\frac {\text {Subst}\left (\int \frac {\sin \left (\frac {a}{b}-\frac {x}{b}\right )}{x} \, dx,x,a+b \arcsin (c+d x)\right )}{b^2 d} \\ & = -\frac {\sqrt {1-(c+d x)^2}}{b d (a+b \arcsin (c+d x))}-\frac {\cos \left (\frac {a}{b}\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \arcsin (c+d x)\right )}{b^2 d}+\frac {\sin \left (\frac {a}{b}\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \arcsin (c+d x)\right )}{b^2 d} \\ & = -\frac {\sqrt {1-(c+d x)^2}}{b d (a+b \arcsin (c+d x))}+\frac {\operatorname {CosIntegral}\left (\frac {a+b \arcsin (c+d x)}{b}\right ) \sin \left (\frac {a}{b}\right )}{b^2 d}-\frac {\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \arcsin (c+d x)}{b}\right )}{b^2 d} \\ \end{align*}
Time = 0.30 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.85 \[ \int \frac {1}{(a+b \arcsin (c+d x))^2} \, dx=\frac {-\frac {b \sqrt {1-(c+d x)^2}}{a+b \arcsin (c+d x)}+\operatorname {CosIntegral}\left (\frac {a}{b}+\arcsin (c+d x)\right ) \sin \left (\frac {a}{b}\right )-\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a}{b}+\arcsin (c+d x)\right )}{b^2 d} \]
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Time = 0.41 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.88
method | result | size |
derivativedivides | \(\frac {-\frac {\sqrt {1-\left (d x +c \right )^{2}}}{\left (a +b \arcsin \left (d x +c \right )\right ) b}+\frac {\operatorname {Ci}\left (\arcsin \left (d x +c \right )+\frac {a}{b}\right ) \sin \left (\frac {a}{b}\right )-\operatorname {Si}\left (\arcsin \left (d x +c \right )+\frac {a}{b}\right ) \cos \left (\frac {a}{b}\right )}{b^{2}}}{d}\) | \(82\) |
default | \(\frac {-\frac {\sqrt {1-\left (d x +c \right )^{2}}}{\left (a +b \arcsin \left (d x +c \right )\right ) b}+\frac {\operatorname {Ci}\left (\arcsin \left (d x +c \right )+\frac {a}{b}\right ) \sin \left (\frac {a}{b}\right )-\operatorname {Si}\left (\arcsin \left (d x +c \right )+\frac {a}{b}\right ) \cos \left (\frac {a}{b}\right )}{b^{2}}}{d}\) | \(82\) |
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\[ \int \frac {1}{(a+b \arcsin (c+d x))^2} \, dx=\int { \frac {1}{{\left (b \arcsin \left (d x + c\right ) + a\right )}^{2}} \,d x } \]
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\[ \int \frac {1}{(a+b \arcsin (c+d x))^2} \, dx=\int \frac {1}{\left (a + b \operatorname {asin}{\left (c + d x \right )}\right )^{2}}\, dx \]
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\[ \int \frac {1}{(a+b \arcsin (c+d x))^2} \, dx=\int { \frac {1}{{\left (b \arcsin \left (d x + c\right ) + a\right )}^{2}} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 215 vs. \(2 (91) = 182\).
Time = 0.31 (sec) , antiderivative size = 215, normalized size of antiderivative = 2.31 \[ \int \frac {1}{(a+b \arcsin (c+d x))^2} \, dx=\frac {b \arcsin \left (d x + c\right ) \operatorname {Ci}\left (\frac {a}{b} + \arcsin \left (d x + c\right )\right ) \sin \left (\frac {a}{b}\right )}{b^{3} d \arcsin \left (d x + c\right ) + a b^{2} d} - \frac {b \arcsin \left (d x + c\right ) \cos \left (\frac {a}{b}\right ) \operatorname {Si}\left (\frac {a}{b} + \arcsin \left (d x + c\right )\right )}{b^{3} d \arcsin \left (d x + c\right ) + a b^{2} d} + \frac {a \operatorname {Ci}\left (\frac {a}{b} + \arcsin \left (d x + c\right )\right ) \sin \left (\frac {a}{b}\right )}{b^{3} d \arcsin \left (d x + c\right ) + a b^{2} d} - \frac {a \cos \left (\frac {a}{b}\right ) \operatorname {Si}\left (\frac {a}{b} + \arcsin \left (d x + c\right )\right )}{b^{3} d \arcsin \left (d x + c\right ) + a b^{2} d} - \frac {\sqrt {-{\left (d x + c\right )}^{2} + 1} b}{b^{3} d \arcsin \left (d x + c\right ) + a b^{2} d} \]
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Timed out. \[ \int \frac {1}{(a+b \arcsin (c+d x))^2} \, dx=\int \frac {1}{{\left (a+b\,\mathrm {asin}\left (c+d\,x\right )\right )}^2} \,d x \]
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