Integrand size = 16, antiderivative size = 214 \[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x} \, dx=-\frac {1}{4} i b \arcsin \left (c+d x^2\right )^2+\frac {1}{2} b \arcsin \left (c+d x^2\right ) \log \left (1-\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c-\sqrt {1-c^2}}\right )+\frac {1}{2} b \arcsin \left (c+d x^2\right ) \log \left (1-\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c+\sqrt {1-c^2}}\right )+a \log (x)-\frac {1}{2} i b \operatorname {PolyLog}\left (2,\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c-\sqrt {1-c^2}}\right )-\frac {1}{2} i b \operatorname {PolyLog}\left (2,\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c+\sqrt {1-c^2}}\right ) \]
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Time = 0.28 (sec) , antiderivative size = 214, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.438, Rules used = {6874, 4889, 4825, 4617, 2221, 2317, 2438} \[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x} \, dx=a \log (x)-\frac {1}{2} i b \operatorname {PolyLog}\left (2,\frac {e^{i \arcsin \left (d x^2+c\right )}}{i c-\sqrt {1-c^2}}\right )-\frac {1}{2} i b \operatorname {PolyLog}\left (2,\frac {e^{i \arcsin \left (d x^2+c\right )}}{i c+\sqrt {1-c^2}}\right )+\frac {1}{2} b \arcsin \left (c+d x^2\right ) \log \left (1-\frac {e^{i \arcsin \left (c+d x^2\right )}}{-\sqrt {1-c^2}+i c}\right )+\frac {1}{2} b \arcsin \left (c+d x^2\right ) \log \left (1-\frac {e^{i \arcsin \left (c+d x^2\right )}}{\sqrt {1-c^2}+i c}\right )-\frac {1}{4} i b \arcsin \left (c+d x^2\right )^2 \]
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Rule 2221
Rule 2317
Rule 2438
Rule 4617
Rule 4825
Rule 4889
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a}{x}+\frac {b \arcsin \left (c+d x^2\right )}{x}\right ) \, dx \\ & = a \log (x)+b \int \frac {\arcsin \left (c+d x^2\right )}{x} \, dx \\ & = a \log (x)+\frac {1}{2} b \text {Subst}\left (\int \frac {\arcsin (c+d x)}{x} \, dx,x,x^2\right ) \\ & = a \log (x)+\frac {b \text {Subst}\left (\int \frac {\arcsin (x)}{-\frac {c}{d}+\frac {x}{d}} \, dx,x,c+d x^2\right )}{2 d} \\ & = a \log (x)+\frac {b \text {Subst}\left (\int \frac {x \cos (x)}{-\frac {c}{d}+\frac {\sin (x)}{d}} \, dx,x,\arcsin \left (c+d x^2\right )\right )}{2 d} \\ & = -\frac {1}{4} i b \arcsin \left (c+d x^2\right )^2+a \log (x)+\frac {(i b) \text {Subst}\left (\int \frac {e^{i x} x}{-\frac {i c}{d}-\frac {\sqrt {1-c^2}}{d}+\frac {e^{i x}}{d}} \, dx,x,\arcsin \left (c+d x^2\right )\right )}{2 d}+\frac {(i b) \text {Subst}\left (\int \frac {e^{i x} x}{-\frac {i c}{d}+\frac {\sqrt {1-c^2}}{d}+\frac {e^{i x}}{d}} \, dx,x,\arcsin \left (c+d x^2\right )\right )}{2 d} \\ & = -\frac {1}{4} i b \arcsin \left (c+d x^2\right )^2+\frac {1}{2} b \arcsin \left (c+d x^2\right ) \log \left (1-\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c-\sqrt {1-c^2}}\right )+\frac {1}{2} b \arcsin \left (c+d x^2\right ) \log \left (1-\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c+\sqrt {1-c^2}}\right )+a \log (x)-\frac {1}{2} b \text {Subst}\left (\int \log \left (1+\frac {e^{i x}}{\left (-\frac {i c}{d}-\frac {\sqrt {1-c^2}}{d}\right ) d}\right ) \, dx,x,\arcsin \left (c+d x^2\right )\right )-\frac {1}{2} b \text {Subst}\left (\int \log \left (1+\frac {e^{i x}}{\left (-\frac {i c}{d}+\frac {\sqrt {1-c^2}}{d}\right ) d}\right ) \, dx,x,\arcsin \left (c+d x^2\right )\right ) \\ & = -\frac {1}{4} i b \arcsin \left (c+d x^2\right )^2+\frac {1}{2} b \arcsin \left (c+d x^2\right ) \log \left (1-\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c-\sqrt {1-c^2}}\right )+\frac {1}{2} b \arcsin \left (c+d x^2\right ) \log \left (1-\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c+\sqrt {1-c^2}}\right )+a \log (x)+\frac {1}{2} (i b) \text {Subst}\left (\int \frac {\log \left (1+\frac {x}{\left (-\frac {i c}{d}-\frac {\sqrt {1-c^2}}{d}\right ) d}\right )}{x} \, dx,x,e^{i \arcsin \left (c+d x^2\right )}\right )+\frac {1}{2} (i b) \text {Subst}\left (\int \frac {\log \left (1+\frac {x}{\left (-\frac {i c}{d}+\frac {\sqrt {1-c^2}}{d}\right ) d}\right )}{x} \, dx,x,e^{i \arcsin \left (c+d x^2\right )}\right ) \\ & = -\frac {1}{4} i b \arcsin \left (c+d x^2\right )^2+\frac {1}{2} b \arcsin \left (c+d x^2\right ) \log \left (1-\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c-\sqrt {1-c^2}}\right )+\frac {1}{2} b \arcsin \left (c+d x^2\right ) \log \left (1-\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c+\sqrt {1-c^2}}\right )+a \log (x)-\frac {1}{2} i b \operatorname {PolyLog}\left (2,\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c-\sqrt {1-c^2}}\right )-\frac {1}{2} i b \operatorname {PolyLog}\left (2,\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c+\sqrt {1-c^2}}\right ) \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 221, normalized size of antiderivative = 1.03 \[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x} \, dx=a \log (x)+\frac {1}{2} b \left (-\frac {1}{2} i \arcsin \left (c+d x^2\right )^2+\arcsin \left (c+d x^2\right ) \log \left (1+\frac {e^{i \arcsin \left (c+d x^2\right )}}{\left (-\frac {i c}{d}-\frac {\sqrt {1-c^2}}{d}\right ) d}\right )+\arcsin \left (c+d x^2\right ) \log \left (1+\frac {e^{i \arcsin \left (c+d x^2\right )}}{\left (-\frac {i c}{d}+\frac {\sqrt {1-c^2}}{d}\right ) d}\right )-i \operatorname {PolyLog}\left (2,-\frac {e^{i \arcsin \left (c+d x^2\right )}}{-i c+\sqrt {1-c^2}}\right )-i \operatorname {PolyLog}\left (2,\frac {e^{i \arcsin \left (c+d x^2\right )}}{i c+\sqrt {1-c^2}}\right )\right ) \]
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\[\int \frac {a +b \arcsin \left (d \,x^{2}+c \right )}{x}d x\]
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\[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x} \, dx=\int { \frac {b \arcsin \left (d x^{2} + c\right ) + a}{x} \,d x } \]
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\[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x} \, dx=\int \frac {a + b \operatorname {asin}{\left (c + d x^{2} \right )}}{x}\, dx \]
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\[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x} \, dx=\int { \frac {b \arcsin \left (d x^{2} + c\right ) + a}{x} \,d x } \]
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\[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x} \, dx=\int { \frac {b \arcsin \left (d x^{2} + c\right ) + a}{x} \,d x } \]
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Timed out. \[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x} \, dx=\int \frac {a+b\,\mathrm {asin}\left (d\,x^2+c\right )}{x} \,d x \]
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