Integrand size = 16, antiderivative size = 126 \[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x^2} \, dx=-\frac {a+b \arcsin \left (c+d x^2\right )}{x}+\frac {2 b \sqrt {1-c} \sqrt {d} \sqrt {1-\frac {d x^2}{1-c}} \sqrt {1+\frac {d x^2}{1+c}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {d} x}{\sqrt {1-c}}\right ),-\frac {1-c}{1+c}\right )}{\sqrt {1-c^2-2 c d x^2-d^2 x^4}} \]
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Time = 0.06 (sec) , antiderivative size = 126, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {4926, 12, 1118, 430} \[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x^2} \, dx=\frac {2 b \sqrt {1-c} \sqrt {d} \sqrt {1-\frac {d x^2}{1-c}} \sqrt {\frac {d x^2}{c+1}+1} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {d} x}{\sqrt {1-c}}\right ),-\frac {1-c}{c+1}\right )}{\sqrt {-c^2-2 c d x^2-d^2 x^4+1}}-\frac {a+b \arcsin \left (c+d x^2\right )}{x} \]
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Rule 12
Rule 430
Rule 1118
Rule 4926
Rubi steps \begin{align*} \text {integral}& = -\frac {a+b \arcsin \left (c+d x^2\right )}{x}+b \int \frac {2 d}{\sqrt {1-c^2-2 c d x^2-d^2 x^4}} \, dx \\ & = -\frac {a+b \arcsin \left (c+d x^2\right )}{x}+(2 b d) \int \frac {1}{\sqrt {1-c^2-2 c d x^2-d^2 x^4}} \, dx \\ & = -\frac {a+b \arcsin \left (c+d x^2\right )}{x}+\frac {\left (2 b d \sqrt {1-\frac {2 d^2 x^2}{-2 d-2 c d}} \sqrt {1-\frac {2 d^2 x^2}{2 d-2 c d}}\right ) \int \frac {1}{\sqrt {1-\frac {2 d^2 x^2}{-2 d-2 c d}} \sqrt {1-\frac {2 d^2 x^2}{2 d-2 c d}}} \, dx}{\sqrt {1-c^2-2 c d x^2-d^2 x^4}} \\ & = -\frac {a+b \arcsin \left (c+d x^2\right )}{x}+\frac {2 b \sqrt {1-c} \sqrt {d} \sqrt {1-\frac {d x^2}{1-c}} \sqrt {1+\frac {d x^2}{1+c}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {d} x}{\sqrt {1-c}}\right ),-\frac {1-c}{1+c}\right )}{\sqrt {1-c^2-2 c d x^2-d^2 x^4}} \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.18 (sec) , antiderivative size = 140, normalized size of antiderivative = 1.11 \[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x^2} \, dx=-\frac {a}{x}-\frac {b \arcsin \left (c+d x^2\right )}{x}-\frac {2 i b d \sqrt {1-\frac {d x^2}{-1-c}} \sqrt {1-\frac {d x^2}{1-c}} \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {-\frac {d}{-1-c}} x\right ),\frac {-1-c}{1-c}\right )}{\sqrt {-\frac {d}{-1-c}} \sqrt {1-c^2-2 c d x^2-d^2 x^4}} \]
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Time = 0.34 (sec) , antiderivative size = 114, normalized size of antiderivative = 0.90
method | result | size |
default | \(-\frac {a}{x}+b \left (-\frac {\arcsin \left (d \,x^{2}+c \right )}{x}+\frac {2 d \sqrt {1+\frac {d \,x^{2}}{-1+c}}\, \sqrt {1+\frac {d \,x^{2}}{1+c}}\, \operatorname {EllipticF}\left (x \sqrt {-\frac {d}{-1+c}}, \sqrt {-1+\frac {2 c}{1+c}}\right )}{\sqrt {-\frac {d}{-1+c}}\, \sqrt {-d^{2} x^{4}-2 c d \,x^{2}-c^{2}+1}}\right )\) | \(114\) |
parts | \(-\frac {a}{x}+b \left (-\frac {\arcsin \left (d \,x^{2}+c \right )}{x}+\frac {2 d \sqrt {1+\frac {d \,x^{2}}{-1+c}}\, \sqrt {1+\frac {d \,x^{2}}{1+c}}\, \operatorname {EllipticF}\left (x \sqrt {-\frac {d}{-1+c}}, \sqrt {-1+\frac {2 c}{1+c}}\right )}{\sqrt {-\frac {d}{-1+c}}\, \sqrt {-d^{2} x^{4}-2 c d \,x^{2}-c^{2}+1}}\right )\) | \(114\) |
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Time = 0.14 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.13 \[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x^2} \, dx=-\frac {b \arcsin \left (d x^{2} + c\right ) + a}{x} \]
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\[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x^2} \, dx=\int \frac {a + b \operatorname {asin}{\left (c + d x^{2} \right )}}{x^{2}}\, dx \]
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Exception generated. \[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x^2} \, dx=\text {Exception raised: ValueError} \]
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\[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x^2} \, dx=\int { \frac {b \arcsin \left (d x^{2} + c\right ) + a}{x^{2}} \,d x } \]
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Timed out. \[ \int \frac {a+b \arcsin \left (c+d x^2\right )}{x^2} \, dx=\int \frac {a+b\,\mathrm {asin}\left (d\,x^2+c\right )}{x^2} \,d x \]
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