Integrand size = 16, antiderivative size = 337 \[ \int e^{-\frac {1}{2} i \arctan (a x)} x^3 \, dx=-\frac {11 \sqrt [4]{1-i a x} (1+i a x)^{3/4}}{64 a^4}+\frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2}-\frac {(1-i a x)^{5/4} (1+i a x)^{3/4} (25-4 i a x)}{96 a^4}-\frac {11 \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{64 \sqrt {2} a^4}+\frac {11 \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{64 \sqrt {2} a^4}-\frac {11 \log \left (1+\frac {\sqrt {1-i a x}}{\sqrt {1+i a x}}-\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{128 \sqrt {2} a^4}+\frac {11 \log \left (1+\frac {\sqrt {1-i a x}}{\sqrt {1+i a x}}+\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{128 \sqrt {2} a^4} \]
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Time = 0.16 (sec) , antiderivative size = 337, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.750, Rules used = {5170, 102, 152, 52, 65, 246, 217, 1179, 642, 1176, 631, 210} \[ \int e^{-\frac {1}{2} i \arctan (a x)} x^3 \, dx=-\frac {11 \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{64 \sqrt {2} a^4}+\frac {11 \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{64 \sqrt {2} a^4}-\frac {(1-i a x)^{5/4} (1+i a x)^{3/4} (25-4 i a x)}{96 a^4}-\frac {11 \sqrt [4]{1-i a x} (1+i a x)^{3/4}}{64 a^4}-\frac {11 \log \left (\frac {\sqrt {1-i a x}}{\sqrt {1+i a x}}-\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}+1\right )}{128 \sqrt {2} a^4}+\frac {11 \log \left (\frac {\sqrt {1-i a x}}{\sqrt {1+i a x}}+\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}+1\right )}{128 \sqrt {2} a^4}+\frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2} \]
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Rule 52
Rule 65
Rule 102
Rule 152
Rule 210
Rule 217
Rule 246
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 5170
Rubi steps \begin{align*} \text {integral}& = \int \frac {x^3 \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}} \, dx \\ & = \frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2}+\frac {\int \frac {x \left (-2+\frac {i a x}{2}\right ) \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}} \, dx}{4 a^2} \\ & = \frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2}-\frac {(1-i a x)^{5/4} (1+i a x)^{3/4} (25-4 i a x)}{96 a^4}-\frac {(11 i) \int \frac {\sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}} \, dx}{64 a^3} \\ & = -\frac {11 \sqrt [4]{1-i a x} (1+i a x)^{3/4}}{64 a^4}+\frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2}-\frac {(1-i a x)^{5/4} (1+i a x)^{3/4} (25-4 i a x)}{96 a^4}-\frac {(11 i) \int \frac {1}{(1-i a x)^{3/4} \sqrt [4]{1+i a x}} \, dx}{128 a^3} \\ & = -\frac {11 \sqrt [4]{1-i a x} (1+i a x)^{3/4}}{64 a^4}+\frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2}-\frac {(1-i a x)^{5/4} (1+i a x)^{3/4} (25-4 i a x)}{96 a^4}+\frac {11 \text {Subst}\left (\int \frac {1}{\sqrt [4]{2-x^4}} \, dx,x,\sqrt [4]{1-i a x}\right )}{32 a^4} \\ & = -\frac {11 \sqrt [4]{1-i a x} (1+i a x)^{3/4}}{64 a^4}+\frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2}-\frac {(1-i a x)^{5/4} (1+i a x)^{3/4} (25-4 i a x)}{96 a^4}+\frac {11 \text {Subst}\left (\int \frac {1}{1+x^4} \, dx,x,\frac {\sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{32 a^4} \\ & = -\frac {11 \sqrt [4]{1-i a x} (1+i a x)^{3/4}}{64 a^4}+\frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2}-\frac {(1-i a x)^{5/4} (1+i a x)^{3/4} (25-4 i a x)}{96 a^4}+\frac {11 \text {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,\frac {\sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{64 a^4}+\frac {11 \text {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,\frac {\sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{64 a^4} \\ & = -\frac {11 \sqrt [4]{1-i a x} (1+i a x)^{3/4}}{64 a^4}+\frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2}-\frac {(1-i a x)^{5/4} (1+i a x)^{3/4} (25-4 i a x)}{96 a^4}+\frac {11 \text {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\frac {\sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{128 a^4}+\frac {11 \text {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\frac {\sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{128 a^4}-\frac {11 \text {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\frac {\sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{128 \sqrt {2} a^4}-\frac {11 \text {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\frac {\sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{128 \sqrt {2} a^4} \\ & = -\frac {11 \sqrt [4]{1-i a x} (1+i a x)^{3/4}}{64 a^4}+\frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2}-\frac {(1-i a x)^{5/4} (1+i a x)^{3/4} (25-4 i a x)}{96 a^4}-\frac {11 \log \left (1+\frac {\sqrt {1-i a x}}{\sqrt {1+i a x}}-\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{128 \sqrt {2} a^4}+\frac {11 \log \left (1+\frac {\sqrt {1-i a x}}{\sqrt {1+i a x}}+\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{128 \sqrt {2} a^4}+\frac {11 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{64 \sqrt {2} a^4}-\frac {11 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{64 \sqrt {2} a^4} \\ & = -\frac {11 \sqrt [4]{1-i a x} (1+i a x)^{3/4}}{64 a^4}+\frac {x^2 (1-i a x)^{5/4} (1+i a x)^{3/4}}{4 a^2}-\frac {(1-i a x)^{5/4} (1+i a x)^{3/4} (25-4 i a x)}{96 a^4}-\frac {11 \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{64 \sqrt {2} a^4}+\frac {11 \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{64 \sqrt {2} a^4}-\frac {11 \log \left (1+\frac {\sqrt {1-i a x}}{\sqrt {1+i a x}}-\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{128 \sqrt {2} a^4}+\frac {11 \log \left (1+\frac {\sqrt {1-i a x}}{\sqrt {1+i a x}}+\frac {\sqrt {2} \sqrt [4]{1-i a x}}{\sqrt [4]{1+i a x}}\right )}{128 \sqrt {2} a^4} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.08 (sec) , antiderivative size = 127, normalized size of antiderivative = 0.38 \[ \int e^{-\frac {1}{2} i \arctan (a x)} x^3 \, dx=\frac {(1-i a x)^{5/4} \left (5 a^2 x^2 (1+i a x)^{3/4}+4\ 2^{3/4} \operatorname {Hypergeometric2F1}\left (-\frac {7}{4},\frac {5}{4},\frac {9}{4},\frac {1}{2} (1-i a x)\right )-12\ 2^{3/4} \operatorname {Hypergeometric2F1}\left (-\frac {3}{4},\frac {5}{4},\frac {9}{4},\frac {1}{2} (1-i a x)\right )+5\ 2^{3/4} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {5}{4},\frac {9}{4},\frac {1}{2} (1-i a x)\right )\right )}{20 a^4} \]
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\[\int \frac {x^{3}}{\sqrt {\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}}}d x\]
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none
Time = 0.30 (sec) , antiderivative size = 255, normalized size of antiderivative = 0.76 \[ \int e^{-\frac {1}{2} i \arctan (a x)} x^3 \, dx=-\frac {96 \, a^{4} \sqrt {\frac {121 i}{4096 \, a^{8}}} \log \left (\frac {64}{11} i \, a^{4} \sqrt {\frac {121 i}{4096 \, a^{8}}} + \sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}}\right ) - 96 \, a^{4} \sqrt {\frac {121 i}{4096 \, a^{8}}} \log \left (-\frac {64}{11} i \, a^{4} \sqrt {\frac {121 i}{4096 \, a^{8}}} + \sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}}\right ) - 96 \, a^{4} \sqrt {-\frac {121 i}{4096 \, a^{8}}} \log \left (\frac {64}{11} i \, a^{4} \sqrt {-\frac {121 i}{4096 \, a^{8}}} + \sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}}\right ) + 96 \, a^{4} \sqrt {-\frac {121 i}{4096 \, a^{8}}} \log \left (-\frac {64}{11} i \, a^{4} \sqrt {-\frac {121 i}{4096 \, a^{8}}} + \sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}}\right ) - {\left (-48 i \, a^{3} x^{3} + 56 \, a^{2} x^{2} + 58 i \, a x - 83\right )} \sqrt {a^{2} x^{2} + 1} \sqrt {\frac {i \, \sqrt {a^{2} x^{2} + 1}}{a x + i}}}{192 \, a^{4}} \]
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\[ \int e^{-\frac {1}{2} i \arctan (a x)} x^3 \, dx=\int \frac {x^{3}}{\sqrt {\frac {i \left (a x - i\right )}{\sqrt {a^{2} x^{2} + 1}}}}\, dx \]
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\[ \int e^{-\frac {1}{2} i \arctan (a x)} x^3 \, dx=\int { \frac {x^{3}}{\sqrt {\frac {i \, a x + 1}{\sqrt {a^{2} x^{2} + 1}}}} \,d x } \]
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Exception generated. \[ \int e^{-\frac {1}{2} i \arctan (a x)} x^3 \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int e^{-\frac {1}{2} i \arctan (a x)} x^3 \, dx=\int \frac {x^3}{\sqrt {\frac {1+a\,x\,1{}\mathrm {i}}{\sqrt {a^2\,x^2+1}}}} \,d x \]
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