Integrand size = 16, antiderivative size = 93 \[ \int \frac {e^{2 i \arctan (a+b x)}}{x^4} \, dx=-\frac {i-a}{3 (i+a) x^3}+\frac {i b}{(i+a)^2 x^2}+\frac {2 b^2}{(1-i a)^3 x}-\frac {2 i b^3 \log (x)}{(i+a)^4}+\frac {2 i b^3 \log (i+a+b x)}{(i+a)^4} \]
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Time = 0.04 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {5203, 78} \[ \int \frac {e^{2 i \arctan (a+b x)}}{x^4} \, dx=-\frac {2 i b^3 \log (x)}{(a+i)^4}+\frac {2 i b^3 \log (a+b x+i)}{(a+i)^4}+\frac {2 b^2}{(1-i a)^3 x}+\frac {i b}{(a+i)^2 x^2}-\frac {-a+i}{3 (a+i) x^3} \]
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Rule 78
Rule 5203
Rubi steps \begin{align*} \text {integral}& = \int \frac {1+i a+i b x}{x^4 (1-i a-i b x)} \, dx \\ & = \int \left (\frac {i-a}{(i+a) x^4}-\frac {2 i b}{(i+a)^2 x^3}+\frac {2 i b^2}{(i+a)^3 x^2}-\frac {2 i b^3}{(i+a)^4 x}+\frac {2 i b^4}{(i+a)^4 (i+a+b x)}\right ) \, dx \\ & = -\frac {i-a}{3 (i+a) x^3}+\frac {i b}{(i+a)^2 x^2}+\frac {2 b^2}{(1-i a)^3 x}-\frac {2 i b^3 \log (x)}{(i+a)^4}+\frac {2 i b^3 \log (i+a+b x)}{(i+a)^4} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.95 \[ \int \frac {e^{2 i \arctan (a+b x)}}{x^4} \, dx=\frac {(i+a) \left (i+a+i a^2+a^3-3 b x+3 i a b x-6 i b^2 x^2\right )-6 i b^3 x^3 \log (x)+6 i b^3 x^3 \log (i+a+b x)}{3 (i+a)^4 x^3} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 266 vs. \(2 (79 ) = 158\).
Time = 0.35 (sec) , antiderivative size = 267, normalized size of antiderivative = 2.87
method | result | size |
default | \(-\frac {-a^{2}+2 i a +1}{3 \left (a^{2}+1\right ) x^{3}}+\frac {b \left (i a^{2}+2 a -i\right )}{\left (a^{2}+1\right )^{2} x^{2}}-\frac {2 b^{2} \left (i a^{3}+3 a^{2}-3 i a -1\right )}{\left (a^{2}+1\right )^{3} x}-\frac {2 b^{3} \left (i a^{4}+4 a^{3}-6 i a^{2}-4 a +i\right ) \ln \left (x \right )}{\left (a^{2}+1\right )^{4}}+\frac {2 b^{4} \left (\frac {\left (i a^{4} b +4 a^{3} b -6 i a^{2} b -4 a b +i b \right ) \ln \left (b^{2} x^{2}+2 a b x +a^{2}+1\right )}{2 b^{2}}+\frac {\left (i a^{5}-10 i a^{3}+5 a^{4}+5 i a -10 a^{2}+1-\frac {\left (i a^{4} b +4 a^{3} b -6 i a^{2} b -4 a b +i b \right ) a}{b}\right ) \arctan \left (\frac {2 b^{2} x +2 a b}{2 b}\right )}{b}\right )}{\left (a^{2}+1\right )^{4}}\) | \(267\) |
parallelrisch | \(-\frac {1+3 b x i+12 a^{2} b^{2} x^{2}+2 a^{2}+6 i x^{2} a^{5} b^{2}+6 i b^{3} \ln \left (x \right ) x^{3}+2 i a -12 a^{3} b x +2 i a^{7}-6 a^{5} b x +18 a^{4} b^{2} x^{2}-6 a b x -a^{8}-2 a^{6}-6 b^{2} x^{2}+6 i a^{5}+6 i \ln \left (x \right ) x^{3} a^{4} b^{3}-6 i \ln \left (b x +a +i\right ) x^{3} a^{4} b^{3}-36 i \ln \left (x \right ) x^{3} a^{2} b^{3}+36 i \ln \left (b x +a +i\right ) x^{3} a^{2} b^{3}-18 i a \,b^{2} x^{2}+3 i a^{2} b x +6 i a^{3}-3 i a^{4} b x -12 i x^{2} a^{3} b^{2}-3 i x \,a^{6} b +24 \ln \left (x \right ) x^{3} a^{3} b^{3}-24 \ln \left (x \right ) x^{3} a \,b^{3}-24 \ln \left (b x +a +i\right ) x^{3} a^{3} b^{3}+24 \ln \left (b x +a +i\right ) x^{3} a \,b^{3}-6 i b^{3} \ln \left (b x +a +i\right ) x^{3}}{3 \left (a^{6}+3 a^{4}+3 a^{2}+1\right ) \left (a^{2}+1\right ) x^{3}}\) | \(337\) |
risch | \(\frac {-\frac {2 i b^{2} x^{2}}{\left (a^{2}+2 i a -1\right ) \left (i+a \right )}+\frac {i b x}{a^{2}+2 i a -1}+\frac {a -i}{3 i+3 a}}{x^{3}}+\frac {2 b^{3} \ln \left (\left (-2 a^{6} b -6 a^{4} b -6 a^{2} b -2 b \right ) x \right )}{i a^{4}-4 a^{3}-6 i a^{2}+4 a +i}-\frac {b^{3} \ln \left (4 a^{12} b^{2} x^{2}+8 a^{13} b x +4 a^{14}+24 a^{10} b^{2} x^{2}+48 a^{11} b x +28 a^{12}+60 a^{8} b^{2} x^{2}+120 a^{9} b x +84 a^{10}+80 a^{6} b^{2} x^{2}+160 a^{7} b x +140 a^{8}+60 a^{4} b^{2} x^{2}+120 a^{5} b x +140 a^{6}+24 a^{2} b^{2} x^{2}+48 a^{3} b x +84 a^{4}+4 b^{2} x^{2}+8 a b x +28 a^{2}+4\right )}{i a^{4}-4 a^{3}-6 i a^{2}+4 a +i}+\frac {2 i b^{3} \arctan \left (\frac {\left (2 a^{6} b +6 a^{4} b +6 a^{2} b +2 b \right ) x +2 a^{7}+6 a^{5}+6 a^{3}+2 a}{2 a^{6}+6 a^{4}+6 a^{2}+2}\right )}{i a^{4}-4 a^{3}-6 i a^{2}+4 a +i}\) | \(400\) |
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Time = 0.25 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.01 \[ \int \frac {e^{2 i \arctan (a+b x)}}{x^4} \, dx=\frac {-6 i \, b^{3} x^{3} \log \left (x\right ) + 6 i \, b^{3} x^{3} \log \left (\frac {b x + a + i}{b}\right ) - 6 \, {\left (i \, a - 1\right )} b^{2} x^{2} + a^{4} + 2 i \, a^{3} - 3 \, {\left (-i \, a^{2} + 2 \, a + i\right )} b x + 2 i \, a - 1}{3 \, {\left (a^{4} + 4 i \, a^{3} - 6 \, a^{2} - 4 i \, a + 1\right )} x^{3}} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 286 vs. \(2 (73) = 146\).
Time = 0.56 (sec) , antiderivative size = 286, normalized size of antiderivative = 3.08 \[ \int \frac {e^{2 i \arctan (a+b x)}}{x^4} \, dx=- \frac {2 i b^{3} \log {\left (- \frac {2 a^{5} b^{3}}{\left (a + i\right )^{4}} - \frac {10 i a^{4} b^{3}}{\left (a + i\right )^{4}} + \frac {20 a^{3} b^{3}}{\left (a + i\right )^{4}} + \frac {20 i a^{2} b^{3}}{\left (a + i\right )^{4}} + 2 a b^{3} - \frac {10 a b^{3}}{\left (a + i\right )^{4}} + 4 b^{4} x + 2 i b^{3} - \frac {2 i b^{3}}{\left (a + i\right )^{4}} \right )}}{\left (a + i\right )^{4}} + \frac {2 i b^{3} \log {\left (\frac {2 a^{5} b^{3}}{\left (a + i\right )^{4}} + \frac {10 i a^{4} b^{3}}{\left (a + i\right )^{4}} - \frac {20 a^{3} b^{3}}{\left (a + i\right )^{4}} - \frac {20 i a^{2} b^{3}}{\left (a + i\right )^{4}} + 2 a b^{3} + \frac {10 a b^{3}}{\left (a + i\right )^{4}} + 4 b^{4} x + 2 i b^{3} + \frac {2 i b^{3}}{\left (a + i\right )^{4}} \right )}}{\left (a + i\right )^{4}} - \frac {- a^{3} - i a^{2} - a + 6 i b^{2} x^{2} + x \left (- 3 i a b + 3 b\right ) - i}{x^{3} \cdot \left (3 a^{3} + 9 i a^{2} - 9 a - 3 i\right )} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 263 vs. \(2 (69) = 138\).
Time = 0.26 (sec) , antiderivative size = 263, normalized size of antiderivative = 2.83 \[ \int \frac {e^{2 i \arctan (a+b x)}}{x^4} \, dx=\frac {2 \, {\left (a^{4} - 4 i \, a^{3} - 6 \, a^{2} + 4 i \, a + 1\right )} b^{3} \arctan \left (\frac {b^{2} x + a b}{b}\right )}{a^{8} + 4 \, a^{6} + 6 \, a^{4} + 4 \, a^{2} + 1} + \frac {{\left (i \, a^{4} + 4 \, a^{3} - 6 i \, a^{2} - 4 \, a + i\right )} b^{3} \log \left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}{a^{8} + 4 \, a^{6} + 6 \, a^{4} + 4 \, a^{2} + 1} - \frac {2 \, {\left (i \, a^{4} + 4 \, a^{3} - 6 i \, a^{2} - 4 \, a + i\right )} b^{3} \log \left (x\right )}{a^{8} + 4 \, a^{6} + 6 \, a^{4} + 4 \, a^{2} + 1} + \frac {a^{6} - 2 i \, a^{5} + 6 \, {\left (-i \, a^{3} - 3 \, a^{2} + 3 i \, a + 1\right )} b^{2} x^{2} + a^{4} - 4 i \, a^{3} + 3 \, {\left (i \, a^{4} + 2 \, a^{3} + 2 \, a - i\right )} b x - a^{2} - 2 i \, a - 1}{3 \, {\left (a^{6} + 3 \, a^{4} + 3 \, a^{2} + 1\right )} x^{3}} \]
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Time = 0.29 (sec) , antiderivative size = 126, normalized size of antiderivative = 1.35 \[ \int \frac {e^{2 i \arctan (a+b x)}}{x^4} \, dx=\frac {2 \, b^{4} \log \left (b x + a + i\right )}{-i \, a^{4} b + 4 \, a^{3} b + 6 i \, a^{2} b - 4 \, a b - i \, b} + \frac {2 \, b^{3} \log \left ({\left | x \right |}\right )}{i \, a^{4} - 4 \, a^{3} - 6 i \, a^{2} + 4 \, a + i} + \frac {a^{4} + 2 i \, a^{3} - 6 i \, {\left (a b^{2} + i \, b^{2}\right )} x^{2} + 3 i \, {\left (a^{2} b + 2 i \, a b - b\right )} x + 2 i \, a - 1}{3 \, {\left (a + i\right )}^{4} x^{3}} \]
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Time = 0.83 (sec) , antiderivative size = 199, normalized size of antiderivative = 2.14 \[ \int \frac {e^{2 i \arctan (a+b x)}}{x^4} \, dx=\frac {\frac {a-\mathrm {i}}{3\,\left (a+1{}\mathrm {i}\right )}-\frac {b^2\,x^2\,2{}\mathrm {i}}{{\left (a+1{}\mathrm {i}\right )}^3}+\frac {b\,x\,1{}\mathrm {i}}{{\left (a+1{}\mathrm {i}\right )}^2}}{x^3}+\frac {b^3\,\mathrm {atanh}\left (\frac {a^4+a^3\,4{}\mathrm {i}-6\,a^2-a\,4{}\mathrm {i}+1}{{\left (a+1{}\mathrm {i}\right )}^4}-\frac {x\,\left (2\,a^{12}\,b^2+12\,a^{10}\,b^2+30\,a^8\,b^2+40\,a^6\,b^2+30\,a^4\,b^2+12\,a^2\,b^2+2\,b^2\right )}{{\left (a+1{}\mathrm {i}\right )}^4\,\left (-b\,a^9+3{}\mathrm {i}\,b\,a^8+8{}\mathrm {i}\,b\,a^6+6\,b\,a^5+6{}\mathrm {i}\,b\,a^4+8\,b\,a^3+3\,b\,a-b\,1{}\mathrm {i}\right )}\right )\,4{}\mathrm {i}}{{\left (a+1{}\mathrm {i}\right )}^4} \]
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