Integrand size = 16, antiderivative size = 176 \[ \int \frac {e^{3 i \arctan (a+b x)}}{x^2} \, dx=-\frac {6 i b \sqrt {1+i a+i b x}}{(i+a)^2 \sqrt {1-i a-i b x}}-\frac {(1+i a+i b x)^{3/2}}{(1-i a) x \sqrt {1-i a-i b x}}+\frac {6 i \sqrt {i-a} b \text {arctanh}\left (\frac {\sqrt {i+a} \sqrt {1+i a+i b x}}{\sqrt {i-a} \sqrt {1-i a-i b x}}\right )}{(i+a)^{5/2}} \]
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Time = 0.06 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {5203, 96, 95, 214} \[ \int \frac {e^{3 i \arctan (a+b x)}}{x^2} \, dx=\frac {6 i \sqrt {-a+i} b \text {arctanh}\left (\frac {\sqrt {a+i} \sqrt {i a+i b x+1}}{\sqrt {-a+i} \sqrt {-i a-i b x+1}}\right )}{(a+i)^{5/2}}-\frac {(i a+i b x+1)^{3/2}}{(1-i a) x \sqrt {-i a-i b x+1}}-\frac {6 i b \sqrt {i a+i b x+1}}{(a+i)^2 \sqrt {-i a-i b x+1}} \]
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Rule 95
Rule 96
Rule 214
Rule 5203
Rubi steps \begin{align*} \text {integral}& = \int \frac {(1+i a+i b x)^{3/2}}{x^2 (1-i a-i b x)^{3/2}} \, dx \\ & = -\frac {(1+i a+i b x)^{3/2}}{(1-i a) x \sqrt {1-i a-i b x}}-\frac {(3 b) \int \frac {\sqrt {1+i a+i b x}}{x (1-i a-i b x)^{3/2}} \, dx}{i+a} \\ & = -\frac {6 i b \sqrt {1+i a+i b x}}{(i+a)^2 \sqrt {1-i a-i b x}}-\frac {(1+i a+i b x)^{3/2}}{(1-i a) x \sqrt {1-i a-i b x}}-\frac {(3 (i-a) b) \int \frac {1}{x \sqrt {1-i a-i b x} \sqrt {1+i a+i b x}} \, dx}{(i+a)^2} \\ & = -\frac {6 i b \sqrt {1+i a+i b x}}{(i+a)^2 \sqrt {1-i a-i b x}}-\frac {(1+i a+i b x)^{3/2}}{(1-i a) x \sqrt {1-i a-i b x}}-\frac {(6 (i-a) b) \text {Subst}\left (\int \frac {1}{-1-i a-(-1+i a) x^2} \, dx,x,\frac {\sqrt {1+i a+i b x}}{\sqrt {1-i a-i b x}}\right )}{(i+a)^2} \\ & = -\frac {6 i b \sqrt {1+i a+i b x}}{(i+a)^2 \sqrt {1-i a-i b x}}-\frac {(1+i a+i b x)^{3/2}}{(1-i a) x \sqrt {1-i a-i b x}}+\frac {6 i \sqrt {i-a} b \text {arctanh}\left (\frac {\sqrt {i+a} \sqrt {1+i a+i b x}}{\sqrt {i-a} \sqrt {1-i a-i b x}}\right )}{(i+a)^{5/2}} \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 145, normalized size of antiderivative = 0.82 \[ \int \frac {e^{3 i \arctan (a+b x)}}{x^2} \, dx=\frac {\frac {\sqrt {1+i a+i b x} \left (1+a^2-5 i b x+a b x\right )}{x \sqrt {-i (i+a+b x)}}+\frac {6 i \sqrt {-1-i a} b \text {arctanh}\left (\frac {\sqrt {-1-i a} \sqrt {-i (i+a+b x)}}{\sqrt {-1+i a} \sqrt {1+i a+i b x}}\right )}{\sqrt {-1+i a}}}{(i+a)^2} \]
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Time = 1.58 (sec) , antiderivative size = 181, normalized size of antiderivative = 1.03
method | result | size |
risch | \(\frac {i \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\, \left (a -i\right )}{\left (i+a \right )^{2} x}+\frac {b \left (-\frac {\left (3 a^{2}+3\right ) \ln \left (\frac {2 a^{2}+2+2 a b x +2 \sqrt {a^{2}+1}\, \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{x}\right )}{\left (i+a \right ) \sqrt {a^{2}+1}}-\frac {4 i \left (i a -1\right ) \sqrt {\left (x +\frac {i+a}{b}\right )^{2} b^{2}-2 i b \left (x +\frac {i+a}{b}\right )}}{b \left (i+a \right ) \left (x +\frac {i+a}{b}\right )}\right )}{a^{2}+2 i a -1}\) | \(181\) |
default | \(-\frac {6 b^{2} \left (2 b^{2} x +2 a b \right )}{\left (4 b^{2} \left (a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}-i b^{3} \left (-\frac {1}{b^{2} \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}-\frac {2 a \left (2 b^{2} x +2 a b \right )}{b \left (4 b^{2} \left (a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}\right )-\frac {6 i a \,b^{2} \left (2 b^{2} x +2 a b \right )}{\left (4 b^{2} \left (a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}-3 b \left (i a^{2}+2 a -i\right ) \left (\frac {1}{\left (a^{2}+1\right ) \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}-\frac {2 a b \left (2 b^{2} x +2 a b \right )}{\left (a^{2}+1\right ) \left (4 b^{2} \left (a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}-\frac {\ln \left (\frac {2 a^{2}+2+2 a b x +2 \sqrt {a^{2}+1}\, \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{x}\right )}{\left (a^{2}+1\right )^{\frac {3}{2}}}\right )+\left (-i a^{3}-3 a^{2}+3 i a +1\right ) \left (-\frac {1}{\left (a^{2}+1\right ) x \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}-\frac {3 a b \left (\frac {1}{\left (a^{2}+1\right ) \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}-\frac {2 a b \left (2 b^{2} x +2 a b \right )}{\left (a^{2}+1\right ) \left (4 b^{2} \left (a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}-\frac {\ln \left (\frac {2 a^{2}+2+2 a b x +2 \sqrt {a^{2}+1}\, \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{x}\right )}{\left (a^{2}+1\right )^{\frac {3}{2}}}\right )}{a^{2}+1}-\frac {4 b^{2} \left (2 b^{2} x +2 a b \right )}{\left (a^{2}+1\right ) \left (4 b^{2} \left (a^{2}+1\right )-4 a^{2} b^{2}\right ) \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}\right )\) | \(631\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 389 vs. \(2 (116) = 232\).
Time = 0.30 (sec) , antiderivative size = 389, normalized size of antiderivative = 2.21 \[ \int \frac {e^{3 i \arctan (a+b x)}}{x^2} \, dx=-\frac {{\left (-i \, a - 5\right )} b^{2} x^{2} + {\left (-i \, a^{2} - 4 \, a - 5 i\right )} b x - 3 \, {\left ({\left (a^{2} + 2 i \, a - 1\right )} b x^{2} + {\left (a^{3} + 3 i \, a^{2} - 3 \, a - i\right )} x\right )} \sqrt {\frac {{\left (a - i\right )} b^{2}}{a^{5} + 5 i \, a^{4} - 10 \, a^{3} - 10 i \, a^{2} + 5 \, a + i}} \log \left (-\frac {b^{2} x + {\left (a^{3} + 3 i \, a^{2} - 3 \, a - i\right )} \sqrt {\frac {{\left (a - i\right )} b^{2}}{a^{5} + 5 i \, a^{4} - 10 \, a^{3} - 10 i \, a^{2} + 5 \, a + i}} - \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} b}{b}\right ) + 3 \, {\left ({\left (a^{2} + 2 i \, a - 1\right )} b x^{2} + {\left (a^{3} + 3 i \, a^{2} - 3 \, a - i\right )} x\right )} \sqrt {\frac {{\left (a - i\right )} b^{2}}{a^{5} + 5 i \, a^{4} - 10 \, a^{3} - 10 i \, a^{2} + 5 \, a + i}} \log \left (-\frac {b^{2} x - {\left (a^{3} + 3 i \, a^{2} - 3 \, a - i\right )} \sqrt {\frac {{\left (a - i\right )} b^{2}}{a^{5} + 5 i \, a^{4} - 10 \, a^{3} - 10 i \, a^{2} + 5 \, a + i}} - \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} b}{b}\right ) + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} {\left ({\left (-i \, a - 5\right )} b x - i \, a^{2} - i\right )}}{{\left (a^{2} + 2 i \, a - 1\right )} b x^{2} + {\left (a^{3} + 3 i \, a^{2} - 3 \, a - i\right )} x} \]
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\[ \int \frac {e^{3 i \arctan (a+b x)}}{x^2} \, dx=- i \left (\int \frac {i}{a^{2} x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + 2 a b x^{3} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + b^{2} x^{4} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}\, dx + \int \left (- \frac {3 a}{a^{2} x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + 2 a b x^{3} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + b^{2} x^{4} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}\right )\, dx + \int \frac {a^{3}}{a^{2} x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + 2 a b x^{3} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + b^{2} x^{4} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}\, dx + \int \left (- \frac {3 i a^{2}}{a^{2} x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + 2 a b x^{3} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + b^{2} x^{4} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}\right )\, dx + \int \left (- \frac {3 b x}{a^{2} x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + 2 a b x^{3} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + b^{2} x^{4} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}\right )\, dx + \int \frac {b^{3} x^{3}}{a^{2} x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + 2 a b x^{3} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + b^{2} x^{4} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}\, dx + \int \left (- \frac {3 i b^{2} x^{2}}{a^{2} x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + 2 a b x^{3} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + b^{2} x^{4} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}\right )\, dx + \int \frac {3 a b^{2} x^{2}}{a^{2} x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + 2 a b x^{3} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + b^{2} x^{4} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}\, dx + \int \frac {3 a^{2} b x}{a^{2} x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + 2 a b x^{3} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + b^{2} x^{4} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}\, dx + \int \left (- \frac {6 i a b x}{a^{2} x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + 2 a b x^{3} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + b^{2} x^{4} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} + x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}\right )\, dx\right ) \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 992 vs. \(2 (116) = 232\).
Time = 0.21 (sec) , antiderivative size = 992, normalized size of antiderivative = 5.64 \[ \int \frac {e^{3 i \arctan (a+b x)}}{x^2} \, dx=\text {Too large to display} \]
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\[ \int \frac {e^{3 i \arctan (a+b x)}}{x^2} \, dx=\int { \frac {{\left (i \, b x + i \, a + 1\right )}^{3}}{{\left ({\left (b x + a\right )}^{2} + 1\right )}^{\frac {3}{2}} x^{2}} \,d x } \]
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Timed out. \[ \int \frac {e^{3 i \arctan (a+b x)}}{x^2} \, dx=\int \frac {{\left (1+a\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}\right )}^3}{x^2\,{\left ({\left (a+b\,x\right )}^2+1\right )}^{3/2}} \,d x \]
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