Integrand size = 16, antiderivative size = 83 \[ \int \frac {e^{-2 i \arctan (a+b x)}}{x^3} \, dx=\frac {-i-a}{2 (i-a) x^2}-\frac {2 i b}{(i-a)^2 x}-\frac {2 b^2 \log (x)}{(1+i a)^3}+\frac {2 b^2 \log (i-a-b x)}{(1+i a)^3} \]
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Time = 0.04 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.98, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {5203, 78} \[ \int \frac {e^{-2 i \arctan (a+b x)}}{x^3} \, dx=-\frac {2 b^2 \log (x)}{(1+i a)^3}+\frac {2 b^2 \log (-a-b x+i)}{(1+i a)^3}-\frac {2 i b}{(-a+i)^2 x}-\frac {a+i}{2 (-a+i) x^2} \]
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Rule 78
Rule 5203
Rubi steps \begin{align*} \text {integral}& = \int \frac {1-i a-i b x}{x^3 (1+i a+i b x)} \, dx \\ & = \int \left (\frac {-i-a}{(-i+a) x^3}+\frac {2 i b}{(-i+a)^2 x^2}-\frac {2 i b^2}{(-i+a)^3 x}+\frac {2 i b^3}{(-i+a)^3 (-i+a+b x)}\right ) \, dx \\ & = -\frac {i+a}{2 (i-a) x^2}-\frac {2 i b}{(i-a)^2 x}-\frac {2 b^2 \log (x)}{(1+i a)^3}+\frac {2 b^2 \log (i-a-b x)}{(1+i a)^3} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.80 \[ \int \frac {e^{-2 i \arctan (a+b x)}}{x^3} \, dx=\frac {(-i+a) \left (1+a^2-4 i b x\right )-4 i b^2 x^2 \log (x)+4 i b^2 x^2 \log (i-a-b x)}{2 (-i+a)^3 x^2} \]
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Time = 0.29 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.31
method | result | size |
default | \(-\frac {2 b^{2} \left (i a +1\right ) \ln \left (x \right )}{\left (i-a \right )^{4}}-\frac {2 b \left (i a^{2}+2 a -i\right )}{\left (i-a \right )^{4} x}-\frac {-a^{4}+2 i a^{3}+2 i a +1}{2 \left (i-a \right )^{4} x^{2}}+\frac {2 b^{2} \left (i a +1\right ) \ln \left (-b x -a +i\right )}{\left (i-a \right )^{4}}\) | \(109\) |
risch | \(\frac {-\frac {2 i b x}{a^{2}-2 i a -1}+\frac {i+a}{2 a -2 i}}{x^{2}}+\frac {2 b^{2} \ln \left (\left (2 a^{4} b +4 a^{2} b +2 b \right ) x \right )}{i a^{3}+3 a^{2}-3 i a -1}-\frac {b^{2} \ln \left (4 a^{8} b^{2} x^{2}+8 a^{9} b x +4 a^{10}+16 a^{6} b^{2} x^{2}+32 a^{7} b x +20 a^{8}+24 a^{4} b^{2} x^{2}+48 a^{5} b x +40 a^{6}+16 a^{2} b^{2} x^{2}+32 a^{3} b x +40 a^{4}+4 b^{2} x^{2}+8 a b x +20 a^{2}+4\right )}{i a^{3}+3 a^{2}-3 i a -1}+\frac {2 i b^{2} \arctan \left (\frac {\left (-2 a^{4} b -4 a^{2} b -2 b \right ) x -2 a^{5}-4 a^{3}-2 a}{2 a^{4}+4 a^{2}+2}\right )}{i a^{3}+3 a^{2}-3 i a -1}\) | \(288\) |
parallelrisch | \(\frac {-b -42 a^{4} b +8 i a^{9} b -48 i a^{7} b -8 i a b +4 \ln \left (b x +a -i\right ) x^{2} b^{3}+3 i x \,b^{2}+24 \ln \left (x \right ) x^{3} a^{5} b^{4}+28 \ln \left (x \right ) x^{2} a^{6} b^{3}-80 \ln \left (x \right ) x^{3} a^{3} b^{4}-140 \ln \left (x \right ) x^{2} a^{4} b^{3}+24 \ln \left (x \right ) x^{3} a \,b^{4}+84 \ln \left (x \right ) x^{2} a^{2} b^{3}-24 \ln \left (b x +a -i\right ) x^{3} a^{5} b^{4}-28 \ln \left (b x +a -i\right ) x^{2} a^{6} b^{3}+80 \ln \left (b x +a -i\right ) x^{3} a^{3} b^{4}+140 \ln \left (b x +a -i\right ) x^{2} a^{4} b^{3}-24 \ln \left (b x +a -i\right ) x^{3} a \,b^{4}-84 \ln \left (b x +a -i\right ) x^{2} a^{2} b^{3}-84 i x^{2} a^{5} b^{3}-4 i \ln \left (x \right ) x^{3} b^{4}+4 i \ln \left (b x +a -i\right ) x^{3} b^{4}+266 i x \,a^{4} b^{2}-92 i x \,a^{2} b^{2}+140 i x^{2} a^{3} b^{3}-28 i x^{2} a \,b^{3}+4 i x^{2} a^{7} b^{3}+11 i x \,a^{8} b^{2}-140 i x \,a^{6} b^{2}+48 i a^{3} b -25 a \,b^{2} x -a^{10} b +27 a^{8} b +28 x^{2} a^{6} b^{3}-140 x^{2} a^{4} b^{3}+84 x^{2} a^{2} b^{3}-x \,a^{9} b^{2}+52 x \,a^{7} b^{2}-238 x \,a^{5} b^{2}+196 x \,a^{3} b^{2}-4 \ln \left (x \right ) x^{2} b^{3}+27 a^{2} b -42 a^{6} b -4 b^{3} x^{2}+60 i \ln \left (x \right ) x^{3} a^{2} b^{4}-60 i \ln \left (b x +a -i\right ) x^{3} a^{2} b^{4}-84 i \ln \left (x \right ) x^{2} a^{5} b^{3}+84 i \ln \left (b x +a -i\right ) x^{2} a^{5} b^{3}+140 i \ln \left (x \right ) x^{2} a^{3} b^{3}-140 i \ln \left (b x +a -i\right ) x^{2} a^{3} b^{3}-28 i \ln \left (x \right ) x^{2} a \,b^{3}+28 i \ln \left (b x +a -i\right ) x^{2} a \,b^{3}+4 i \ln \left (x \right ) x^{3} a^{6} b^{4}-4 i \ln \left (b x +a -i\right ) x^{3} a^{6} b^{4}+4 i \ln \left (x \right ) x^{2} a^{7} b^{3}-4 i \ln \left (b x +a -i\right ) x^{2} a^{7} b^{3}-60 i \ln \left (x \right ) x^{3} a^{4} b^{4}+60 i \ln \left (b x +a -i\right ) x^{3} a^{4} b^{4}}{2 \left (-a^{6}+6 i a^{5}+15 a^{4}-20 i a^{3}-15 a^{2}+6 i a +1\right ) b \left (-a^{3}+3 i a^{2}+3 a -i\right ) \left (-b x -a +i\right ) x^{2}}\) | \(788\) |
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Time = 0.27 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.83 \[ \int \frac {e^{-2 i \arctan (a+b x)}}{x^3} \, dx=\frac {-4 i \, b^{2} x^{2} \log \left (x\right ) + 4 i \, b^{2} x^{2} \log \left (\frac {b x + a - i}{b}\right ) + a^{3} - 4 \, {\left (i \, a + 1\right )} b x - i \, a^{2} + a - i}{2 \, {\left (a^{3} - 3 i \, a^{2} - 3 \, a + i\right )} x^{2}} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 226 vs. \(2 (61) = 122\).
Time = 0.44 (sec) , antiderivative size = 226, normalized size of antiderivative = 2.72 \[ \int \frac {e^{-2 i \arctan (a+b x)}}{x^3} \, dx=- \frac {2 i b^{2} \log {\left (- \frac {2 a^{4} b^{2}}{\left (a - i\right )^{3}} + \frac {8 i a^{3} b^{2}}{\left (a - i\right )^{3}} + \frac {12 a^{2} b^{2}}{\left (a - i\right )^{3}} + 2 a b^{2} - \frac {8 i a b^{2}}{\left (a - i\right )^{3}} + 4 b^{3} x - 2 i b^{2} - \frac {2 b^{2}}{\left (a - i\right )^{3}} \right )}}{\left (a - i\right )^{3}} + \frac {2 i b^{2} \log {\left (\frac {2 a^{4} b^{2}}{\left (a - i\right )^{3}} - \frac {8 i a^{3} b^{2}}{\left (a - i\right )^{3}} - \frac {12 a^{2} b^{2}}{\left (a - i\right )^{3}} + 2 a b^{2} + \frac {8 i a b^{2}}{\left (a - i\right )^{3}} + 4 b^{3} x - 2 i b^{2} + \frac {2 b^{2}}{\left (a - i\right )^{3}} \right )}}{\left (a - i\right )^{3}} - \frac {- a^{2} + 4 i b x - 1}{x^{2} \cdot \left (2 a^{2} - 4 i a - 2\right )} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 160 vs. \(2 (61) = 122\).
Time = 0.19 (sec) , antiderivative size = 160, normalized size of antiderivative = 1.93 \[ \int \frac {e^{-2 i \arctan (a+b x)}}{x^3} \, dx=-\frac {2 \, {\left (-i \, a - 1\right )} b^{2} \log \left (i \, b x + i \, a + 1\right )}{a^{4} - 4 i \, a^{3} - 6 \, a^{2} + 4 i \, a + 1} - \frac {2 \, {\left (i \, a + 1\right )} b^{2} \log \left (x\right )}{a^{4} - 4 i \, a^{3} - 6 \, a^{2} + 4 i \, a + 1} + \frac {4 \, {\left (-i \, a - 1\right )} b^{2} x^{2} + a^{4} - 2 i \, a^{3} + {\left (a^{3} - 5 i \, a^{2} - 7 \, a + 3 i\right )} b x - 2 i \, a - 1}{2 \, {\left ({\left (a^{3} - 3 i \, a^{2} - 3 \, a + i\right )} b x^{3} + {\left (a^{4} - 4 i \, a^{3} - 6 \, a^{2} + 4 i \, a + 1\right )} x^{2}\right )}} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 142 vs. \(2 (61) = 122\).
Time = 0.27 (sec) , antiderivative size = 142, normalized size of antiderivative = 1.71 \[ \int \frac {e^{-2 i \arctan (a+b x)}}{x^3} \, dx=\frac {2 \, b^{3} \log \left (-\frac {i \, a}{i \, b x + i \, a + 1} - \frac {1}{i \, b x + i \, a + 1} + 1\right )}{i \, a^{3} b + 3 \, a^{2} b - 3 i \, a b - b} + \frac {\frac {i \, a b^{2} - 5 \, b^{2}}{-i \, a - 1} + \frac {2 i \, {\left (a b^{3} + 3 i \, b^{3}\right )}}{{\left (i \, b x + i \, a + 1\right )} b}}{2 \, {\left (a - i\right )}^{2} {\left (\frac {i \, a}{i \, b x + i \, a + 1} + \frac {1}{i \, b x + i \, a + 1} - 1\right )}^{2}} \]
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Time = 0.80 (sec) , antiderivative size = 156, normalized size of antiderivative = 1.88 \[ \int \frac {e^{-2 i \arctan (a+b x)}}{x^3} \, dx=\frac {\frac {a+1{}\mathrm {i}}{2\,\left (a-\mathrm {i}\right )}-\frac {b\,x\,2{}\mathrm {i}}{{\left (a-\mathrm {i}\right )}^2}}{x^2}-\frac {b^2\,\mathrm {atanh}\left (\frac {-a^3+a^2\,3{}\mathrm {i}+3\,a-\mathrm {i}}{{\left (a-\mathrm {i}\right )}^3}-\frac {x\,\left (2\,a^8\,b^2+8\,a^6\,b^2+12\,a^4\,b^2+8\,a^2\,b^2+2\,b^2\right )}{{\left (a-\mathrm {i}\right )}^3\,\left (b\,a^6+2{}\mathrm {i}\,b\,a^5+b\,a^4+4{}\mathrm {i}\,b\,a^3-b\,a^2+2{}\mathrm {i}\,b\,a-b\right )}\right )\,4{}\mathrm {i}}{{\left (a-\mathrm {i}\right )}^3} \]
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