Integrand size = 14, antiderivative size = 140 \[ \int e^{n \arctan (a+b x)} x^m \, dx=\frac {x^{1+m} (1-i a-i b x)^{\frac {i n}{2}} (1+i a+i b x)^{-\frac {i n}{2}} \left (1-\frac {b x}{i-a}\right )^{\frac {i n}{2}} \left (1+\frac {b x}{i+a}\right )^{-\frac {i n}{2}} \operatorname {AppellF1}\left (1+m,-\frac {i n}{2},\frac {i n}{2},2+m,-\frac {b x}{i+a},\frac {b x}{i-a}\right )}{1+m} \]
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Time = 0.06 (sec) , antiderivative size = 140, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {5203, 140, 138} \[ \int e^{n \arctan (a+b x)} x^m \, dx=\frac {x^{m+1} (-i a-i b x+1)^{\frac {i n}{2}} (i a+i b x+1)^{-\frac {i n}{2}} \left (1-\frac {b x}{-a+i}\right )^{\frac {i n}{2}} \left (1+\frac {b x}{a+i}\right )^{-\frac {i n}{2}} \operatorname {AppellF1}\left (m+1,-\frac {i n}{2},\frac {i n}{2},m+2,-\frac {b x}{a+i},\frac {b x}{i-a}\right )}{m+1} \]
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Rule 138
Rule 140
Rule 5203
Rubi steps \begin{align*} \text {integral}& = \int x^m (1-i a-i b x)^{\frac {i n}{2}} (1+i a+i b x)^{-\frac {i n}{2}} \, dx \\ & = \left ((1-i a-i b x)^{\frac {i n}{2}} \left (1-\frac {i b x}{1-i a}\right )^{-\frac {i n}{2}}\right ) \int x^m (1+i a+i b x)^{-\frac {i n}{2}} \left (1-\frac {i b x}{1-i a}\right )^{\frac {i n}{2}} \, dx \\ & = \left ((1-i a-i b x)^{\frac {i n}{2}} (1+i a+i b x)^{-\frac {i n}{2}} \left (1-\frac {i b x}{1-i a}\right )^{-\frac {i n}{2}} \left (1+\frac {i b x}{1+i a}\right )^{\frac {i n}{2}}\right ) \int x^m \left (1-\frac {i b x}{1-i a}\right )^{\frac {i n}{2}} \left (1+\frac {i b x}{1+i a}\right )^{-\frac {i n}{2}} \, dx \\ & = \frac {x^{1+m} (1-i a-i b x)^{\frac {i n}{2}} (1+i a+i b x)^{-\frac {i n}{2}} \left (1-\frac {b x}{i-a}\right )^{\frac {i n}{2}} \left (1+\frac {b x}{i+a}\right )^{-\frac {i n}{2}} \operatorname {AppellF1}\left (1+m,-\frac {i n}{2},\frac {i n}{2},2+m,-\frac {b x}{i+a},\frac {b x}{i-a}\right )}{1+m} \\ \end{align*}
\[ \int e^{n \arctan (a+b x)} x^m \, dx=\int e^{n \arctan (a+b x)} x^m \, dx \]
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\[\int {\mathrm e}^{n \arctan \left (b x +a \right )} x^{m}d x\]
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\[ \int e^{n \arctan (a+b x)} x^m \, dx=\int { x^{m} e^{\left (n \arctan \left (b x + a\right )\right )} \,d x } \]
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\[ \int e^{n \arctan (a+b x)} x^m \, dx=\int x^{m} e^{n \operatorname {atan}{\left (a + b x \right )}}\, dx \]
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\[ \int e^{n \arctan (a+b x)} x^m \, dx=\int { x^{m} e^{\left (n \arctan \left (b x + a\right )\right )} \,d x } \]
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\[ \int e^{n \arctan (a+b x)} x^m \, dx=\int { x^{m} e^{\left (n \arctan \left (b x + a\right )\right )} \,d x } \]
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Timed out. \[ \int e^{n \arctan (a+b x)} x^m \, dx=\int x^m\,{\mathrm {e}}^{n\,\mathrm {atan}\left (a+b\,x\right )} \,d x \]
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