Integrand size = 14, antiderivative size = 48 \[ \int e^{2 i \arctan (a x)} x^3 \, dx=-\frac {2 i x}{a^3}+\frac {x^2}{a^2}+\frac {2 i x^3}{3 a}-\frac {x^4}{4}-\frac {2 \log (i+a x)}{a^4} \]
[Out]
Time = 0.03 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {5170, 78} \[ \int e^{2 i \arctan (a x)} x^3 \, dx=-\frac {2 \log (a x+i)}{a^4}-\frac {2 i x}{a^3}+\frac {x^2}{a^2}+\frac {2 i x^3}{3 a}-\frac {x^4}{4} \]
[In]
[Out]
Rule 78
Rule 5170
Rubi steps \begin{align*} \text {integral}& = \int \frac {x^3 (1+i a x)}{1-i a x} \, dx \\ & = \int \left (-\frac {2 i}{a^3}+\frac {2 x}{a^2}+\frac {2 i x^2}{a}-x^3-\frac {2}{a^3 (i+a x)}\right ) \, dx \\ & = -\frac {2 i x}{a^3}+\frac {x^2}{a^2}+\frac {2 i x^3}{3 a}-\frac {x^4}{4}-\frac {2 \log (i+a x)}{a^4} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.00 \[ \int e^{2 i \arctan (a x)} x^3 \, dx=-\frac {2 i x}{a^3}+\frac {x^2}{a^2}+\frac {2 i x^3}{3 a}-\frac {x^4}{4}-\frac {2 \log (i+a x)}{a^4} \]
[In]
[Out]
Time = 0.24 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.96
method | result | size |
parallelrisch | \(\frac {-3 a^{4} x^{4}+8 i a^{3} x^{3}+12 a^{2} x^{2}-24 i a x -24 \ln \left (a x +i\right )}{12 a^{4}}\) | \(46\) |
risch | \(-\frac {x^{4}}{4}+\frac {2 i x^{3}}{3 a}+\frac {x^{2}}{a^{2}}-\frac {2 i x}{a^{3}}-\frac {\ln \left (a^{2} x^{2}+1\right )}{a^{4}}+\frac {2 i \arctan \left (a x \right )}{a^{4}}\) | \(55\) |
default | \(\frac {-\frac {1}{4} a^{3} x^{4}+\frac {2}{3} i a^{2} x^{3}+a \,x^{2}-2 i x}{a^{3}}+\frac {-\frac {\ln \left (a^{2} x^{2}+1\right )}{a}+\frac {2 i \arctan \left (a x \right )}{a}}{a^{3}}\) | \(63\) |
meijerg | \(\frac {a^{2} x^{2}-\ln \left (a^{2} x^{2}+1\right )}{2 a^{4}}+\frac {i \left (-\frac {2 x \left (a^{2}\right )^{\frac {5}{2}} \left (-5 a^{2} x^{2}+15\right )}{15 a^{4}}+\frac {2 \left (a^{2}\right )^{\frac {5}{2}} \arctan \left (a x \right )}{a^{5}}\right )}{a^{3} \sqrt {a^{2}}}-\frac {-\frac {x^{2} a^{2} \left (-3 a^{2} x^{2}+6\right )}{6}+\ln \left (a^{2} x^{2}+1\right )}{2 a^{4}}\) | \(108\) |
[In]
[Out]
none
Time = 0.25 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.96 \[ \int e^{2 i \arctan (a x)} x^3 \, dx=-\frac {3 \, a^{4} x^{4} - 8 i \, a^{3} x^{3} - 12 \, a^{2} x^{2} + 24 i \, a x + 24 \, \log \left (\frac {a x + i}{a}\right )}{12 \, a^{4}} \]
[In]
[Out]
Time = 0.08 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.85 \[ \int e^{2 i \arctan (a x)} x^3 \, dx=- \frac {x^{4}}{4} + \frac {2 i x^{3}}{3 a} + \frac {x^{2}}{a^{2}} - \frac {2 i x}{a^{3}} - \frac {2 \log {\left (a x + i \right )}}{a^{4}} \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.17 \[ \int e^{2 i \arctan (a x)} x^3 \, dx=-\frac {3 \, a^{3} x^{4} - 8 i \, a^{2} x^{3} - 12 \, a x^{2} + 24 i \, x}{12 \, a^{3}} + \frac {2 i \, \arctan \left (a x\right )}{a^{4}} - \frac {\log \left (a^{2} x^{2} + 1\right )}{a^{4}} \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.96 \[ \int e^{2 i \arctan (a x)} x^3 \, dx=-\frac {3 \, a^{4} x^{4} - 8 i \, a^{3} x^{3} - 12 \, a^{2} x^{2} + 24 i \, a x}{12 \, a^{4}} - \frac {2 \, \log \left (a x + i\right )}{a^{4}} \]
[In]
[Out]
Time = 0.47 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.90 \[ \int e^{2 i \arctan (a x)} x^3 \, dx=\frac {x^2}{a^2}-\frac {x^4}{4}-\frac {2\,\ln \left (x+\frac {1{}\mathrm {i}}{a}\right )}{a^4}-\frac {x\,2{}\mathrm {i}}{a^3}+\frac {x^3\,2{}\mathrm {i}}{3\,a} \]
[In]
[Out]