\(\int e^{2 \arctan (a x)} (c+a^2 c x^2)^2 \, dx\) [260]

Optimal result

Integrand size = 21, antiderivative size = 53 \[ \int e^{2 \arctan (a x)} \left (c+a^2 c x^2\right )^2 \, dx=\frac {\left (\frac {1}{5}+\frac {3 i}{5}\right ) 2^{1-i} c^2 (1-i a x)^{3+i} \operatorname {Hypergeometric2F1}\left (-2+i,3+i,4+i,\frac {1}{2} (1-i a x)\right )}{a} \]

[Out]

(1/5+3/5*I)*2^(1-I)*c^2*(1-I*a*x)^(3+I)*hypergeom([3+I, -2+I],[4+I],1/2-1/2*I*a*x)/a

Rubi [A] (verified)

Time = 0.03 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {5181, 71} \[ \int e^{2 \arctan (a x)} \left (c+a^2 c x^2\right )^2 \, dx=\frac {\left (\frac {1}{5}+\frac {3 i}{5}\right ) 2^{1-i} c^2 (1-i a x)^{3+i} \operatorname {Hypergeometric2F1}\left (-2+i,3+i,4+i,\frac {1}{2} (1-i a x)\right )}{a} \]

[In]

Int[E^(2*ArcTan[a*x])*(c + a^2*c*x^2)^2,x]

[Out]

((1/5 + (3*I)/5)*2^(1 - I)*c^2*(1 - I*a*x)^(3 + I)*Hypergeometric2F1[-2 + I, 3 + I, 4 + I, (1 - I*a*x)/2])/a

Rule 71

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)/(b*(m + 1)*(b/(b*c
- a*d))^n))*Hypergeometric2F1[-n, m + 1, m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m, n}
, x] && NeQ[b*c - a*d, 0] &&  !IntegerQ[m] &&  !IntegerQ[n] && GtQ[b/(b*c - a*d), 0] && (RationalQ[m] ||  !(Ra
tionalQ[n] && GtQ[-d/(b*c - a*d), 0]))

Rule 5181

Int[E^(ArcTan[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[c^p, Int[(1 - I*a*x)^(p + I*(n
/2))*(1 + I*a*x)^(p - I*(n/2)), x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[d, a^2*c] && (IntegerQ[p] || GtQ[c,
0])

Rubi steps \begin{align*} \text {integral}& = c^2 \int (1-i a x)^{2+i} (1+i a x)^{2-i} \, dx \\ & = \frac {\left (\frac {1}{5}+\frac {3 i}{5}\right ) 2^{1-i} c^2 (1-i a x)^{3+i} \operatorname {Hypergeometric2F1}\left (-2+i,3+i,4+i,\frac {1}{2} (1-i a x)\right )}{a} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.01 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.00 \[ \int e^{2 \arctan (a x)} \left (c+a^2 c x^2\right )^2 \, dx=\frac {\left (\frac {1}{5}+\frac {3 i}{5}\right ) 2^{1-i} c^2 (1-i a x)^{3+i} \operatorname {Hypergeometric2F1}\left (-2+i,3+i,4+i,\frac {1}{2} (1-i a x)\right )}{a} \]

[In]

Integrate[E^(2*ArcTan[a*x])*(c + a^2*c*x^2)^2,x]

[Out]

((1/5 + (3*I)/5)*2^(1 - I)*c^2*(1 - I*a*x)^(3 + I)*Hypergeometric2F1[-2 + I, 3 + I, 4 + I, (1 - I*a*x)/2])/a

Maple [F]

\[\int {\mathrm e}^{2 \arctan \left (a x \right )} \left (a^{2} c \,x^{2}+c \right )^{2}d x\]

[In]

int(exp(2*arctan(a*x))*(a^2*c*x^2+c)^2,x)

[Out]

int(exp(2*arctan(a*x))*(a^2*c*x^2+c)^2,x)

Fricas [F]

\[ \int e^{2 \arctan (a x)} \left (c+a^2 c x^2\right )^2 \, dx=\int { {\left (a^{2} c x^{2} + c\right )}^{2} e^{\left (2 \, \arctan \left (a x\right )\right )} \,d x } \]

[In]

integrate(exp(2*arctan(a*x))*(a^2*c*x^2+c)^2,x, algorithm="fricas")

[Out]

integral((a^4*c^2*x^4 + 2*a^2*c^2*x^2 + c^2)*e^(2*arctan(a*x)), x)

Sympy [F]

\[ \int e^{2 \arctan (a x)} \left (c+a^2 c x^2\right )^2 \, dx=c^{2} \left (\int 2 a^{2} x^{2} e^{2 \operatorname {atan}{\left (a x \right )}}\, dx + \int a^{4} x^{4} e^{2 \operatorname {atan}{\left (a x \right )}}\, dx + \int e^{2 \operatorname {atan}{\left (a x \right )}}\, dx\right ) \]

[In]

integrate(exp(2*atan(a*x))*(a**2*c*x**2+c)**2,x)

[Out]

c**2*(Integral(2*a**2*x**2*exp(2*atan(a*x)), x) + Integral(a**4*x**4*exp(2*atan(a*x)), x) + Integral(exp(2*ata
n(a*x)), x))

Maxima [F]

\[ \int e^{2 \arctan (a x)} \left (c+a^2 c x^2\right )^2 \, dx=\int { {\left (a^{2} c x^{2} + c\right )}^{2} e^{\left (2 \, \arctan \left (a x\right )\right )} \,d x } \]

[In]

integrate(exp(2*arctan(a*x))*(a^2*c*x^2+c)^2,x, algorithm="maxima")

[Out]

integrate((a^2*c*x^2 + c)^2*e^(2*arctan(a*x)), x)

Giac [F]

\[ \int e^{2 \arctan (a x)} \left (c+a^2 c x^2\right )^2 \, dx=\int { {\left (a^{2} c x^{2} + c\right )}^{2} e^{\left (2 \, \arctan \left (a x\right )\right )} \,d x } \]

[In]

integrate(exp(2*arctan(a*x))*(a^2*c*x^2+c)^2,x, algorithm="giac")

[Out]

sage0*x

Mupad [F(-1)]

Timed out. \[ \int e^{2 \arctan (a x)} \left (c+a^2 c x^2\right )^2 \, dx=\int {\mathrm {e}}^{2\,\mathrm {atan}\left (a\,x\right )}\,{\left (c\,a^2\,x^2+c\right )}^2 \,d x \]

[In]

int(exp(2*atan(a*x))*(c + a^2*c*x^2)^2,x)

[Out]

int(exp(2*atan(a*x))*(c + a^2*c*x^2)^2, x)