Integrand size = 24, antiderivative size = 41 \[ \int \frac {e^{-2 i \arctan (a x)}}{\sqrt {1+a^2 x^2}} \, dx=\frac {2 i \sqrt {1-i a x}}{a \sqrt {1+i a x}}-\frac {\text {arcsinh}(a x)}{a} \]
[Out]
Time = 0.03 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {5181, 49, 41, 221} \[ \int \frac {e^{-2 i \arctan (a x)}}{\sqrt {1+a^2 x^2}} \, dx=-\frac {\text {arcsinh}(a x)}{a}+\frac {2 i \sqrt {1-i a x}}{a \sqrt {1+i a x}} \]
[In]
[Out]
Rule 41
Rule 49
Rule 221
Rule 5181
Rubi steps \begin{align*} \text {integral}& = \int \frac {\sqrt {1-i a x}}{(1+i a x)^{3/2}} \, dx \\ & = \frac {2 i \sqrt {1-i a x}}{a \sqrt {1+i a x}}-\int \frac {1}{\sqrt {1-i a x} \sqrt {1+i a x}} \, dx \\ & = \frac {2 i \sqrt {1-i a x}}{a \sqrt {1+i a x}}-\int \frac {1}{\sqrt {1+a^2 x^2}} \, dx \\ & = \frac {2 i \sqrt {1-i a x}}{a \sqrt {1+i a x}}-\frac {\text {arcsinh}(a x)}{a} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.37 \[ \int \frac {e^{-2 i \arctan (a x)}}{\sqrt {1+a^2 x^2}} \, dx=\frac {2 \left (\sqrt {1+a^2 x^2}+(-1-i a x) \arcsin \left (\frac {\sqrt {1-i a x}}{\sqrt {2}}\right )\right )}{a (-i+a x)} \]
[In]
[Out]
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 148 vs. \(2 (34 ) = 68\).
Time = 0.27 (sec) , antiderivative size = 149, normalized size of antiderivative = 3.63
method | result | size |
default | \(-\frac {\frac {i \left (\left (x -\frac {i}{a}\right )^{2} a^{2}+2 i a \left (x -\frac {i}{a}\right )\right )^{\frac {3}{2}}}{a \left (x -\frac {i}{a}\right )^{2}}-i a \left (\sqrt {\left (x -\frac {i}{a}\right )^{2} a^{2}+2 i a \left (x -\frac {i}{a}\right )}+\frac {i a \ln \left (\frac {i a +\left (x -\frac {i}{a}\right ) a^{2}}{\sqrt {a^{2}}}+\sqrt {\left (x -\frac {i}{a}\right )^{2} a^{2}+2 i a \left (x -\frac {i}{a}\right )}\right )}{\sqrt {a^{2}}}\right )}{a^{2}}\) | \(149\) |
[In]
[Out]
none
Time = 0.27 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.32 \[ \int \frac {e^{-2 i \arctan (a x)}}{\sqrt {1+a^2 x^2}} \, dx=\frac {2 \, a x + {\left (a x - i\right )} \log \left (-a x + \sqrt {a^{2} x^{2} + 1}\right ) + 2 \, \sqrt {a^{2} x^{2} + 1} - 2 i}{a^{2} x - i \, a} \]
[In]
[Out]
\[ \int \frac {e^{-2 i \arctan (a x)}}{\sqrt {1+a^2 x^2}} \, dx=- \int \frac {\sqrt {a^{2} x^{2} + 1}}{a^{2} x^{2} - 2 i a x - 1}\, dx \]
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.80 \[ \int \frac {e^{-2 i \arctan (a x)}}{\sqrt {1+a^2 x^2}} \, dx=-\frac {\operatorname {arsinh}\left (a x\right )}{a} + \frac {2 i \, \sqrt {a^{2} x^{2} + 1}}{i \, a^{2} x + a} \]
[In]
[Out]
\[ \int \frac {e^{-2 i \arctan (a x)}}{\sqrt {1+a^2 x^2}} \, dx=\int { \frac {\sqrt {a^{2} x^{2} + 1}}{{\left (i \, a x + 1\right )}^{2}} \,d x } \]
[In]
[Out]
Time = 0.57 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.37 \[ \int \frac {e^{-2 i \arctan (a x)}}{\sqrt {1+a^2 x^2}} \, dx=-\frac {\mathrm {asinh}\left (x\,\sqrt {a^2}\right )}{\sqrt {a^2}}-\frac {2\,\sqrt {a^2\,x^2+1}}{\left (-x\,\sqrt {a^2}+\frac {\sqrt {a^2}\,1{}\mathrm {i}}{a}\right )\,\sqrt {a^2}} \]
[In]
[Out]